regexm | A Rust macro for writing regex pattern matching | Regex library

by TaKO8Ki Rust Version: v0.2.1 License: MIT

X-Ray Key Features Code Snippets(3)Community Discussions(4)Vulnerabilities Install Support

kandi X-RAY | regexm Summary

regexm is a Rust library typically used in Utilities, Regex applications. regexm has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A Rust macro for writing regex pattern matching. Usage | Examples | Docs.

Support

Quality

Security

License

Reuse

Support

regexm has a low active ecosystem.

It has 42 star(s) with 0 fork(s). There are 2 watchers for this library.

It had no major release in the last 12 months.

There are 1 open issues and 1 have been closed. On average issues are closed in 24 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of regexm is v0.2.1

Quality

regexm has 0 bugs and 0 code smells.

Security

regexm has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

regexm code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

regexm is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

regexm releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

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regexm Key Features

No Key Features are available at this moment for regexm.

regexm Examples and Code Snippets

regexm,Usage,Capture Groups

Rust

Lines of Code : 41

License : Permissive (MIT)

Copy

fn main() {
    let text1 = "2020-01-02";
    regexm::regexm!(match text1 {
        // capture groups
        captures(r"^(\d{4})-(\d{2})-(\d{2})$") => |caps| println!(
            "year: {}, month: {}, day: {}",
            caps.get(1).map_or("",

regexm,Usage,Let match

Rust

Lines of Code : 35

License : Permissive (MIT)

Copy

fn main() {
    let text2 = "foo";
    let foo = regexm::regexm!(match text2 {
        r"^\d{4}-\d{2}-\d{2}$" => "yyyy-mm-dd",
        r"^\d{4}-\d{2}$" => "yyyy-mm",
        // block
        r"^\d{4}-\d{2}-\d{2}$" => {
            let yyyy_m

regexm,Usage,Simple pattern matching

Rust

Lines of Code : 30

License : Permissive (MIT)

Copy

fn main() {
    let text1 = "2020-01-01";
    regexm::regexm!(match text1 {
        r"^\d{4}$" => println!("yyyy"),
        r"^\d{4}-\d{2}$" => println!("yyyy-mm"),
        // block
        r"^\d{4}-\d{2}-\d{2}$" => {
            let yyyy_mm

Community Discussions

Trending Discussions on regexm

JS: How to convert string to JSON Format using replace and then JSON.Parse

How to add incrementing values to string for every time string occurs in Stata?

How to generate a dummy variable in Stata based on a sub-string of an existing string variable?

Regex not working for multiple characters

QUESTION

JS: How to convert string to JSON Format using replace and then JSON.Parse

Asked 2021-Jul-11 at 06:16

I am having trouble converting my string to JSON format.

I have this specific kind of string:

...

ANSWER

Answered 2021-Jul-11 at 05:13

I made you an ugly script to fix an ugly problem... ;)

Source https://stackoverflow.com/questions/68333152

QUESTION

How to add incrementing values to string for every time string occurs in Stata?

Asked 2021-Jan-07 at 09:35

I have a string variable named talk. Let's say I want to find all instances of the word "please" in talk and, within each row, add a suffix to each "please" that contains an incrementing count of the word.

For example, if talk looks like this:

...

ANSWER

Answered 2021-Jan-07 at 09:35

* Example generated by -dataex-. To install: ssc install dataex
clear
input str71 talk
"will you please come here please do it as soon as you can if you please"
end

// Install egenmore if not installed already
* ssc install egenmore

clonevar wanted = talk

// count occurrences of "please"
egen countplease = noccur(talk), string(please)

// Loop over 1 to max number of occurrences
sum countplease, meanonly 
forval i = 1/`r(max)' {
    replace wanted = ustrregexrf(wanted, "\bplease\b", "please`i'")
}
list

     +---------------------------------------------------------------------------------------+
  1. |                                                                           talk        |
     |        will you please come here please do it as soon as you can if you please        |
     |---------------------------------------------------------------------------------------|
     |                                                                     wanted | countp~e |
     | will you please1 come here please2 do it as soon as you can if you please3 |        3 |
     +---------------------------------------------------------------------------------------+

Source https://stackoverflow.com/questions/65604864

QUESTION

How to generate a dummy variable in Stata based on a sub-string of an existing string variable?

Asked 2020-Dec-17 at 20:30

I am looking for a way to create a dummy variable which checks a variable called text against multiple given substrings like "book, buy, journey".

Now, I want to check if a observation has either book, buy, or journey in it. If there is one of these keywords found in the substring then the dummy variable should be 1, otherwise 0. A example:

...

ANSWER

Answered 2020-Dec-17 at 20:30

Using strpos may be tedious because you have to take capitalization into account, so I would use regular expressions.

Source https://stackoverflow.com/questions/65347476

QUESTION

Regex not working for multiple characters

Asked 2020-Mar-31 at 22:10

I want to search and replace special characters of markdown (viz \`*_{}[]()#+.!|-) from the given string.

I am able to make it work in C# easily since there is verbatim @ but Javascript not getting what's the issue. It seems something to do with /g , I read in another post which asked to use replaceAll but I could not find that method for string

C# version ...

ANSWER

Answered 2020-Mar-27 at 01:00

You may use

Source https://stackoverflow.com/questions/60878402

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install regexm

You can download it from GitHub.
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: