N-Gram | N-Gram generator in Ruby - http
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kandi X-RAY | N-Gram Summary
N-Gram generator in Ruby - http://en.wikipedia.org/wiki/N-gram
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Trending Discussions on N-Gram
QUESTION
I have dataframe
...ANSWER
Answered 2022-Mar-28 at 19:16A self join can help, the second condition is implemented in the join condition. Then the n-grams are created by combining the arrays of the two sides. When combining the arrays the element that is common in both arrays is omitted:
QUESTION
I have a list of texts. I turn each text into a token list. For example if one of the texts is 'I am studying word2vec'
the respective token list will be (assuming I consider n-grams with n = 1, 2, 3) ['I', 'am', 'studying ', 'word2vec, 'I am', 'am studying', 'studying word2vec', 'I am studying', 'am studying word2vec']
.
- Is this the right way to transform any text in order to apply
most_similar()
?
(I could also delete n-grams that contain at least one stopword, but that's not the point of my question.)
I call this list of lists of tokens texts
. Now I build the model:
model = Word2Vec(texts)
then, if I use
words = model.most_similar('term', topn=5)
- Is there a way to determine what kind of results i will get? For example, if
term
is a 1-gram then will I get a list of five 1-gram? Ifterm
is a 2-gram then will I get a list of five 2-gram?
ANSWER
Answered 2022-Mar-07 at 23:20Generally, the very best way to determine "what kinds of results" you will get if you were to try certain things is to try those things, and observe the results you actually get.
In preparing text for word2vec training, it is not typical to convert an input text to the form you've shown, with a bunch of space-delimited word n-grams added. Rather, the string 'I am studying word2vec'
would typically just be preprocessed/tokenized to a list of (unigram) tokens like ['I', 'am', 'studying', 'word2vec']
.
The model will then learn one vector per single word – with no vectors for multigrams. And since it only knows such 1-word vectors, all the results its reports from .most_similar()
will also be single words.
You can preprocess your text to combine some words into multiword entities, based on some sort of statistical or semantic understanding of the text. Very often, this process converts the runs-of-related-words to underscore-connected single tokens. For example, 'I visited New York City'
might become ['I', 'visited', 'New_York_City']
.
But any such preprocessing decisions are separate from the word2vec algorithm itself, which just considers whatever 'words' you feed it as 1:1 keys for looking-up vectors-in-training. It only knows tokens, not n-grams.
QUESTION
I'm trying to find the most used n-grams of a pandas column in python. I managed to gather the following code allowing me to do exactly that.
However I would like to have the results split by "category" column. Instead of having a line with bi-gram|total frequency
like
"blue orange"|1
I would like three columns of bi-gram|frequency fruit|frequency|meat
like
..."blue orange"|1|0
ANSWER
Answered 2022-Feb-21 at 15:45Refactoring your code into a function you can apply
it per group:
QUESTION
I looked at multiple tutorials on how to derive n-grams (here I will stick to bigrams) and included them in the analysis in NLP.
My quesiton is that whether we need to include all the possible combinations of bigrams as features because not all the bigrams would be meaningful.
For example, if we have a sentence such as "I like this movie because it was fun and scary" and consider bigrams as well, these include (after pre-processing):
ANSWER
Answered 2022-Feb-21 at 07:40We may consider each bigram as a feature of different importance. Then the question can be reformulated as "How to choose the most important features?". As you have already mentioned, one way is to consider the top max features ordered by term frequency across the corpus. Other possible ways to choose the most important features are:
- Apply the TF-IDF weighting scheme. You will also be able to control two additional hyperparameters: max document frequency and min document frequency;
- Use Principle Component Analysis to select the most informative features from a big feature set.
- Train any estimator in scikit-learn and then select the features from the trained model.
These are the most widespread methods of feature selection in the NLP field. It is still possible use other methods like recursive feature elimination or sequential feature selection, but these methods are not feasible if the number of informative features is low (like 1000) and the total number of features is high (like 10000).
QUESTION
I am trying to upload Google n-gram word frequency data into a dataframe.
Dataset can be found here: https://www.kaggle.com/wheelercode/dictionary-word-frequency
A couple of words are not loading unfortunately. The word "null" appears on row 9156 of the csv file and the word "nan" appears on row 17230 of the csv file.
This is how I am uploading the data
...ANSWER
Answered 2022-Feb-20 at 04:53Pandas treats a certain set of values as "NA" by default, but you can explicitly tell it to ignore those defaults with keep_default_na=False
. "null" and "nan" both happen to be in that list!
QUESTION
I have a code that builds n-gram model to test next word prediction based on a corpus provided. How can I replace the given corpus to read WSJ corpus as the training corpus ? A part of the program is given below.
...ANSWER
Answered 2021-Dec-18 at 11:40If you are going to use the WSJ
corpus from nltk
package it would be available after you download it:
QUESTION
I am following the pytorch tutorial here and got to the word embeddings tutorial but there is some code I do not understand.
When constructing n-grams they use the following:
...ANSWER
Answered 2021-Dec-06 at 23:08This is a syntax of python like you can define a list like this:
QUESTION
I am trying to tokenize natural language for the first sentence in wikipedia in order to find 'is a' patterns. n-grams of the tokens and left over text would be the next step. "Wellington is a town in the UK." becomes "town
is a attr_root
in the country
." Then find common patterns using n-grams.
For this I need to replace string values in a string column using other string columns in the dataframe. In Pandas I can do this using
...ANSWER
Answered 2021-Nov-15 at 16:16Turns out I had a bug. Needed dfv
in the call to apply
instead of df
.
Also got this faster method from the nice people at vaex
.
QUESTION
ANSWER
Answered 2021-Nov-15 at 00:49I have achieved the result in a crude manner.
QUESTION
I would like to first extract repeating n-grams from within a single sentence using Gensim's Phrases, then use those to get rid of duplicates within sentences. Like so:
Input: "Testing test this test this testing again here testing again here"
Desired output: "Testing test this testing again here"
My code seemed to have worked for generating up to 5-grams using multiple sentences but whenever I pass it a single sentence (even a list full of the same sentence) it doesn't work. If I pass a single sentence, it splits the words into characters. If I pass the list full of the same sentence, it detects nonsense like non-repeating words while not detecting repeating words.
I thought my code was working because I used like 30MB of text and produced very intelligible n-grams up to n=5 that seemed to correspond to what I expected. I have no idea how to tell its precision and recall, though. Here is the full function, which recursively generates all n-grams from 2 to n::
...ANSWER
Answered 2021-Nov-01 at 04:59The Gensim Phrases
class is designed to statistically detect when certain pairs of words appear so often together, compared to independently, that it might be useful to combine them into a single token.
As such, it's unlikely to be helpful for your example task, of eliminating the duplicate 3-word ['testing', 'again', 'here']
run-of-tokens.
First, it never eliminates tokens – only combines them. So, if it saw the couplet ['again', 'here']
appearing ver often together, rather than as separate 'again'
and 'here'
, it'd turn it into 'again_here'
– not eliminate it.
But second, it does these combinations not for every repeated n-token grouping, but only if the large amount of training data implies, based on the threshold
configured, that certain pairs stick out. (And it only goes beyond pairs if run repeatedly.) Your example 3-word grouping, ['testing', 'again', 'here']
, does not seem likely to stick out as a composition of extra-likely pairings.
If you have a more rigorous definition of which tokens/runs-of-tokens need to be eliminated, you'd probably want to run other Python code on the lists-of-tokens to enforce that de-duplication. Can you describe in more detail, perhaps with more examples, the kinds of n-grams you want removed? (Will they only be at the beginning or end of a text, or also the middle? Do they have to be next-to each other, or can they be spread throughout the text? Why are such duplicates present in the data, & why is it thought important to remove them?)
Update: Based on the comments about the real goal, a few lines of Python that check, at each position in a token-list, whether the next N tokens match the previous N tokens (and thus can be ignored) should do the trick. For example:
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