cream | Integrates Devise , Roles and CanCan with Permits | Application Framework library

You are simply using wrong locator.
Try this

your code as some naming error. you don't have to use findall every time like name is only one time . action is not define but you are still appending it , this code generate your desire output of df

Instead of a custom made UDF, try to utilize what Excel does offer through build-in functionality, for examle FILTERXML():

Formula used in B1:

First, your TrieNode is using a List, which means you have to do a for-loop O(N) search for each char. It would be faster to use a Map.

(You could also use a 26D array, instead of a map, if you know that you'll only have English letters: [0] = 'A', [1] = 'B', ... [25] = 'Z')

Now I need to search using prefix so if the user searches for bur it'll show Burger. But if someone write Garlic Butter I need to Garlic Parmesan Butter. So, basically if the search query has multiple words I need to show the correct name.

bur is easy to do, as that's what a Trie data structure is for, but the garlic butter one is harder. You probably want to look into how to implement a fuzzy search or "did you mean...?" type algorithm:

• Fuzzy search algorithm (approximate string matching algorithm)

However, maybe this is more complex than you want.

Here are some alternatives I thought of:

Change your TrieNode to store a String variable stating the "standard" word. So the final TrieNode of garlic parmesan butter and garlic butter would both have an instance variable that stores garlic butter (the main standard/common word you want to use).

Your TrieNode would be like this:

Try below:

I have reproduced your code and for me the test does not work with toBeInTheDocument, but works with toBeVisible as long as display: none is there.

Here is the code of my test file, the first test does not pass, the second passes:

You're treating the mealObj as an array while it's an object and also you're not looping, so your code only runs once.

Below you can find a code that works for the first Menu (Steak). You might need to account for multiple meals by creating multiple tables.

I think this may be what you are looking for... Though you mention not parsing ingredients that are listed twice, though each food, only has an ingredient listed in your object once. Correct me if I am wrong I will refine answer.

You can use for/in loops to get the nested ingredients and their foods. Then use the obj.name to get the name. Through the first for/in loop the key -> i will be the name of the food, then use the second key along witht he first to get the actual .name => obj[i][k].name this will give you the ingredient name.

I also created a couple of divs to palce the food and its buttons wrapped in divs for styling, etc...

You can use conditionals to filter by food if you want to only show a certain type of foods ingredients as buttons.

NOTE: your obj key for the first value is uppercase, this will cause issues when parsing obj[index][key].name, likely that is just a typo...

You are rewriting the s variable each iteration, that's why it only shows the result for the last column. Try