granola | Simple JSON serializers | JSON Processing library
kandi X-RAY | granola Summary
kandi X-RAY | granola Summary
Granola aims to provide a simple interface to generate JSON responses based on your application's domain models. It doesn't make assumptions about anything and gets out of your way. You just write plain ruby.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Create a new object .
- Generate the cache key
- Render a serializer .
- Gets the key
granola Key Features
granola Examples and Code Snippets
Lines of Code : 22License : Permissive (MIT)
Copyclass UserSerializer < Granola::Serializer
def data
{ "id" => object.id, "name" => object.name, "email" => object.email }
end
def last_modified
object.updated_at
end
def cache_key
"user:#{object.id}:#{object.update granola(person) #=> This will infer PersonSerializer from a Person instance
granola(person, with: AnotherSerializer)
require "granola/rack"
Cuba.plugin Granola::Rack
Cuba.define do
on get, "users/:id" do |id|
user = User[id]
halt gran class PersonSerializer < Granola::Serializer
def data
{
"name" => object.name,
"email" => object.email,
"age" => object.age
}
end
end
PersonSerializer.new(person).to_json #=> '{"name":"John Doe",...}'
Community Discussions
Trending Discussions on granola
QUESTION
I'm trying to create a code that will add milk to each list in a shopping cart (nested list). But if there is already milk in that list, milk should not be added to it.
...ANSWER
Answered 2021-Dec-23 at 17:23You don't need nested loops. You just need to loop over the main list, not the nested lists, so you can append to that list. You can use the in operator to test if a list contains something, you don't do that by looping (your loop will falsely say that the list doesn't contain milk when any of the elements are not milk).
Also, get in the habit of using for item in list: rather than for index in range(len(list)):
QUESTION
I'm trying to figure out a code that will go through all items of the list, and keep a count of how many times the given item occurs, without the count funtion!
This is my code:
...ANSWER
Answered 2021-Dec-22 at 22:35You can do something like this if you don't want to use any built-in method:
QUESTION
I have this mongoose schema,
...ANSWER
Answered 2021-May-28 at 12:17It is returned correctly. saleSizes is the array of Objects. {saleSize: "P", price: "100"} is Object. You can try to access those nested objects like this:
QUESTION
I'm trying to implement a search filter in reactjs, I've tried bind method to `onChange´ event but it triggered for every single letter. How can it make it work to after type 3 letters.
...ANSWER
Answered 2020-Dec-21 at 06:39As the function which is pass to the onChange property of an input field is called any time you type on the keyboard. You can check inside of that function before performing any change which you need as updating the state If the value of event.target.value length is greather or equal to 3 like this
QUESTION
I am trying to use stroi in my "vending machine" code below. I had a working vending machine before I tried to add a feature that allows users to enter characters ("c" for checkout, "a" for add, and "r" for remove) as well. Since my user input can be both int and char I realized I had to convert strings to numbers. I have checked references but none give an example of how to use it with vectors. Can someone please help?
Currently, there is an error located at the int myint1 = stoi(item); line in the if statement in the main. It says "use of undeclared identifier 'i'."
Note: I am fixing my code so it does not run. But when it did, the code breaks after 2 user inputs and I am not sure why.
Here is an example of what I am trying to code:
Vending machine:
----Items----
(5 listed below)
what item would you like to buy? Enter "c" to checkout, "a" for add item and "r" for remove item.
-If user input is an integer, then run the enterSelection function
-If user input is a character (c, a, or r) , then:
if "c" , then run checkout function
if "a", What Item would you like to add and for what price? Then append to menuItems and cost accordingly.
if "r", what item would you like to remove (enter a number)? Then erase the item from menuItems.
Then print: "User input" has been added/removed from the menu.
When the menu is displayed again, the user edit will show.
And yes, I know there are many more problems with my code that I do not know how to fix.
Full Code:
...ANSWER
Answered 2020-Aug-13 at 23:24To answer your question, you can.
However you are not doing correctly, regardless, you wouldn't need all those conversions, you could compare item directly with a char or int deppending on the type of input you ask for.
We can also continue with std::stoi to convert the input to its int value, you must, however, guard for the aphabetic inputs, these will not be converted, of course, and error derived from this failed conversions should be prevented.
Semi-corrected code with comments:
QUESTION
I admit this might be a simple question but I cannot seem to map my head around it. Say that I have a .txt file that I'm reading with a BufferedReader in Java that might look like this:
...ANSWER
Answered 2020-Aug-12 at 15:42This can inspire (before anyone closes it ): The structure you want to build is a map (key-value structure) not a list.
QUESTION
I am working on the "checkout" process of my vending machine code. I want to write it so that the program will keep asking for the amount needed from the user until all the money is entered. However, this code segment does not completely work.
"Checkout" Segment of Code:
...ANSWER
Answered 2020-Aug-07 at 19:21In this loop:
QUESTION
I am progressing on my "vending machine" code where users are able to add an unlimited amount of items to the cart until they press 0 to checkout. I ran into a problem with the array cost[item] in my "do-while" loop where it says "subscripted value is not an array, pointer, or vector." Could someone please help me with this?
I also have a few smaller problems if someone would like to help. Here are my main problems I ran into:
the press 0 to checkout part of the code - I think this problem is related to the
cost[item]array problem I described above.how to get my menu prices to display 2 digit decimals - I am not sure where to put
cout << fixed << setprecision(2) << total;in my code if that is the correct way of doing it.how to print a statement when "checking out" to display items with total cost.
my full code:
...ANSWER
Answered 2020-Aug-06 at 02:33I will try to help you sort out where you did mistakes:
- About cost[item]:
Maybe you already hear about "scope". It's about location of your variables, pointers, etc. In your program you declared
float cost[5] = {2, 3, 2.50, 1.50, 1};in global scope. This scope is where you declare something outside the main function. This scope works in wherever in this file. But you also declaredfloat cost;with the same name in local scope. Local scope works only where you declared this and deeper (in loops of this function, if-statements etc.); Compiler priority is for local variables(notice that compiler allows you to write same name of variables but with different scopes). I have correct your misstakes and add comments for all moments:
QUESTION
I am writing a "vending machine" program and I need to have 5 items where 3 items cost an integer amount and the other 2 cost a decimal amount.
I am only using if statements in this code, but there is an error with my cost variable.
What did I do wrong?
Code below:
...ANSWER
Answered 2020-Jul-27 at 19:43When I try to compile your code, I get the following error message:
Error: ‘cost’ was not declared in this scope
In order to fix this error, you just need to declare cost variable in the function's main block scope, for example like this:
QUESTION
The below code demonstrates the problem I'm trying to solve. Basically I only want to select transactions where a customer has never purchased a product where isActive is now 0.
I tried using GROUP BY and HAVING MIN(p.isActive) = 1 to get only the customers associated with active products. This query is close but MIN does not like bit type. How can I do this?
The goal is to only see transactions associated with just Lisa and Fred. Bill should be removed from the results since one of his transactions is currently associated with a InActive product.
...ANSWER
Answered 2020-Jul-21 at 19:21You can always convert to a number:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install granola
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
