excellent | XLS generation from html tables through XERB templates | Grid library

 by   stevo Ruby Version: Current License: No License

kandi X-RAY | excellent Summary

kandi X-RAY | excellent Summary

excellent is a Ruby library typically used in User Interface, Grid applications. excellent has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

EXCELlent is a custom template handler (XERB) for specifying XLS files just as regular XHTML tables. This is kind of limited at the moment, but damn - this is 0.0.1 alpha release :). Currently EXCELlent (or XERB) supports. First things first - installation. EXCELlent relies on spreadsheet and nokogiri gems, so if you haven't already... Then in your controller, add new respond_to format. Then we need our view. Just create file named index.xls.xerb and create a simple table. From now on, simple link. will enable you to download Excel version of your table :). Styling issues: For unknown reason executing spreadsheet::row::set_format method on the first row and it's last cell make whole last column disappeared in the result file. Because of it styling in the first row is currently ignored. Copyright (c) 2009 b.kosmowski@selleo.com [Stevo], released under the MIT license.
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            kandi-support Support

              excellent has a low active ecosystem.
              It has 17 star(s) with 3 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 2 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of excellent is current.

            kandi-Quality Quality

              excellent has 0 bugs and 0 code smells.

            kandi-Security Security

              excellent has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              excellent code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              excellent does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              excellent releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.
              excellent saves you 49 person hours of effort in developing the same functionality from scratch.
              It has 130 lines of code, 14 functions and 7 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

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            excellent Key Features

            No Key Features are available at this moment for excellent.

            excellent Examples and Code Snippets

            No Code Snippets are available at this moment for excellent.

            Community Discussions

            QUESTION

            How To dynamically generate an HTML Table using ngFor. in Angular
            Asked 2021-Jun-15 at 09:50

            I am trying to dynamically generate the following html table, as seen on the screenshot

            I was able to manually create the table using dummy data, but my problem is that I am trying to combine multiple data sources in order to achieve this HTML table structure.

            SEE STACKBLITZ for the full example.

            The Data looks like this (focus on the activities field):

            ...

            ANSWER

            Answered 2021-Jun-13 at 13:28

            Oh, if you can change your data structure please do.

            Source https://stackoverflow.com/questions/67956130

            QUESTION

            Assign grading based on available data in R data.frame?
            Asked 2021-Jun-14 at 19:37

            I have the following two data.frame. I want to get the Grade from D1 and Assign to the Pts in D. Once the operations completes the D data.frame should have a columns for Pts,Val, and Grade without C or Good Grade.

            ...

            ANSWER

            Answered 2021-Jun-14 at 19:32

            We can use a join in data.table by joining on by 'Pts' column and assign (:=) the 'Grade' from D1 to D

            Source https://stackoverflow.com/questions/67976193

            QUESTION

            Recursing to a function that doesn't exist yet in Haskell
            Asked 2021-Jun-10 at 23:14

            I'm stuck on a problem with writing a parser in Haskell that I hope someone can help out with!

            It is a bit more complicated than my usual parser because there are two layers of parsing. First a language definition is parsed into an AST, then that AST is transformed into another parser that parses the actual language.

            I have made pretty good progress so far but I'm stuck on implementing recursion in the language definition. As the language definition is transformed from AST into a parser in a recursive function, I can't work out how it can call itself if it doesn't exist yet.

            I'm finding it a bit hard to explain my problem, so maybe an example will help.

            The language definition might define that a language consists of three keywords in sequence and then optional recursion in brackets.

            ...

            ANSWER

            Answered 2021-Jun-10 at 18:53

            I believe you can use laziness here. Pass the final parser as a parameter to transformSyntaxExprToParser, and when you see a Recurse, return that parser.

            Source https://stackoverflow.com/questions/67919833

            QUESTION

            Columns side by side with css grid
            Asked 2021-Jun-10 at 13:29

            I am having a problem understanding how CSS grid works.

            I want 3 columns side by side with a specific width and height, but there's a gap between each columns.

            ...

            ANSWER

            Answered 2021-Jun-05 at 22:38

            You can simply specify the widths that you need in the grid-template-columns property. There is no gap visible between columns.

            If you want the red borders you can specify a common class for those divs and just do it once.

            Source https://stackoverflow.com/questions/67854299

            QUESTION

            Simplifying gather() with pivot_longer() using multiple ID columns and value columns
            Asked 2021-Jun-08 at 22:12

            I'm working to get a better handle on pivot_longer, coming from a gather user. From the source documents it seems like I should be able to do the following in a single command using name_pattern or names_sep but I've been unable to find a working solution.

            Data

            ...

            ANSWER

            Answered 2021-Jun-08 at 20:20

            You can use the following solution. In this case we create 2 capture groups. What .value does here actually is to define for pivot_longer the part of the name that contains the name of the value we are trying to measure. Here the left side of the underscore are values value and status. The right side of the underscore which is in fact the result of our second capturing group defines the id. And it should be noted that the length of names_to argument should be the same as the number of capturing groups in names_pattern or possibly names_sep.

            Source https://stackoverflow.com/questions/67893983

            QUESTION

            Kotlin by lazy throws NullPointerException
            Asked 2021-Jun-08 at 16:39

            I am currently trying to learn Kotlin with the help of the book "Kotlin Programming The Big Nerd Ranch Guide" and so far everything worked. But now I am struggling with the "lazy" initialization which throws a NullPointerException which says

            Cannot invoke "kotlin.Lazy.getValue()" because "< local1>" is null

            The corresponding lines are:

            ...

            ANSWER

            Answered 2021-Jun-08 at 16:39

            When something like this happens, it's usually due to bad ordering of initialization.

            The initialization of the Player class goes this way:

            1. the name property has its backing field initialized with the _name value
            2. the init block is run, and tries to access name
            3. the getter of name tries to read the hometown property, but fails because hometown is still not initialized
            4. ...if things had gone right, the hometown property would be initialized now with the lazy delegate

            So basically you're trying to access hometown before the lazy delegate is configured. If you move hometown's declaration above the init block, you should be fine.

            You can see the fix in action on the playground

            Source https://stackoverflow.com/questions/67890451

            QUESTION

            pandas check if value exists in one specific index in a MultiIndex dataframe
            Asked 2021-Jun-05 at 20:09

            I have a MultiIndex data frame called df with 3 indexes (Fruit, Color, Taste). I want to search 1 specific index, that index being Color and see if the value exists in it.

            For example: the code would look something like this. Color is an index in the dataframe not just a column.

            ...

            ANSWER

            Answered 2021-Jun-05 at 20:01

            Try xs to grab a cross-section from the DataFrame:

            Source https://stackoverflow.com/questions/67853446

            QUESTION

            python3 email message to disable base64 and remove MIME-Version
            Asked 2021-Jun-05 at 17:41
            from email.message import EmailMessage
            from email.headerregistry import Address
            msg = EmailMessage()
            
            msg['From'] = Address("Pepé Le Pew", "pepe", "example.com")
            msg['To'] = (
                    Address("Penelope Pussycat", "penelope", "example.com")
                    , Address("Fabrette Pussycat", "fabrette", "example.com")
                    )
            msg['Subject'] = 'This email sent from Python code'
            msg.set_content("""\
                    Salut!
            
                    Cela ressemble à un excellent recipie[1] déjeuner.
            
                    [1] http://www.yummly.com/recipe/Roasted-Asparagus-Epicurious-203718
            
                    --Pepé
                    """)
            print(msg)
            
            ...

            ANSWER

            Answered 2021-Jun-05 at 17:41

            You absolutely must not remove the MIME-Version: header; it's what identifies this as a MIME message.

            The From: header should indeed be RFC2047-encoded, and the documentation suggests that it will be "when the message is serialized". When you print(msg) you are not properly serializing it; you want print(msg.as_string()) which does exhibit the required serialization.

            When it comes to the transfer encoding, Python's email library has an unattractive penchant for using base64 for content which could very well be encoded as quoted-printable instead. You can't really reliably send the content completely unencoded (though if you wanted to, the MIME 8bit or binary encodings would be able to accommodate that; but for backwards compatibility, SMTP requires everything to be encoded into a 7-bit representation).

            In the old email library, various shenanigans were required to do this, but in the new EmailMessage API introduced in Python 3.6, you really only have to add cte='quoted-printable' to the set_content call.

            Source https://stackoverflow.com/questions/66039715

            QUESTION

            What does * mean in git rev-list?
            Asked 2021-Jun-03 at 21:20

            Just for context, I've got a Git repo with a number of remotes, some of which I consider less important and put in a subgroup by prepending them with a group name and a slash. For example, I might have origin, othercomputer as my "main" remotes; and otherpeople/alice, otherpeople/bob as secondary remotes that I just check in on occasionally. I was looking for a simple way to make gitk only list branches in my main remotes (since gitk --all lists everything).

            Just as a random thing, I tried running gitk \*, and frankly to my surprise, it seems to have done exactly what I was looking for (displaying my local branches and my "main" remotes), so I tried to figure out what it actually does. Since the arguments to gitk are mostly the same as those to git rev-list, I've been trying to read that manpage in order to do that, but I can't find anything.

            So, what does gitk \* do, and where is this documented? (I assume that it is documented, since Git documentation is generally quite excellent.)

            (Just to avoid confusion, the backslash in \* is the shell escape to pass the asterisk unmodified to gitk. I did not mean to imply that I'm actually passing that backslash to gitk.)

            ...

            ANSWER

            Answered 2021-Jun-03 at 21:13

            gitk * (with the star quoted from the shell) causes gitk to run:

            Source https://stackoverflow.com/questions/67828480

            QUESTION

            How are people implementing immutable data structures in JavaScript when the language doesn't offer any obvious way of implementing immutability?
            Asked 2021-Jun-03 at 21:09

            So I decided to tryout functional programming because people say it gives you more control over the programs that you write, it's extremely testable, and it makes code more readable & easy to follow — who wouldn't want that..?

            Obviously I decided to try writing a program using the functional paradigm. I got stuck, nearly just as soon as I decided to try writing the thing. I couldn't really figure out how to make all of the program's data immutable. My first thought was to use all const declared variables, since a const variable cannot be re-referenced after the initial assignment, however; I found out that implementing an immutable data structure is quite different from declaring several const variables to store a programs state in. It became quite clear to me that I was going to need immutable objects, with immutable properties, and so forth. After attempting to create an Immutable data structure (example is at the question's bottom). I concluded that that JavaScript doesn't really have a way of implementing Immutable data, at least not a way that is obvious. And now here I am, scratching my head...

            What I would like to know is:

            "How are the people, who are writing JavaScript programs, using the Functional Programming paradigm implementing immutable data structures when the language doesn't really offer any sort of way implementing immutability?

            EDIT: I want to be as clear as possible, because I have struggled with clarity in some of my past questions, so I am just going to sorta meta-explain what I am asking for:

            In a nutshell, what I would like to know is: How does a person implement immutable data structures that work for the functional programming paradigm. An example of Any immutable data structure will suffice, or even an immutable object. If the answer involves use 3rd party libraries, other languages, or any other tool that would be great, and an example of what code using those tools might look like would be really excellent.

            Below is some code, where I was trying to hack a JS object into being immutable. Its not good code, in fact it throws an error, but it demonstrates my mindset, and what I am trying to solve.

            ...

            ANSWER

            Answered 2021-Jun-03 at 00:44

            Welcome to Functional Programming!

            One solution is using ES6 class. getter returns property's deep copy, setter throws error.

            Example Code:

            Source https://stackoverflow.com/questions/67758847

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install excellent

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/stevo/excellent.git

          • CLI

            gh repo clone stevo/excellent

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            git@github.com:stevo/excellent.git

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