bitfields | n Booleans 1 Integer , saves columns and migrations | Data Migration library
kandi X-RAY | bitfields Summary
kandi X-RAY | bitfields Summary
n Booleans = 1 Integer, saves columns and migrations.
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Top functions reviewed by kandi - BETA
- Adds multiple fields to the setter method .
- Generate one or more or more fields .
- Sets the specified bitfield value .
- Based on the set of fields
- Converts a set of bit fields to a bitfield .
- Adds a bitfield to the bitfield
- Returns the bitfield .
- Saves the last value to the current state of this bitfield
- Store the fields of this bitfield .
- Returns a hash of the current state of the given bitfield .
bitfields Key Features
bitfields Examples and Code Snippets
Community Discussions
Trending Discussions on bitfields
QUESTION
I am trying to use static_assert for registers for a FPGA and defined the following unions of struct with bitfields and all variable. But whenever I try to compile static_assert won't compile and I get an error saying the variable doesn't name a type. If I try to forward declare, it doesn't solve the problem. I'm not sure what the right pattern is to get the static_assert to work. Any ideas of the correct way to write the following code?
so.h:
...ANSWER
Answered 2021-Apr-01 at 20:49Any ideas of the correct way to write the following code?
There is no correct way. It's not possible to use static_assert
to check if bitfields are in specific places.
You are using C++. Do not use an union. Write a normal class with accessors that access specific bits with masks - such way is clear, portable and guaranteed to work. Alternatively use a std::bitset
.
QUESTION
I have two functions, both are similar to this:
...ANSWER
Answered 2021-Jun-01 at 18:57I question the following assumption:
This didn't work. It is clear that the compiler is optimising-out much of the code related to z completely! The code then fails to function properly (running far too fast), and the size of the compiled binary drops to about 50% or so.
Looking at https://gcc.godbolt.org/z/sKdz3h8oP, it seems like the loops are actually being performed, however, for whatever reason each z++
, when using a global volatile z
goes from:
QUESTION
I have separated the code into files (*.c and *.h) and included them. I have guard headers and all the separated files were reported to being build:
...ANSWER
Answered 2021-May-30 at 07:57Sketch.cpp is compiled as as C++, including test.h. In order to support function overloading, class membership etc, C++ uses name mangling to encode these C++ features in the symbol name. As such the symbol name for some_test
in Sketch.cpp is not the same as that in test.c which is compiled as C and no name mabgling is applied..
The solution is to prevent name mangling for this symbol when the header is C++ compiled by specifying that the symbol has C linkage:
QUESTION
I have a 16-bit number, the LSB 4 bits are used as bitfields to check settings, and the MSB 12 bits are used as a number
that is incremented.
I know that tempNum = (data_bits >> 4)
will get me the number
out of the larger one. If I want to increment that tempNum
by 1 and then put that back into the overall 16-bit number as a replacement without affecting the lower 4 bits, how would I go about doing this? I want to do this using bitwise
operations only.
ANSWER
Answered 2021-Apr-04 at 01:58The simplest way to do this would be to increment starting after 4 bits, i.e.:
QUESTION
I am working with a DSL (Chisel) in which one particular part of the library requires me to define a Seq
of items. I have several companion objects to create some intermediate logic and return one of these items. I have a situation where I want to actually return two of these items, but I'm having a hard time figuring out how to do that.
Let's say the "items" here are Person
. (What Person
is here is not important)
The DSL wants you to describe all your Person
s through a Seq
.
ANSWER
Answered 2021-Mar-10 at 00:56Return a Seq
and concatenate?
QUESTION
I have a file from which I would like to retrieve the header, the header is in network order (big endian) and I would like to store it in this structure:
...ANSWER
Answered 2021-Feb-25 at 15:13the header is in network order (big endian)
QUESTION
there is a class declared as:
...ANSWER
Answered 2020-Dec-05 at 20:32sizeof(Payload)*CHAR_BIT
. This gets the size of the structure in bytes and multiplies it by the number of bits per byte (it’s technically not always 8). This works because bitfield-containing structs cannot have a size in bits which is not a multiple of CHAR_BIT
. The compiler will add padding bits after the last member.
QUESTION
For the TLE985x Infineon uses bitfields to map the registers in their library. Since I'm am kind of new to embedded programming, I read about bitfields. Many of the articles mentiond bad effects of bitfield. Now the question is, when bitfields are somehow bad, why is Infineon using it in their library?
Thank you for your help
...ANSWER
Answered 2020-Oct-30 at 09:16Whether to use the default register maps from the vendor or roll out your own is pretty much project-specific. If you have high requirements of portability and general source code quality, you have to make your own register map.
Some discussion on that topic can be found here: How to access a hardware register from firmware? As discussed in that post, the vendor has several reasons for rolling out their own custom, crappy register maps:
- Makes debugging register maps easier, particularly when using a crappy debugger with no specific part support (such as the various Eclipse-flavoured ones). High quality debuggers like Lauterbach, iSystem, Crossworks etc do have part support and you can watch registers just fine in them, no matter how those registers were declared in C source.
- Silicon vendors have absolutely no reason to make it easier for you to port away from their silicon to some other. Quite the contrary. Register maps are of course quite non-portable to begin with. But similarly, tool vendors don't want you to port to another compiler for the same silicon.
- Silicon vendors are notoriously incompetent when it comes to writing firmware. This has been the case for as long as everyone can remember. I wouldn't point at any particular vendor here, they are all hopelessly bad at this.
What you could do however, in case of Infineon specifically, is to ask: "Hey guys, you seem to like automotive electronics a lot. The automotive industry has been using MISRA-C since 1998. How come you still don't provide MISRA-C compliant libraries in the year 2020? You don't want automotive customers to use your products?" Lots of amusing mumbling responses to be had.
QUESTION
I'm a trying to migrate some legacy C code for Embedded targets to C++ for compatibility issues and I am encountering some issues with unions in C++.
in our project we have the following style of union to reduce the amount of RAM usage:
...ANSWER
Answered 2020-Oct-08 at 13:16In C++ you need an extra set of braces to reflect that the initializers are in a sub-struct:
QUESTION
Let's take the following assembly instruction:
...ANSWER
Answered 2020-Oct-08 at 04:52Yes, looks right.
The general pattern (for "legacy" ALU instructions that date back to 8086) for encoding op r/m, r
vs. op r, r/m
, and 8-bit vs. 16/32 bit does use the low 2 bits of the opcode byte in a regular pattern, but there's no need to rely on that.
Intel does fully document exactly what's going on for each encoding of each instruction in their vol.2 manual. See the Op/En column and Operand Encoding table for add
for example. (See also https://ref.x86asm.net/coder64.htm which also specifies which operand is which for every opcode). These both let you know which opcodes take a ModRM byte and which don't.
These of course use Intel-syntax order. You're making your life more complicated by trying to follow manuals and tutorials while using AT&T syntax which reverses the order of the operand-list vs. Intel and AMD manuals.
e.g. 00 /r
is listed as MR
operand encoding, which from the table we can see is operand 1 = ModRM:r/m (r, w)
, so it's read and written, and encoded by the r/m
field. operand 2 = ModRM:reg (r)
, so it's a read-only source encoded by the reg
field.
Fun fact: 00 00
is add [rax], al
, or AT&T add %al, (%rax)
Note that you can ask GAS to pick the either encoding: x86 XOR opcode differences
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