namedict | Generate Chinese names for the newborn baby | Translation library

 by   thyrlian Ruby Version: Current License: No License

kandi X-RAY | namedict Summary

kandi X-RAY | namedict Summary

namedict is a Ruby library typically used in Utilities, Translation, Transformer applications. namedict has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Before you use this utility, please try to answer the three questions below. If all answers are "Yes", just go ahead. Congratulations, Mr. Yes! I think this tool will meet your requirements and helps you give your child an Easy-to-Read Chinese name. That's the initial idea, just to make it pronounceable for foreigners, and provide a consistent pronunciation in Chinese and other languages. It's not trying to catch up with the international trend.
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            kandi-support Support

              namedict has a low active ecosystem.
              It has 38 star(s) with 12 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              namedict has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of namedict is current.

            kandi-Quality Quality

              namedict has 0 bugs and 0 code smells.

            kandi-Security Security

              namedict has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              namedict code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              namedict does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              namedict releases are not available. You will need to build from source code and install.
              namedict saves you 110 person hours of effort in developing the same functionality from scratch.
              It has 280 lines of code, 39 functions and 14 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

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            namedict Key Features

            No Key Features are available at this moment for namedict.

            namedict Examples and Code Snippets

            No Code Snippets are available at this moment for namedict.

            Community Discussions

            QUESTION

            Updating a dictionary item within an outer dictionary
            Asked 2021-Mar-20 at 14:58

            I'm a bit confused by the following code. I would have expected that only the 'D' value in the 'Bob' outer dictionary would have been changed, but instead all the 'D' items have been updated. Any ideas as to what is going on here?

            ...

            ANSWER

            Answered 2021-Mar-20 at 14:58

            Assignment statements in Python do not copy objects, they create bindings between a target and an object. So when you are doing nameDict[n] = zeroItemDict it means a shallow copy of zeroItemDict is assigned to every key of nameList. Any changes made to zeroItemDict will reflect in all of the copies made.
            To avoid this use copy.deepcopy when you're assigning zeroItemDict like this nameDict[n] = copy.deepcopy(zeroItemDict).

            Note: The difference between shallow and deep copying is only relevant for compound objects

            Read more about shallow and deep copy operations.

            Source https://stackoverflow.com/questions/66722827

            QUESTION

            Why do my python dictionaries keep overwriting
            Asked 2020-Apr-10 at 16:18

            What I am trying to do is create a dictionary within a dictionary. It is supposed to be a movie lover's club in which you can add movies to a member's account, but when I try to add it, it gets overwritten. Below is my code:

            ...

            ANSWER

            Answered 2020-Apr-10 at 16:18

            Edit2: With your updated code, here's the solution to your problem. You were actually really close, the only issue was that you were using .update on the movies dictionary, rather than the movies[name] dictionary, so you would replace movies[name] with your new movie dict each time. The solution here is to update movies[name] instead. Also, I made a change to your option_five function so that when you add a new member, they have an empty dictionary by default rather than an empty string, so it can be updated:

            Source https://stackoverflow.com/questions/61140334

            QUESTION

            python making list of averages from dictionary of dictionaries: all averages same
            Asked 2019-Dec-06 at 21:38

            I have a dictionary of dictionaries, d:

            ...

            ANSWER

            Answered 2019-Dec-06 at 21:38

            Using the code with a couple of minor calculations, I was able to get [9.5, 9.0, 9.75, 8.5]

            The two changes I made was that I had to cast the output of dictionary d to a float(), and I changed nameDict to d, since nameDict was not defined in the example code provided. Here is the resulting code below:

            Source https://stackoverflow.com/questions/59220205

            QUESTION

            Having trouble with writing a simple python password reset code sample
            Asked 2019-Nov-18 at 10:51

            I'm new to Python and trying to wirte a simple password reset code sample to learn about sets, dictionaries, and exception handlers. To reset a password, the program must first take in both the student_id and user_id and confirms their ID against the list. If the student_id and user_id match, it will prompt the user for their admission term as an extra security measure. If all things match, the program will greet the user by name and prompt their to enter their new password. The new password cannot match any of the user's previous passwords. The program should not quit until the user asks to quit or successfully logs in (note, resetting the password should not be the end and we may give the user a "quit" option if they decide they do not want to change their password.).

            The program should run similar to the following:

            ...

            ANSWER

            Answered 2019-Nov-18 at 08:16

            Ok so quick disclaimer all the code in this is sudo code and is for example to give you the idea of my train of thought.

            So that out of the way I see your problems as the following.

            • User Input (Actions)
            • DataBase Handling

            If I am correct on this I would suggest that you take the following approach.

