wagi | Write HTTP handlers in WebAssembly with a minimal amount

 by   deislabs Rust Version: v0.8.1 License: Apache-2.0

kandi X-RAY | wagi Summary

kandi X-RAY | wagi Summary

wagi is a Rust library typically used in Binary Executable Format, Nodejs applications. wagi has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

WARNING: This is experimental code. It is not considered production-grade by its developers, neither is it "supported" software. DeisLabs is experimenting with many WASM technologies right now. This is one of a multitude of projects (including Krustlet) designed to test the limits of WebAssembly as a cloud-based runtime.
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              wagi has a medium active ecosystem.
              It has 789 star(s) with 47 fork(s). There are 32 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 19 open issues and 55 have been closed. On average issues are closed in 50 days. There are 5 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of wagi is v0.8.1

            kandi-Quality Quality

              wagi has 0 bugs and 0 code smells.

            kandi-Security Security

              wagi has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              wagi code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              wagi is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              wagi releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            wagi Key Features

            No Key Features are available at this moment for wagi.

            wagi Examples and Code Snippets

            No Code Snippets are available at this moment for wagi.

            Community Discussions

            QUESTION

            Perform best cycle sort knowing order at the end
            Asked 2021-Feb-24 at 18:43

            We have list A that after sorting needs to look like list B and we have effort or "weight" of each number so when we are swapping in order effort will swap also ,they are connected.

            Knowing how list should look like at the end find what is the lowest effort needed to sort list A to look like lis B

            I've found answear to my question but it's in c++ code is at the bottom

            ...

            ANSWER

            Answered 2021-Feb-24 at 10:53

            I decided to sit down a bit and try tackling this problem. If I understand correctly, we are performing swaps on list in order to get them sorted like in the destination list.

            There are two types of operations we can do. Swapping two numbers to destination, which is swapping two numbers and they both land where they belong. And swapping one number to destination, which makes one of them land where it belongs and puts other in the incorrect location.

            Perfect swap should always be prioritized over one-element to destination. After writing it down on paper, I also concluded that to minimize the sum when doing one-element to desination swaps, the more you move the smallest element, the smaller the sum.

            So, the algorithm I came up with is: Find smallest weight element in target, find what should be in its place, switch them. Then remove all elements that are on their correct places from both target and origin lists(in order to find new smallest weight if previous one is already in destination), loop until the lists are empty.

            Program will use one-to-destination swaps to move the lowest weight as long as it can, and when its done, chooses next smallest element. two-way perfect swaps will solve themselves when program picks one of those elements as the smallest weight.

            I am not sure if this algorithm is perfectly correct, especially on the corner cases, but it's the best I could come up with, with the little time I have.

            Source https://stackoverflow.com/questions/66338097

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install wagi

            Here's the fastest way to try out WAGI. For details, checkout out the documentation.
            Get the latest binary release
            Unpack it tar -zxf wagi-VERSION-OS.tar.gz
            Run the wagi --help command

            Support

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