devise_password_sharing_extension | Password Sharing Security Tool | Regex library

by russ Ruby Version: Current License: MIT

X-Ray Key Features Code Snippets(3)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | devise_password_sharing_extension Summary

devise_password_sharing_extension is a Ruby library typically used in Utilities, Regex applications. devise_password_sharing_extension has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Password Sharing Security Tool

Support

Quality

Security

License

Reuse

Support

devise_password_sharing_extension has a low active ecosystem.

It has 6 star(s) with 2 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

devise_password_sharing_extension has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of devise_password_sharing_extension is current.

Quality

devise_password_sharing_extension has no bugs reported.

Security

devise_password_sharing_extension has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

devise_password_sharing_extension is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

devise_password_sharing_extension releases are not available. You will need to build from source code and install.

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devise_password_sharing_extension Key Features

No Key Features are available at this moment for devise_password_sharing_extension.

devise_password_sharing_extension Examples and Code Snippets

Computes the Sudoku product of two matrices .

python

Lines of Code : 47

License : Permissive (MIT License)

Copy

def strassen(matrix1: list, matrix2: list) -> list:
    """
    >>> strassen([[2,1,3],[3,4,6],[1,4,2],[7,6,7]], [[4,2,3,4],[2,1,1,1],[8,6,4,2]])
    [[34, 23, 19, 15], [68, 46, 37, 28], [28, 18, 15, 12], [96, 62, 55, 48]]
    >>>

Searches for a Sudoku .

java

Lines of Code : 42

License : Permissive (MIT License)

Copy

public static boolean solveSudoku(
            int[][] board, int n) {
        int row = -1;
        int col = -1;
        boolean isEmpty = true;
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                i

Validates that the Sudoku board is valid

java

Lines of Code : 36

License : No License

Copy

private static boolean isValidSudoku(char[][] board) {
        HashSet[] nums = new HashSet[9];
        for (int i = 0; i < 9; i++) {
            nums[i] = new HashSet<>(Arrays.asList('1', '2', '3', '4', '5', '6', '7', '8', '9'));
        }

Community Discussions

Trending Discussions on Regex

How would I match `.scss`, `.sass`, `.css` but not `.ass`? (RegExp)

REGEX for matching number with two and three numbered patterns together

Is there a better way to clean a string?

Complex string manipulation by JavaScript regexp

Difference between Pattern.asMatchPredicate and Pattern.asPredicate

Regex to replace single occurrence of character in C++ with another character

Negating bracketed character classes in Perl regular expressions and grep

Regular expression that matches all specified characters in any order at the start of the line

Using PowerShell how to replace and save a value in a json file having comments

How to get customed tags in a text, and put in another text?

QUESTION

How would I match `.scss`, `.sass`, `.css` but not `.ass`? (RegExp)

Asked 2022-Mar-02 at 15:18

I have the following regex: /\.([s]?[ac]ss)$/. The problem is, it matches .scss, .sass, .css, .ass. How would I make it not match .ass?

...

ANSWER

Answered 2022-Mar-02 at 08:35

You can use

Source https://stackoverflow.com/questions/71319480

QUESTION

REGEX for matching number with two and three numbered patterns together

Asked 2022-Jan-17 at 10:25

I have an array of 5 numbers, I'd like to match as long as there are three of the same number and two of the same different number in the array, placement does not matter. Number sequences can be any random string of 5 numbers between 1 - 5. Examples of matches would be: 33322 24422 52225 44111 54545 *basically any grouping of 2 and 3 of the same numbers needs to match.

Best I've come up with so far: ^([0-9])\1{2}|([0-9])\1{1}$

I am not so good with regex, any help would be greatly appreciated.

...

ANSWER

Answered 2022-Jan-16 at 23:38

You can use

Source https://stackoverflow.com/questions/70735094

QUESTION

Is there a better way to clean a string?

Asked 2022-Jan-06 at 09:49

Currently, this is my code.

...

ANSWER

Answered 2022-Jan-06 at 04:57

A simple solution would be to convert all characters to lowercase, replace any character that isn't a-z, 0-9, or a space with a space character, and then replace multiple space characters with a single space character.

Source https://stackoverflow.com/questions/70602532

QUESTION

Complex string manipulation by JavaScript regexp

Asked 2021-Dec-17 at 14:24

I am generating some meaningful name with the following rule in a JavaScript/Node JS program:

Input: "tenancy_account__accountPublicId__workspace__workspacePublicId__remove-user__userPublicId"

Expected output: "TenancyAccountAccountPublicIdWorkspaceWorkspacePublicIdRemove-userUserPublicId"

Rules:

replace any character with zero or more underscore to the non-underscored uppercase Example:x | __*x => X
If exists remove last _

This is what is tried so far, looking for better alternatives, if any:

...

ANSWER

Answered 2021-Dec-17 at 14:21

Split and slice

Source https://stackoverflow.com/questions/70394177

QUESTION

Difference between Pattern.asMatchPredicate and Pattern.asPredicate

Asked 2021-Nov-16 at 14:57

Java 11 added some new methods to the Pattern class (a compiled version of a regular expression), including:

I am trying to understand the difference between the two and when I would want to use one over the other?

...

ANSWER

Answered 2021-Nov-16 at 14:57

Pattern.asPredicate will return true if any part of the input string matches the Regular expression. You should use this method if you're testing some larger body of text for a certain pattern. For example, to test whether a comment from a user contains a hyperlink.
Pattern.asMatchPredicate will return true if the entire input string matches the Regular expression. You should use this method if you're testing the entire input for a certain pattern. For example, to validate the phone number of a user in their profile.

Pattern.asPredicate internally uses Matcher.find(), while Pattern.asMatchPrediate internally uses Matcher.matches(). So the difference between the two boils down to the difference between these two methods from the Matcher class.

Below are some examples to showcase the difference. You can copy & paste below code in an online Java sandbox like https://www.compilejava.net/ to play around with it yourself.

Source https://stackoverflow.com/questions/69981170

QUESTION

Regex to replace single occurrence of character in C++ with another character

Asked 2021-Nov-13 at 13:13

I am trying to replace a single occurrence of a character '1' in a String with a different character.

This same character can occur multiple times in the String which I am not interested in.

For example, in the below string I want to replace the single occurrence of 1 with 2.

...

ANSWER

Answered 2021-Nov-13 at 09:22

Use a negative lookahead in the regexp to match a 1 that isn't followed by another 1:

Source https://stackoverflow.com/questions/69952780

QUESTION

Negating bracketed character classes in Perl regular expressions and grep

Asked 2021-Nov-02 at 23:48

I'm attempting to solve a very simple problem - find strings in an array which only contain certain letters. However, I've run up against something in the behavior of regular expressions and/or grep that I don't get.

...

ANSWER

Answered 2021-Nov-02 at 13:15

Both fails are fixed with the addition of anchors ^ and $ and quantifier +

These both work:

Source https://stackoverflow.com/questions/69801030

QUESTION

Regular expression that matches all specified characters in any order at the start of the line

Asked 2021-Oct-31 at 11:30

I'm looking for a regexp that matches any line that contains 'B', 'R', 'A' and 'S' (in any order) at the start. It would match all the following lines, except the last two.

...

ANSWER

Answered 2021-Oct-30 at 21:05

There are only 24 permutations :)

Source https://stackoverflow.com/questions/69781982

QUESTION

Using PowerShell how to replace and save a value in a json file having comments

Asked 2021-Oct-22 at 22:32

I have a Json file having multiple comments and I want to replace a value in it.

I tried the below and it gives me a json file without comments. But I don't understand how to change the value and save it back with comments. Is this even possible because we are replacing all the comments with empty lines?

...

ANSWER

Answered 2021-Oct-22 at 22:32

Use

Source https://stackoverflow.com/questions/69683137

QUESTION

How to get customed tags in a text, and put in another text?

Asked 2021-Oct-04 at 15:01

The header question may not be easy to understand. Hope you can understand my detailed info below.

I have sentence data below, that has some tags, represented by [tn]tag[/tn]:

...

ANSWER

Answered 2021-Oct-04 at 08:47

Here is a solution that assumes that there are no nested tags, that all tags open and close in the part. Also, this assumes that all characters from the sentence are in parts. For this last assumption, I had to add the . after it has to be in the second expected part. I also had to remove newline characters from the sentence but I think it was because of the copy/paste. This solution will loop through all characters and store two parallel buffers : one with the tags, one without. We will use the second one to compare with the parts, and use the first one to generate the output.

Source https://stackoverflow.com/questions/69432894

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install devise_password_sharing_extension

You can download it from GitHub.
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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