            1. Take care of the Database, by writing a class to handle the getting and setting of specific user in an out of the database that you are using and into a dictionary or any other data structure allows you to forget the structure of the underlying csv etc and will make you actions clearer and simpler later on. something like below would do the trick.

            Source https://stackoverflow.com/questions/58909845

            QUESTION

            Converting two lists to json
            Asked 2019-Jul-10 at 16:02

            I'm attempting to convert two lists to json.

            For example :

            ...

            ANSWER

            Answered 2019-Jul-10 at 14:35

            Disclaimer: Since we don't know where the g comes from, I will only build the root children array.

            Since your arrays have the same length, you can use a plain for and use with the index to play with both arrays. Just build an array and check each iteration if the "child" already exists. If not, create it.

            Source https://stackoverflow.com/questions/56972787

            QUESTION

            FileNotFoundException (stderr & stdout) when submitting JAR to Spark in EMR environment
            Asked 2019-Mar-01 at 11:18

            I'm following the 'Apache Spark with Scala - Hands on with Big Data' course on Udemy.
            In one of the lectures, you have to set up an EMR environment and submit a JAR file to the cluster.
            When submitting the code, I get the following error.
            Edit: code does actually proceed after the error.

            ...

            ANSWER

            Answered 2018-Nov-06 at 13:11

            spark-submit --class com.sundogsoftware.spark.MovieSimilarities1M /path/to/jar/MovieSimilarities1M-assembly-1.0.jar

            you need to provide the class name as well

            Source https://stackoverflow.com/questions/53172517

            QUESTION

            Spark Scala throws "java.util.NoSuchElementException: key not found" with Broadcast variable
            Asked 2019-Jan-11 at 13:07

            I have a broadcast variable which is constructed in the following manner

            ...

            ANSWER

            Answered 2017-Feb-24 at 20:09

            One way to create a local map is to use collectAsMap:

            Source https://stackoverflow.com/questions/42447199

            QUESTION

            What is wrong with this Spark RDD mapped with a lambda function with two arguments?
            Asked 2018-Dec-26 at 21:53
            Goal#
            • Print a dataset with Movie Name & Number of times it has been rated.
            • That's a simple way to get the most "popular" movie
            Data
            • One file called "u.data" with movieID, userID, ratings, timestamp
            • One file called "u.item" with movieID and movie name and information about - each movie
            Method
            • Create a dictionnary key = MovieID, values = Name from the u.item files
            • Broadcast the dictionary to the executioner nodes on the cluster
            • Create a rdd with the MovieID and 1 on each line
            • Reduce this rdd by movieID and sum each one
            • Flip the key(movieID) and the value(Total) to sort the dataset by this total
            Issue
            • Then I should map the movieID with the broadcasted dictionary but I get a syntax error on this line:
              sortedMoviesWithNames = sortedMovies.map(lambda (count, movie) : (nameDict.value[movie], count))

            This code example is from cookbook for Apache Spark and Python. All others codings exercises work perfectly on my environment. Windows 10 / Canopy / Python 3.5 / Spark 2.3.2 I've checked the broadcasted dictionary it's ok, and already print the sortedMovies RDD which is ok too. I've checked the online errata of the book, nothing too.

            I'm wondering if this is a syntax error due to the Python version or something like that.

            ...

            ANSWER

            Answered 2018-Dec-26 at 21:53

            I believe the correct syntax for a lambda with multiple arguments is:

            Source https://stackoverflow.com/questions/53937399

            QUESTION

            How can I get the correct value from a dictionary with another list as keys?
            Asked 2018-Nov-10 at 17:28

            I tried my best to look for other answers, but I don't manage to find out how I can do it.

            I have a dictionary like this:

            ...

            ANSWER

            Answered 2018-Nov-10 at 17:17

            Use dict.get with list comprehesion as:

            Source https://stackoverflow.com/questions/53241334

            QUESTION

            Euler 22 code not returning correct answer
            Asked 2018-May-14 at 13:17

            I have been trying to do Problem 22 on Project Euler, but I cannot seem to get the right answer or see any problem with my code. I copied and pasted the contents of the txt file rather than accessing it directly from my code.

            https://projecteuler.net/problem=22

            ...

            ANSWER

            Answered 2018-May-14 at 13:16

            You are close. There are a few problems with your code:

            1. namedict is not a dictionary, it is a list.
            2. The requirement is to sort alphabetically by name, not by value.
            3. You need to use or store indices of your sorted list. I use enumerate for this.

            Combining these elements:

            Source https://stackoverflow.com/questions/50330950

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install namedict

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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