desperado | league framework for Android : Netrunner | Chat library

by muyjohno Ruby Version: v1.0.6 License: No License

X-Ray Key Features Code Snippets Community Discussions(5)Vulnerabilities Install Support

kandi X-RAY | desperado Summary

desperado is a Ruby library typically used in Messaging, Chat, Framework applications. desperado has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Desperado is a framework for league software for Android: Netrunner using Ruby on Rails.

Support

Quality

Security

License

Reuse

Support

desperado has a low active ecosystem.

It has 2 star(s) with 0 fork(s). There are no watchers for this library.

It had no major release in the last 12 months.

There are 0 open issues and 2 have been closed. On average issues are closed in 3 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of desperado is v1.0.6

Quality

desperado has 0 bugs and 0 code smells.

Security

desperado has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

desperado code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

desperado does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

desperado releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

It has 3837 lines of code, 181 functions and 143 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of desperado

Get all kandi verified functions for this library.

desperado Key Features

No Key Features are available at this moment for desperado.

desperado Examples and Code Snippets

No Code Snippets are available at this moment for desperado.

Community Discussions

Trending Discussions on desperado

How to update a specific value in state object using hooks?

Mongodb query to Display the number of movies based on the number of directors a movie has using split

How do I query for all rows but limit by max values of two columns when 3rd column is of a specific value in one single query?

Remove emojis and @users from a list in Python and punctuation, NLP problem, and my emoji function does not work

Is it possible to use D3.tree() with a dataset that includes parents instead of children?

QUESTION

How to update a specific value in state object using hooks?

Asked 2021-May-02 at 16:09

I'm trying to update the quantity of an item in a shopping basket, however struggling to get it working?

I have an input field that lets the user update the quantity, the quantity is used to update the total price of items based on the number, as well as also the total basket cost.

I have managed to get the correct item in the array of objects that make up the basket, however i can't seem to be able to update the quantity using the state hook, how would i be able to do this?

My idea is to update it in the if statement, then replace the old object with the new object with the updated quantity... but my knowledge on how to do this is non existent...

this is what i have so far....

...

ANSWER

Answered 2021-May-02 at 13:30

Do you use the quantityHandler onClick? Something like this:

Source https://stackoverflow.com/questions/67356632

QUESTION

Mongodb query to Display the number of movies based on the number of directors a movie has using split

Asked 2021-Apr-28 at 11:45

I have a movieDetails.json database and the collection name is a movie then our teacher wants us to Display the number of movies based on the number of directors a movie has a. Hint you might have to use the javascript function split Since the director is not an array, it is only a string so I can't count how many directors are there because it will always come out as 1 since its a string so I want to split that string so that I can get an array so that I can count it. But unfortunately, I don't know the query that will solve this problem. ex. of expected output:

...

ANSWER

Answered 2021-Apr-28 at 11:45

Demo - https://mongoplayground.net/p/y3kvFnocWKn

Use aggregation query

Read the below links for better understanding

Source https://stackoverflow.com/questions/67298166

QUESTION

How do I query for all rows but limit by max values of two columns when 3rd column is of a specific value in one single query?

Asked 2020-Oct-21 at 15:38

ID     Type     MovieYear      MovieName    BookName       BookGenre     SongName     SongYear     SongMonth
-------------------------------------------------------------------------------------------------------------
1      Book     null           null         The Hobbit     Fantasy       null          null        null
2      Movie    2019           It           null           null          null          null        null   
3      Song     null           null         null           null          Desperado     2019        11
4      Song     null           null         null           null          Desperado     2019        7
5      Song     null           null         null           null          Away          2000        6
6      Song     null           null         null           null          Away          1988        10

...

ANSWER

Answered 2020-Oct-21 at 15:38

Hmm . . . I think row_number() does this:

Source https://stackoverflow.com/questions/64467017

QUESTION

Remove emojis and @users from a list in Python and punctuation, NLP problem, and my emoji function does not work

Asked 2020-Jun-26 at 07:49

I wrote the code below. My sentence is part of Twitter. I want to remove all emojis from my list, but my emoji function does not work. Why?

And also I want to remove users. Users start from the beginning of a sentence, but sometimes it keeps users and sometimes it removes users. Also my punctuation does not work and I commented it. How can I fix that?

...

ANSWER

Answered 2020-Jun-01 at 23:06

I'm drawing on some other SO answers here:

removing textual emojis: https://stackoverflow.com/a/61758471/42346
removing graphical emojis: https://stackoverflow.com/a/50602709/42346

This will also remove any Twitter username wherever it appears in the string.

Source https://stackoverflow.com/questions/62141647

QUESTION

Is it possible to use D3.tree() with a dataset that includes parents instead of children?

Asked 2020-May-02 at 01:38

I'm in the process of creating a family-tree using D3. My dataset is indeed hierarchical, but the root node of the tree is the child. Each "child node" contains two "parent" nodes that represents each childs two parents. Here is an example of my data.

...

ANSWER

Answered 2020-May-02 at 01:38

You don't need to alter your original dataset, instead when you create the root using d3.hierarchy you can specify which property contains the "children":

Source https://stackoverflow.com/questions/61548914

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install desperado

You can download it from GitHub.
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: