forest | 🌲 Rust Filecoin Node Implementation | Blockchain library

 by   ChainSafe Rust Version: v0.8.2 License: Apache-2.0

kandi X-RAY | forest Summary

kandi X-RAY | forest Summary

forest is a Rust library typically used in Blockchain, Bitcoin applications. forest has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Forest is an implementation of Filecoin written in Rust. The implementation will take a modular approach to building a full Filecoin node in Rust from the Filecoin Protocol Specification, specifically the virtual machine, blockchain, and node system.
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              forest has a low active ecosystem.
              It has 548 star(s) with 138 fork(s). There are 32 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 147 open issues and 1082 have been closed. On average issues are closed in 70 days. There are 13 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of forest is v0.8.2

            kandi-Quality Quality

              forest has 0 bugs and 0 code smells.

            kandi-Security Security

              forest has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              forest code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              forest is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              forest releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            forest Key Features

            No Key Features are available at this moment for forest.

            forest Examples and Code Snippets

            copy iconCopy
            def includes_any(lst, values):
              for v in values:
                if v in lst:
                  return True
              return False
            
            
            includes_any([1, 2, 3, 4], [2, 9]) # True
            includes_any([1, 2, 3, 4], [8, 9]) # False
            
              
            copy iconCopy
            const lowercaseKeys = obj =>
              Object.keys(obj).reduce((acc, key) => {
                acc[key.toLowerCase()] = obj[key];
                return acc;
              }, {});
            
            
            const myObj = { Name: 'Adam', sUrnAME: 'Smith' };
            const myObjLower = lowercaseKeys(myObj); // {name: 'Adam  
            copy iconCopy
            const decapitalize = ([first, ...rest], upperRest = false) =>
              first.toLowerCase() +
              (upperRest ? rest.join('').toUpperCase() : rest.join(''));
            
            
            decapitalize('FooBar'); // 'fooBar'
            decapitalize('FooBar', true); // 'fOOBAR'
            
              
            Deletes an item from the forest .
            javadot img4Lines of Code : 30dot img4License : Permissive (MIT License)
            copy iconCopy
            private Node delete(Node node, T data) {
                    if (node == null) {
                        System.out.println("No such data present in BST.");
                    } else if (node.data.compareTo(data) > 0) {
                        node.left = delete(node.left, data);
                    } els  
            Initialize a forest saver .
            pythondot img5Lines of Code : 23dot img5License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def __init__(self, resource_handle, create_op, name):
                """Creates a _TreeEnsembleSavable object.
            
                Args:
                  resource_handle: handle to the decision tree ensemble variable.
                  create_op: the op to initialize the variable.
                  name: the n  
            Print the forest .
            javadot img6Lines of Code : 21dot img6License : Permissive (MIT License)
            copy iconCopy
            public void preorder() {
                    if (this.root == null) {
                        System.out.println("This BST is empty.");
                        return;
                    }
                    System.out.println("Preorder traversal of this tree is:");
                    Stack st = new Stack();
                    s  

            Community Discussions

            QUESTION

            export SHAP waterfall plot to dataframe
            Asked 2022-Apr-05 at 09:38

            I am working on a binary classification using random forest model, neural networks in which am using SHAP to explain the model predictions. I followed the tutorial and wrote the below code to get the waterfall plot shown below

            ...

            ANSWER

            Answered 2022-Apr-05 at 09:38

            If I recall correctly, you can do something like this with pandas

            Source https://stackoverflow.com/questions/71688298

            QUESTION

            Why the sum "value" isn't equal to the number of "samples" in scikit-learn RandomForestClassifier?
            Asked 2022-Mar-28 at 10:06

            I built a random forest by RandomForestClassifier and plot the decision trees. What does the parameter "value" (pointed by red arrows) mean? And why the sum of two numbers in the [] doesn't equal to the number of "samples"? I saw some other examples, the sum of two numbers in the [] equals to the number of "samples". Why in my case, it doesn't?

            ...

            ANSWER

            Answered 2022-Mar-28 at 09:03

            Nice catch.

            Although undocumented, this is due to the bootstrap sampling taking place by default in a Random Forest model (see my answer in Why is Random Forest with a single tree much better than a Decision Tree classifier? for more on the RF algorithm details and its difference from a mere "bunch" of decision trees).

            Let's see an example with the iris data:

            Source https://stackoverflow.com/questions/71639534

            QUESTION

            How to export SHAP local explanations to dataframe?
            Asked 2022-Mar-25 at 03:23

            I am working on a binary classification using random forest and trying out SHAP to explain the model predictions.

            However, I would like to convert the SHAP local explanation plots with values into a pandas dataframe for each instance.

            Is there any one here who can help me with exporting SHAP local explanations to pandas dataframe for each instance?

            I know that SHAPASH has .to_pandas() method but couldn't find anything like that in SHAP

            I tried something like below based on the SO post here but it doesn't help

            ...

            ANSWER

            Answered 2022-Mar-25 at 03:23

            If you have a model like this:

            Source https://stackoverflow.com/questions/71599628

            QUESTION

            How to plot several barplots using seaborn with respect to row?
            Asked 2022-Mar-18 at 16:35

            Let's consider the data following:

            ...

            ANSWER

            Answered 2022-Mar-18 at 10:19

            What you can use is something like:

            Source https://stackoverflow.com/questions/71525359

            QUESTION

            Finding the centroid of an xarray
            Asked 2022-Mar-13 at 18:41

            I have an xarray that represents boolean (e.g., forest/no forest) geospatial data with the dimensions x, y representing latitude and longitude, and I want the centroid coordinates.

            ...

            ANSWER

            Answered 2022-Mar-13 at 18:41

            There's nothing in xarray that interprets raster data as geometries or point collections, or to calculate the centroid of such features.

            Your approach is clever - you could certainly use weighted averaging to get a simple centroid, e.g.:

            Source https://stackoverflow.com/questions/71450348

            QUESTION

            Why does coefplot not plot all levels of interaction in Stata?
            Asked 2022-Mar-11 at 12:42

            I want to plot the coefficients from this regression as a forest plot.

            ...

            ANSWER

            Answered 2022-Mar-11 at 12:42

            coefplot automatically excludes coefficients that are flagged as "omitted" or as "base levels"---as in the case of your coefficients. To include all coefficients in the plot, you should specify the "omitted" and "baselevels" options. So it would look like something along these lines:

            Source https://stackoverflow.com/questions/71404316

            QUESTION

            Why does the output of of a linear mixed model using lme4 show one level of a factor but not another?
            Asked 2022-Feb-10 at 19:43

            I am using the lme4 package and running a linear mixed model but I am confused but the output and expect that I am encountering an error even though I do not get an error message. The basic issue is when I fit a model like lmer(Values ~ stimuli + timeperiod + scale(poly(distance.code,3,raw=FALSE))*habitat + wind.speed + (1|location.code), data=df, REML=FALSE) and then look at the results using something like summary I see all the model fixed (and random) effects as I would expect however the habitat effect is always displayed as habitatForest. Like this:

            ...

            ANSWER

            Answered 2022-Feb-10 at 19:43

            note: although your question is about the lmer() function, this answer also applies to lm() and other R functions that fit linear models.

            The way that coefficient estimates from linear models in R are presented can be confusing. To understand what's going on, you need to understand how R fits linear models when the predictor is a factor variable.

            Coefficients on factor variables in R linear models

            Before we look at factor variables, let's look at the more straightforward situation where the predictor is continuous. In your example dataset, one of the predictors is wind speed (continuous variable). The estimated coefficient is about -0.35. It's easy to interpret this: averaged across the other predictors, for every increase of 1 km/h in wind speed, your response value is predicted to decrease by 0.35.

            But what about if the predictor is a factor? A categorical variable cannot increase or decrease by 1. Instead it can take several discrete values. So what the lmer() or lm() function does by default is automatically code your factor variable as a set of so-called "dummy variables." Dummy variables are binary (they can take values of 0 or 1). If the factor variable has n levels, you need n-1 dummy variables to encode it. The reference level or control group acts like an intercept.

            In the case of your habitat variable, there are only 2 levels so you have only 1 dummy variable which will be 0 if habitat is not Forest and 1 if it is Forest. Now we can interpret the coefficient estimate of -68.8: the average value of your response is expected to be 68.8 less in forest habitat relative to the reference level of grassland habitat. You don't need a second dummy variable for grassland because you only need to estimate the one coefficient to compare the two habitats.

            If you had a third habitat, let's say wetland, there would be a second dummy variable that would be 0 if not wetland and 1 if wetland. The coefficient estimate there would be the expected difference between the value of the response variable in wetland habitat compared to grassland habitat. Grassland will be the reference level for all the coefficients.

            Default setting of reference level

            Now to directly address your question of why habitatForest is the coefficient name.

            Because by default no reference level or control group is specified, the first one in the factor level ordering becomes the reference level to which all other levels are compared. Then the coefficients are named by appending the variable's name to the name of the level being compared to the reference level. Your factor is ordered with grassland first and forest second. So the coefficient is the effect of the habitat being forest habitat, compared to the reference level, which is grassland in this case. If you switched the habitat factor level ordering, Forest would be the reference level and you would get habitatGrassland as the coefficient instead. (Note that default factor level ordering is alphabetical, so without specifically ordering the factor levels as you seem to have done, Forest would be the reference level by default).

            Incidentally, the two links you give in your question (guides to mixed models from Phillip Alday and Tufts) do in fact have the same kind of output as you are getting. For example in Alday's tutorial, the factor recipe has 3 levels: A, B, and C. There are two coefficients in the fixed effects summary, recipeB and recipeC, just as you would expect from dummy coding using A as reference level. You may be confusing the fixed effects summary with the ANOVA table presented elsewhere in his post. The ANOVA table does only have a single line for recipe which gives you the ratio of variance due to recipe (across all its levels) and the total variance. So that would only be one ratio regardless of how many levels recipe has.

            Further reading

            This is not the place for a full discussion of contrast coding in linear models in R. The dummy coding (which you may also see called one-hot encoding) I described here is just one way to do it. These resources may be helpful:

            Source https://stackoverflow.com/questions/71055840

            QUESTION

            Issue when trying to set one of div as selected in React JS
            Asked 2022-Feb-09 at 13:04

            I have following code.

            I'm trying to store a value in my state and every time the user goes to the previous step he can see what he has selected and after that he can change and move on to the next step.

            At the first step, everything works good. For example, the user selects the second text and proceeds to the next step, and when he returns to this step, he sees that the second text has already been selected...

            The problem is with the second step, I write all the same, but it doesn't work for the second step. When I am clicking on one of the div's in second step nothing was happened. There is no error. Please help me to figure out what's the problem

            Here is my code.

            App file

            ...

            ANSWER

            Answered 2022-Feb-07 at 13:06

            You use variable "ssetTerm" on second step, it's misspelled.

            Variable "setTerm" would be undefined, so it's not a function.

            Source https://stackoverflow.com/questions/71018955

            QUESTION

            How to join data from 2 datasets conditionally based on time?
            Asked 2022-Jan-06 at 18:12

            In my case, I have 2 datasets I'd like to merge. My first dataset consists of a column of locations, and a column of datetimes.

            ...

            ANSWER

            Answered 2022-Jan-06 at 18:12

            You could specify both site and datetime in the on argument of the rolling join with nearest option:

            Source https://stackoverflow.com/questions/70610682

            QUESTION

            Processing successors in dfs with Haskell
            Asked 2022-Jan-05 at 23:21

            Consider the following Python function, which, given the successors of a node, visits them and collects the results. (In practice this logic would form a part of the recursive visit function.)

            ...

            ANSWER

            Answered 2022-Jan-05 at 23:19

            Looks pretty straightforward to translate it directly:

            Source https://stackoverflow.com/questions/70600392

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install forest

            You can download it from GitHub.
            Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

            Support

            https://chainsafe.github.io/forest/
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