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Community Discussions
Trending Discussions on sushi
QUESTION
I have two arrays that I would like to compare against each other based on the Username
and create a new array that includes EmployeeName
ANSWER
Answered 2021-Jun-06 at 00:20QUESTION
I have the following string:
...ANSWER
Answered 2021-Jun-03 at 19:49Try this:
QUESTION
The object within an object contains variables such as "name", "amount", "amountType", and "cal". The strings on those variables should be transferred through loop as several row in the given HTML table. Each variable should be on its own cell.
I already made one row and made 4 cell for the name, amount, amount type, and calorie columns. Then, I tried to transfer the objects elements inside the cell using the index of the object.
...ANSWER
Answered 2021-May-31 at 07:11You're treating the mealObj
as an array
while it's an object
and also you're not looping, so your code only runs once.
Below you can find a code that works for the first Menu (Steak). You might need to account for multiple meals by creating multiple tables.
QUESTION
On the function "createIngrList", it should take all the ingredient names, such as "Butter", "Beef", "Onion", etc., and turn it into buttons. So each button should have a text with the name of an ingredient written on it. As of now, there is just 4 buttons with "undefined" written on it. If possible, all the repeating ingredients such as "Onion" should not be made into button twice. Once is enough.
...ANSWER
Answered 2021-May-31 at 00:33I think this may be what you are looking for... Though you mention not parsing ingredients that are listed twice, though each food, only has an ingredient listed in your object once. Correct me if I am wrong I will refine answer.
You can use for/in loops to get the nested ingredients and their foods. Then use the obj.name
to get the name. Through the first for/in loop the key -> i
will be the name of the food, then use the second key along witht he first to get the actual .name
=> obj[i][k].name
this will give you the ingredient name.
I also created a couple of divs to palce the food and its buttons wrapped in divs for styling, etc...
You can use conditionals to filter by food if you want to only show a certain type of foods ingredients as buttons.
NOTE: your obj key for the first value is uppercase, this will cause issues when parsing obj[index][key].name
, likely that is just a typo...
QUESTION
I am working on a project in which I need to post a new Course to my API. I tested this with POSTMAN and API works just fine, however when I try to post data using react fetch data is corrupted. While sending single strings like dishName: "pizza" works just fine and is shown in database I cannot manage to send an array of objects. I tried to do it in many ways like:
...ANSWER
Answered 2021-May-27 at 21:44You are setting the ingredients
state as a string, so you are basically 'stringify' a string which will result in JSON SyntaxError
. If you want to send an array that way you must specify the array bracket [
and ]
in order to make it a valid array.
To solve it just change:
QUESTION
I have an SQL-Table which is build like a tree list (parent child). Means you have rootId's and childId's. Each entity has a ParentId. If the ParentId is null then that element is a root item.
Here an example of the hierarchical architecture
...ANSWER
Answered 2021-May-21 at 20:26If you don't interest to load all records from database then process them, you have two choices :
Solution 1 : Write a StoreProcedure and processing in database.
Solution 2 : Write a recursive function that send multiple requests to database (In the amount of root depth)
Here is a function for solution 2 :
QUESTION
The HTML create two drop-down menu and one delete button. One JavaScript, I made a code to fill those drop-down box with arrays. And, every time I change the item on the first drop-down menu, a new set of options appears on the second drop-down menu. The goal is, whenever I clicked the delete button, I should be able to delete an item on the second drop-down and when I changed the item on the first drop-down menu, hence another set of option will appear on the second drop-down menu, I should be able to delete an item from there as well.
The problem is, once the set of items on the second drop-down menu has been changed, a bunch of unwanted results occurs, such as deleting more than one items or deleting on another set of items. For example, if I delete something from "meal", it'll delete one item. Then if I go over to "dessert" and delete something from there, it'll delete one item. But if I go back to "meal" again, a bunch of items are now deleted. Just try it out yourself to see what I mean
...ANSWER
Answered 2021-May-19 at 13:28What were you doing wrong?
In practice your code stored in the variable menuOption
the first menu, doing so every time you tried to delete something it was removed from the first menu
Solution
- Call up the menu variable as often as needed
- Store index before remove it
- Extra:
- Use
menuList.selectedIndex
instead ofdrinkListArr.indexOf(subMenuOption)
- Use
menuType.value
instead ofmenuType.options[menuType.selectedIndex].text
- Use
QUESTION
Hi guys I have two tables dbo.Sales (customer_id, order_date, product_id) and dbo.Menu (Product_id, product_name, price). The question is What was the first item from the menu purchased by each customer?
My solution is
...ANSWER
Answered 2021-May-18 at 11:39You could use a ROW_NUMBER()
window function to get the earliest product_id
per customer and then join to the Menu
table to get your product details.
Edit: Updated ORDER
to ASC
.
QUESTION
I am working with the R programming language. In a previous post (R: converting tidyverse to dplyr/reshape2 for plots), I learned how to make automatic histograms for all categorical variables in my dataset:
...ANSWER
Answered 2021-Apr-29 at 18:33With reshape2::melt
, specify the id columns in id.vars
i.e. deselect_not_factors
, and the corresponding arguments for names_to
and values_to
are variable.name
and value.name
QUESTION
I am using the R programming language. I created the following data set for this example:
...ANSWER
Answered 2021-Apr-29 at 04:30A ggplot2
/tidyverse
solution is to lengthen each column into data and then use faceting to plot them all in the same page:
(with edit to plot only factor variables)
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On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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