leaf | Open Machine Intelligence Framework for Hackers | Machine Learning library
kandi X-RAY | leaf Summary
kandi X-RAY | leaf Summary
Leaf is a open Machine Learning Framework for hackers to build classical, deep or hybrid machine learning applications. It was inspired by the brilliant people behind TensorFlow, Torch, Caffe, Rust and numerous research papers and brings modularity, performance and portability to deep learning. Leaf has one of the simplest APIs, is lean and tries to introduce minimal technical debt to your stack. See the [Leaf - Machine Learning for Hackers][leaf-book] book for more. Leaf is a few months old, but thanks to its architecture and Rust, it is already one of the fastest Machine Intelligence Frameworks available. See more Deep Neural Networks benchmarks on [Deep Learning Benchmarks][deep-learning-benchmarks-website]. Leaf is portable. Run it on CPUs, GPUs, and FPGAs, on machines with an OS, or on machines without one. Run it with OpenCL or CUDA. Credit goes to Collenchyma and Rust. Leaf is part of the [Autumn][autumn] Machine Intelligence Platform, which is working on making AI algorithms 100x more computational efficient. We see Leaf as the core of constructing high-performance machine intelligence applications. Leaf's design makes it easy to publish independent modules to make e.g. deep reinforcement learning, visualization and monitoring, network distribution, automated preprocessing or scaleable production deployment easily accessible for everyone. Disclaimer: Leaf is currently in an early stage of development. If you are experiencing any bugs with features that have been implemented, feel free to create a issue.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of leaf
leaf Key Features
leaf Examples and Code Snippets
Lines of Code : 10
License : No License
Copyconst HSLToRGB = (h, s, l) => {
s /= 100;
l /= 100;
const k = n => (n + h / 30) % 12;
const a = s * Math.min(l, 1 - l);
const f = n =>
l - a * Math.max(-1, Math.min(k(n) - 3, Math.min(9 - k(n), 1)));
return [255 * f(0), 255 * from datetime import timedelta, date
def daterange(start, end):
return [start + timedelta(n) for n in range(int((end - start).days))]
from datetime import date
daterange(date(2020, 10, 1), date(2020, 10, 5))
# [date(2020, 10, 1), date(2020, 10, def get_leaf(self, v):
"""
Tree structure and array storage:
Tree index:
0 -> storing priority sum
/ \
1 2
/ \ / \
3 4 5 6 -> storing priority for public void rootToLeafPaths(BinaryNode node, E[] pathList, int pathLength) {
if (node == null) return;
pathList[pathLength] = node.value;
pathLength++;
// if its a leaf node then print the list
if (node.left def _collect_leaf_level_keys(cross):
"""Collects base keys by expanding all nested crosses.
Args:
cross: A `CrossedColumn`.
Returns:
A list of strings or `CategoricalColumn` instances.
"""
leaf_level_keys = []
for k in cross.key Community Discussions
Trending Discussions on leaf
QUESTION
I have data in below format in a table .
NAME PATH A ABC A ABC:A C XYZ:C E XYZ:C:D F XYZ:C:DI am trying to get the output of only records which are leaf nodes, so basically I am looking to get output like
NAME PATH A ABC:A E XYZ:C:D F XYZ:C:DI tried doing nested substring on the PATH column but it giving me all rows.
My Trail :--
...ANSWER
Answered 2021-Jun-14 at 18:01Since you have the paths, you can use NOT EXISTS and a correlated subquery using LIKE.
QUESTION
Problem Statement: Given a binary tree and a number ‘sum’, find all paths from root-to-leaf such that the sum of all the node values of each path equals ‘sum’.
How do I calculate the time complexity of this algorithm?
What is its recurrence relation?
...ANSWER
Answered 2021-Jun-11 at 18:12This is O(N). There's no looping, and you'll visit each node exactly once.
QUESTION
This is my problem : I have a document ( let's call it root) containing an array of another documents (stick), that contain another array of another documents (leaf).
Or simply said : root{ stickChain[leaveschain1[ leaf1, leaf2],leaveschain2[ leaf1, leaf2] ]}
I have access to root _id, stick _id, or whatever it is needed to identify each document.
Basically, the best result I've come so far is, when creating my leaves documents, is to store then at the same level tha sticks, or in another word I've come to create an array of leaves in root.
I'm working in javascript and using mongoose
This is the line I've used:
...ANSWER
Answered 2021-Jun-14 at 09:31I've splitted my dument like this :
- root[stickChain _id]
- stick[leavesChain[leaf]]
Thanks to Andrey Popov for his explications
QUESTION
In an effort to create a Short, Self Contained, Correct (Compilable), Example, imagine that I want to do the following.
I have a blog website. There are two types of posts, TextPost and LinkPost. There are also two types of users, User and Guest. I would like to implement Multiple Table Inheritance with TextPost and LinkPost, by which I mean (hopefully I'm using the term correctly):
- At the model level, I will have
Post,TextPostandLinkPost.TextPostandLinkPostwill inherit fromPost. - At the database level, I will have tables for the "leaf" models of
TextPostandLinkPost, but not forPost.
Each type of Post can belong to either a User or a Guest. So we have a polymorphic belongs_to situation.
My question is how to accomplish these goals.
I tried the following, but it doesn't work.
...ANSWER
Answered 2021-Jun-12 at 04:58The names of constants look like the names of local variables, except that they begin with a capital letter.
All the built-in classes, along with the classes you define, have a corresponding global constant with the same name as the class called
class name.
So in your case, when you define User class, there's a constant class name: User, but not user, that why the error NameError (wrong constant name user) is raised.
try text_post = TextPost.create(title: 'foo', content: 'lorem ipsum', author_id: 1, author_type: 'User')
QUESTION
I want to delete the leaf nodes, the values of which are outside a given range (say [L R]). I made a solution in which I was simply traversing all the nodes and checking if my current leaf node's value is in the given range or not. If it is not then I'm removing this node.
