liaison | The unobtrusive presenter pattern for Rails | Application Framework library
kandi X-RAY | liaison Summary
kandi X-RAY | liaison Summary
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Community Discussions
Trending Discussions on liaison
QUESTION
I'm working on a react native app from a windows 10 computer. I installed WSL, set up my backend needs on it, and I can see my api responding on localhost from windows, no problem on that end.
Now I would like to call it from my mobile app - both from an android emulator using Android Studio and from my physical android device (using Expo) connected to the same local network over wifi.
Using Ngrok it could work, exposing my localhost to a public url, but that's not what I'm looking for. I want it all to remain local if possible. My pc's local ipv4 is 10.0.0.8
, but nothing comes out on that address (not from the mobile app neither from my desktop browser, which works when using localhost
).
My Ubuntu inside WSL says:
...ANSWER
Answered 2021-Apr-20 at 18:17So I found a solution thanks to https://superuser.com/a/1618446/757755 I successfully used option 2 and used port forwarding, with the script found here. Remember that your PowerShell script has to be ran as administrator.
QUESTION
ANSWER
Answered 2021-Feb-04 at 15:28Order Lines (order_line
) field uses already the order_id
field (inverse name) to link sale order line to the sale order, so you can use that field to get field values from sale order.
You can define client_order_ref
as related to provide the value of a sub-field (client_order_ref
) on the current record (sale orde line):
QUESTION
I have an array that looks like this
...ANSWER
Answered 2020-Oct-08 at 18:33You could take an iterative and recursive approach and return a flat array by using Array#flatMap
.
This approach takes only entity
objects.
QUESTION
I have a dataset df_tidy
with 3 columns vocation
, job_title
, and n
.
ANSWER
Answered 2020-Oct-02 at 16:51The only way I can get this to work is if I aggregate the data to one row per vocation concatenating the names. I've used data.table
, but hopefully gives you the gist.
I followed the last couple of R examples in here for the formatting https://plotly.com/r/hover-text-and-formatting/
and added the part to the tooltip as it was returning an additional
trace 0
as answered here: How to remove trace0 here?
You can replace your base plot_ly
command with this and the layout
addition works fine with it.
QUESTION
I need to select a value of a td based on another td's text in the same row. The XPath should be the same and only text will be changeable. In the following HTML, I have to select $33.00
based on Labor
, $0.66
based on Finance
, $33.66
based on Total
, and so on.
ANSWER
Answered 2020-Sep-10 at 12:38Try this one to get required output:
QUESTION
Y'all, I'm trying to alleviate some of my work in migrating from a face-to-face teaching environment to one that is remote for at least the next three months. To this end, I am trying to create randomized lists of eligible vocabulary words for quizzes. I can have it generate up to eighteen sets of words for an identical number of quizzes, but I seem to be fumbling with checking whether the randomly selected word is already part of that quiz, i.e. I am getting a ton of repeats. Since one word is taught per day, this means the first biweekly quiz will have ten eligible words; the second, twenty words; the third, thirty words; etc. Please see the code below, and thank you in advance for your help!
...ANSWER
Answered 2020-Aug-21 at 01:31You probably want to try using random.sample(all_words, 10)
and loop over to extend the output for subsequent weeks (changing 10 to the desired number of words). You will need to import random
first.
QUESTION
I am new to the XSLT 1.0, where i have the below XML which we are passing into XSLT to generate the PDF.
XML:
...ANSWER
Answered 2020-Feb-24 at 07:08In XSLT 2.0 you can use for-each-group
QUESTION
I have three entities : Trophy | Competition | Season
One Competition is created for one trophy for one season (you can't have two competitions with same combination "season + trophy").
Competition as a ManyToOne relation with Trophy, and a ManyToOne relation with Season.
Trophy and Season have no direct relation.
I want to display two dropdowns on a page with the content of the second one being dependent from the value of the first : First dropdown allow to select a trophy type (which is a property of Trophy entity), second dropdown must list seasons that are "still available" for trophy type selected (meaning by that "list all seasons for which there are no competition for this trophy type")
I've got almost all working (listener in the Formtype, ajax etc) I've created a specific function allWithoutThisCompetitionType() in SeasonRepository. Function is correctly called every-time user select a new value in dropdown BUT... I don't know anything about SQL nor dql, so I'm struggling to find the correct formulation for my query. I've tried with notin(), with "sub" or "nested" queries... I definitely don't know what I'm doing...
How can I do something like ? :
...ANSWER
Answered 2019-Nov-04 at 18:54Here is the query, though, I'm not 100% sure it will match your need.
Let me know in comment if something is wrong, I will edit my answer.
QUESTION
I need some clue on how to import correctly a function from a custom module in perl. (here person_init from the PersonInit module).
This is my folder representation :
...ANSWER
Answered 2019-Sep-19 at 13:07For best results, the package names you use should match the package names you supply to the use
directive. Use
QUESTION
Hi i need to have a manager for my user table. I have now created an intermediate table called liaison which will contain manager_id and references user_id table. The problem is that i don't know how to add the association between them and i need to list the users as manager in my activeadmin panel also during user creation.
I have tried this association in user.rb
...ANSWER
Answered 2019-Aug-15 at 13:03The liaisons model only references a single user/manager and needs to know to map managers back to the users table:
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Install liaison
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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