ast | A library for working with Abstract Syntax Trees | Parser library
kandi X-RAY | ast Summary
kandi X-RAY | ast Summary
AST is a small library for working with immutable abstract syntax trees.
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Top functions reviewed by kandi - BETA
- String representation of this node .
- Convert a representation of this node .
- Returns a new instance of the specified + self + of + self + self + or + self + self + .
- Convert self to an Array of child elements
- Assign hash of properties
- Creates a node
- Convert to type .
- Appends a new array into an array
- Constructs a list of children .
- Append an element to this collection .
ast Key Features
ast Examples and Code Snippets
Lines of Code : 38License : Non-SPDX (Apache License 2.0)
Copydef transform_function(self, fn, user_context):
"""Transforms a function.
Subclasses may override this method. The return value is opaque.
The method receives the original AST. The result is passed as-is to the
output of `transform` def load_ast(nodes,
indentation=' ',
include_source_map=False,
delete_on_exit=True):
"""Loads the given AST as a Python module.
Compiling the AST code this way ensures that the source code is readable by
def to_ast(self):
"""Returns a representation of this object as an AST node.
The AST node encodes a constructor that would create an object with the
same contents.
Returns:
ast.Node
"""
if self == STANDARD_OPTIONS:
Community Discussions
Trending Discussions on ast
QUESTION
I've used a web API to import data from a specific website. I was able to import the data in JSON format. I am very new to python, hence finding hard to transform it to a tabular format which I can use it for my data analysis. Here's my sample code;
...ANSWER
Answered 2021-Jun-15 at 12:09Is it what you expect?
QUESTION
I want to encrypt files fore secure storage, but the problem is, I don't know how to store the key to decrypt the files afterwards.
Code:
...ANSWER
Answered 2021-Jan-03 at 15:18The way you're encrypting data makes no sense. Asymmetric encryption can only encrypt a small, fixed amount of data. Never use asymmetric encryption such as RSA-OAEP for anything other than a symmetric key, and use that symmetric key to encrypt the actual data. For the symmetric encryption, use a proper AEAD mode such as AES-GCM or ChaCha20-Poly1305. This is called hybrid encryption.
Other things that are wrong with your code:
- A 1024-bit RSA key is not enough for security: 2048-bit is a minimum, and you should prepare to move away from RSA because its key sizes don't scale well. (Feel free to use 1024-bit keys for testing and learning, just don't use anything less than 2048-bit for RSA in production.)
- The encryption is a binary format, but you join up lines as if they were text. Text or binary: pick one. Preferably use a well-known format such as ASN.1 (complex but well-supported) for binary data or JSON for text. If you need to encode binary data in a text format, use Base64.
If this is for real-world use, scrap this and use NaCl or libsodium. In Python, use a Python wrapper such as libnacl, PyNaCl, pysodium or csodium. Use a public-key box. The Python APIs are slightly different for each Python wrapper, but all include a way to export the keys.
If this is a learning exercise, read up on hybrid encryption. Look inside libsodium to see how to do it correctly. Key import and export is done with the methods import_key and export_key. Symmetric encryption starts with Crypto.Cipher.AES.new(key, Crypto.Cipher.AES.MODE_GCM) or Crypto.Cipher.ChaCha20_Poly1305.new(key) (Crypto.Cipher.AES.new(key, Crypto.Cipher.AES.MODE_GCM, nonce=nonce) or Crypto.Cipher.ChaCha20_Poly1305.new(key, nonce=nonce) for decryption).
QUESTION
i am working in jave, spring, mysql, hibernate environment
I have the following hql it gives me the correct out put
ANSWER
Answered 2021-Jun-15 at 07:06Instead of
QUESTION
I'm trying to learn Flask and use postgresql with it. I'm following this tutorial https://realpython.com/flask-by-example-part-2-postgres-sqlalchemy-and-alembic/, but I keep getting error.
...ANSWER
Answered 2021-Jun-15 at 02:32I made a new file database.py and defined db there.
database.py
QUESTION
I have a DB in MongoDB like this:
ANSWER
Answered 2021-Jun-14 at 15:39$filterto iterate loop ofSeriesarray$regexMatchto search format inseb$sizeto get total elements in filtered result
QUESTION
def list(A):
head=0
tail=1
new_list=[]
for i in A:
if i==1:
new_list.append(i)
if i==1:
new_list.append(i)
print(new_list)
ANSWER
Answered 2021-Jun-14 at 13:22You can refer to this simple program.
QUESTION
Looking at AST explorer, JSDoc comments are parsed into a nice domain specific AST. Example:
So the following code:
...ANSWER
Answered 2021-Jun-14 at 03:36The ASTExplorer link has the Typescript parser enabled, not Babel's. Typescript parses JSDoc comments, because Typescript lets you use JSDoc annotations for types.
QUESTION
Similar questions to this have been asked many times, but surprisingly few of the answers seem to address what I believe my problem to be.
I have csv files with one or more columns that contain a dictionary in each cell. After read_csv step, I have tried ast.literal_eval on these columns in order to convert the str format dicts into dict type objects. However, I keep getting the malformed node or string error.
Here is a typical example of the dicts in question: {1: 3681.45, 0: 3693.3333333333335}. And another, with a nan value: {1: 4959.95652173913, 0: nan}. Edit: It was only this nan value causing the error, in fact (see Rakesh's solution below).
Looking through previous answers, one reason for this error may be because most of the values of the dicts in these columns are floating point numbers, and apparently literal_eval can't handle floats or nans, even if they're contained within dictionaries (although, this is me inferring from a question about tuples).
I had to read a lot of questions and answers even to get this much information, so thought it could be useful to start a new topic with the keywords str, dict, but also nan in the title.
Any help much appreciated!
...ANSWER
Answered 2021-Jun-13 at 17:41Use eval on json that has nan
Ex:
QUESTION
I am trying to scrape the NBA player names and projected fantasy score (not single stat DFS) using selenium. I've gotten as far as using selenium to automate clicking NBA, and selecting the fantasy score tab.
From there, I see the players in a grid where I will like to scrape the points and names for each player. I have attempted to loop through the grid but I don't think I'm doing it right
Can someone please take a look at my code and point me in the right direction ?
...ANSWER
Answered 2021-Jun-12 at 18:58See you are using
QUESTION
I'm trying to scrape some data off ESPN and run some calculations off the scraped data. Ideally, I will like to iterate through a dataframe, grab the players name with Selenium, send the player's name into the search box and tell Selenium to click the player's name. I was able to do this successfully with one player. I'm not quite sure how to iterate through all the players in my data frame.
The second part of the code is where I'm struggling. For some reason I am not able to get the data. Selenium isn't able to find any of the elements. I don't think I'm doing it properly. If I am able to scrape the required data, I will like to plug them into a calculation and append the calculated projected points into my dataframe, dfNBA.
Can someone please help me with my code? and point me in the right direction. I'm trying to be more efficient writing python codes but right now I'm stuck
Thanks
...ANSWER
Answered 2021-Jun-13 at 15:52Here's some code to accomplish (I think) what you want. You need to wait for the table elements to appear, fix your xpath, and choose the right elements from the table array.
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Vulnerabilities
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Install ast
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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