My approach -
...ANSWER
Answered 2021-Jun-10 at 13:37Like m.raynal said, since you only want to remove leafs you can't get better than O(n).
You only can add a shortcut when all the nodes in the branch will be inside the range, something like
QUESTION
Given a new implementation of tree in Scheme using list:
...ANSWER
Answered 2021-Jun-09 at 23:06You have a reasonable-looking sequence of if tests (though using cond instead would be more idiomatic Scheme). But the values you return do not generally look correct.
The first problem I see is in your first if clause. If both trees are empty, you return '(). But according to the spec, you should be calling the succ function with that result. This may look unimportant if you use id as your continuation, but note that each recursive step builds up a more detailed succ continuation, so in general succ may be a quite impactful function.
The second if is also a problem. Again you return '(), when you are supposed to return the first conflicting subtrees. It's not clear to me what that means, but it would be reasonable to pass a pair of tree1 and tree2 to fail.
The third and fourth clause look fine. You call succ with a pair of the two leaves, as expected.
The recursive call is clearly wrong: you have mis-parenthesized calls to cons, and your lambda variable is named X but you refer to it as x. The series of cons calls doesn't really look right either, but you can experiment with that once your more pressing syntactic issues are resolved and your base cases work properly.
Lastly, you are doing a lot of low-level work with cons, car, '(), and so on. You should be using the abstract functions provided to you, such as add-subtree and (make-tree), instead of using the low-level primitives they are built on.
QUESTION
I was solving some problems on Binary tree and I got stuck in this question https://www.geeksforgeeks.org/sum-nodes-longest-path-root-leaf-node/ I am using python to solve the question I understood the logic of the solution given on the link but my question is how did the value of maxSum change in the SumOfLongRootToLeafPathUtil(root) function when nothing is returned from SumOfLongRootToLeafPath() function how is the original value of the varaible change please help ps:Please refer to the python code given in the link
...ANSWER
Answered 2021-Jun-09 at 23:20The maxSum list object passed into the SumOfLongRootToLeafPath function is mutable. So, when it is changed within that function, the SumOfLongRootToLeafPathUtil function will see the changes to it. So, there is no need to return a value.
e.g. showing mutable nature of a list
QUESTION
below I have posted the code for my drop-down menu. At the very end, there is a variable called variableToChange="".
Probably it is an easy question for the more experienced ones but I want every time I press some button to change the value of the variable. Let's say it should take the text of the button as a new value.
I guess it should be implemented somewhere into the on click part but I lack the experience here so I can't really implement it. I would really appreciate some help.
Update: Expected scenario would be: when I press the button called AA the value of variableToChange should be changed to "AA". Similarly, if I press afterwards BC it should be changed again to "BC".
...ANSWER
Answered 2021-Jun-07 at 23:27You just need to add
QUESTION
I am working on a symbolic algebra system. I'm currently looking at how to carry out polynomial addition/multiplication from a binary parse tree. I will later consider this to be a general ring.
Parsing is not relevant here -- this intended to be the output of parsing. The parse tree that is formed. If something could be improved here, I'm certainly happy to learn about that too.
I 'feel' that this tree structure could be folded/crushed, yet I'm not too clear on how to go about it. I believe I can hack something together, but as I'm still learning Haskell, I wanted to learn what the more advanced users would do.
Below is relevant code background.
My two relevant data declarations are:
...ANSWER
Answered 2021-May-03 at 15:35"Fold" has two related but distinct meanings in common parlance.
Foldas inFoldable. Viewing the datatype as a container,Foldablegives you access to the container's elements while throwing away any information about the shape of the container itself. (This is also the sense in whichlens'sFolduses the term.) Not every datatype isFoldable— only those which can be viewed as a container.- "Fold" can also mean "catamorphism", which is a technique for writing higher-order functions which reduce a structure to a summary value. Every datatype has a corresponding catamorphism, but the signature of the catamorphism depends on the datatype.
The two meanings of "fold" happen to coincide when the datatype you're talking about is [] (which partly explains the confusion over the two meanings), but in general they don't. Your Tree happens to be a suitable candidate for either type of fold, and from your question I can't quite tell which one you're after, so I'll show you how to do both.
The easiest way to write an instance of Foldable is to turn on DeriveFoldable.
QUESTION
I struggle to get the first part of number score occuring before "/" sign in every tweet as below. The problem is that sometimes the score contains decimal like "13.5" or there might be a date written as 9/11 which I do not need.So at the end I need two columns: first with extraction of first part (numerator) of score before "/" sign and in second column to have a denominator occuring after "/" sign, normally it should be always 10. There might be some digits inside the link at the end as well which I do not want to have.
In the first new column I want to get the bolded part only and in second column to catch "/10" part:
This is Bella. She hopes her smile made you smile. If not, she is also offering you her favorite monkey. 13.5/10 https://twitter.com/dog_rates/status/883482846933004288
RT @dog_rates: After so many requests, this is Bretagne. She was the last surviving 9/11 search dog, and our second ever 14/10. RIP https://twitter.com/dog_rates/status/786709082849828864
Here we have a 1949 1st generation vulpix. Enjoys sweat tea and Fox News. Cannot be phased. 5/10 https://twitter.com/dog_rates/status/786709082849828864
This is a western brown Mitsubishi terrier. Upset about leaf. Actually 2 dogs here. 7/10 would walk the shit out of https://twitter.com/dog_rates/status/786709082849828864
I tried to do it as below:
...ANSWER
Answered 2021-Jun-02 at 12:28You can match and capture both values that are followed with any amount of non-digit chars until the http string:
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