neoid | Extend Ruby on Rails ActiveRecord | Database library
kandi X-RAY | neoid Summary
kandi X-RAY | neoid Summary
Make your ActiveRecords stored and searchable on Neo4j graph database, in order to make fast graph queries that MySQL would crawl while doing them. Originally by @elado. Neoid is to Neo4j as Sunspot is to Solr. You get the benefits of Neo4j's speed while keeping your schema on your RDBMS. Neoid does not require JRuby. It's based on the Neography gem which uses Neo4j's REST API. Neoid offers querying Neo4j for IDs of objects and then fetch them from your RDBMS, or storing all desired data on Neo4j.
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Top functions reviewed by kandi - BETA
- Flush the results to the database .
- Run the command .
- Creates a new command .
- Convert result into a hash
- Returns an array of models from the model
- Runs the application .
- Perform search request
- Execute the result
- Get the result of the result
- Set the result of this block .
neoid Key Features
neoid Examples and Code Snippets
Community Discussions
Trending Discussions on neoid
QUESTION
I'm working with an oracle database but I don't have much experience with it, in case I need to make a 'backup' of a table column I was wanting to use CONCAT on the sql server but it works on Oracle, no, it gives the error ORA-00909. the query I'm using is:
...ANSWER
Answered 2020-Jul-03 at 19:15Use the ||
operator:
QUESTION
I have this somewhat huge query which is returning the correct result when I run it on SQL Server Management Studio:
...ANSWER
Answered 2018-Jul-30 at 13:25This is because you don't have column names for the last 3 columns. Provide a column alias for each of those three columns and this should work.
BTW, you might consider using UNION ALL unless you are trying to return only distinct rows.
QUESTION
So I imagine there's some documentation somewhere that discusses this, but I haven't found it. (I don't expect an answer to have benchmarks, just ~"in general, this is what happens")
It is my understanding that each label indexes its member's neoID
, so adding a label to a node, and querying on that label, yields a performance benefit. But how does the performance compare if you have 10 labels on a node (vs 1 label)? What about 100 labels? Or 1000 labels? I imagine that adding more labels to a node comes with some sort of penalty? (other than the additional space the index takes up)
Say I have a db with :Book
, :Person
, :Organization
, and :CommunityGroup
nodes. Each has a uuid
property.
(:Book)-[:OWNER]->(:Person)
(:Book)-[:OWNER]->(:Organization)
:Person
or :Organization
nodes might own a :Book
, but :CommunityGroup
nodes never do. If a client passed my app an uuid
for a book owner, I could find that node a few different ways
- Match the node with that
uuid
which had either the:Person
or:Organization
labels.MATCH (:Book)-[:OWNER]->(n {uuid: $the_id}) WHERE n:Person OR n:Organization
- Ask the client for the node type, and match using that
uuid
and type.MATCH (:Person {uuid: $the_id})
- Add an
:Owner
label to the:Person
and:Organization
nodesMATCH (:Owner {uuid: $the_uuid})
Option 2 must be the fastest. 3 is the overall nicest to query on. 1 minimizes extra labels + client work.
Obviously this example is small, but what if I created extra labels (like the :Owner
label) all over the place. Is there a performance penalty for that? I could easily see a single node acquiring 10 or 20 labels, maybe more, depending on how liberal I was in applying them. The :Owner
label is technically unnecessary, as I have the labels needed to find the node already...
Thoughts? Thanks for any feedback!
Note: I found this S.O. question on multiple label performance, but it's only addressing a scenario with a few labels (~4), rather than 10 / 20 / 100.
...ANSWER
Answered 2017-Sep-23 at 16:28I was talking to Neo4j developer at graphconnect about this and he told me that there is a performance penalty after more than 5 labels per node. So as a rule of thumb use less than 5 labels per node.
QUESTION
I have a C# object model that I want to persist with Neo4j. It contains dozens of Projects, which each has 1000-4000 children. I currently use the official C# driver, but I could switch to something else. Doing this one child at a time is, unsurprisingly, inefficient. This takes several minutes for one project:
...ANSWER
Answered 2017-Feb-06 at 10:181) First you need to create a dictionary with an array of names of services.
2) And inside query expand them using UNWIND.
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