rq | Record Query - A tool for doing record analysis

 by   dflemstr Rust Version: v1.0.2 License: Apache-2.0

kandi X-RAY | rq Summary

kandi X-RAY | rq Summary

rq is a Rust library. rq has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

NOTE: rq no longer ships with query support and a Javascript engine is not included; instead, it focuses exclusively on format transformation. You can still pipe into a runtime like node.js if you need Javascript evaluation. Please see this issue to discuss introducing a new query language. This is the home of the tool called rq (record query). It's a tool that's used for performing queries on streams of records in various formats. The goal is to make ad-hoc exploration of data sets easy without having to use more heavy-weight tools like SQL/MapReduce/custom programs. rq fills a similar niche as tools like awk or sed, but works with structured (record) data instead of text. It was created with love out of the best parts of Rust, and is distributed as a dependency-free binary on many operating systems and architectures.
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            kandi-support Support

              rq has a medium active ecosystem.
              It has 2193 star(s) with 66 fork(s). There are 20 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 34 open issues and 124 have been closed. On average issues are closed in 420 days. There are 4 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of rq is v1.0.2

            kandi-Quality Quality

              rq has no bugs reported.

            kandi-Security Security

              rq has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              rq is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              rq releases are available to install and integrate.

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            rq Key Features

            No Key Features are available at this moment for rq.

            rq Examples and Code Snippets

            No Code Snippets are available at this moment for rq.

            Community Discussions

            QUESTION

            AWS DynamoDB Partition Key Design
            Asked 2021-Jun-15 at 18:09

            I read this answer, which clarified a lot of things, but I'm still confused about how I should go about designing my primary key.

            First off I want to clarify the idea of WCUs. I get that WCU is the write capacity of max 1kb per second. Does it mean that if writing a piece of data takes 0.25 seconds, I would need 4 of those to be billed 1 WCU? Or each time I write something it consumes 1 WCU, but I could also write X times within 1 second and still be billed 1 WCU?

            Usage

            I want to create a table that stores the form data for a set of gyms (95% will be waivers, the rest will be incidents reports). Most of the time, each forms will be accessed directly via its unique ID. I also want to query the forms by date, form, userId, etc..

            We can assume an average of 50k forms per gym

            Options

            • First option is straight forward: having the formId be the partition key. What I don't like about this option is that scan operations will always filter out 90% of the data (i.e. the forms from other gyms), which isn't good for RCUs.

            • Second option is that I would make the gymId the partition key, and add a sort key for the date, formId, userId. To implement this option I would need to know more about the implications of having 50k records on one partition key.

            • Third option is to have one table per gyms and have the formId as partition key. This seems to be like the best option for now, but I don't really like the idea of having a a large number of tables doing the same thing in my account.

            Is there another option? Which one of the three is better?

            Edit: I'm assuming another option would be SimpleDB?

            ...

            ANSWER

            Answered 2021-May-21 at 20:26

            For your PK design. What data does the app have when a user is going to look for a form? Does it have the GymID, userID, and formID? If so, make a compound key out of that for the PK perhaps? So your PK might look like:

            Source https://stackoverflow.com/questions/67628589

            QUESTION

            How to join pandas dataframe to itself by condition?
            Asked 2021-Jun-13 at 19:04

            I'm having a python pandas dataframe with 2 relevant columns "date" and "value", let's assume it looks like this and is ordered by date:

            ...

            ANSWER

            Answered 2021-Jun-13 at 19:04

            If you don’t have too many rows, you could generate all pairs of items and filter from there.

            Let’s start with getting the last days in the month:

            Source https://stackoverflow.com/questions/67952424

            QUESTION

            How can I use the Retrofit response outside the OnResponse function so I can return it up the recommended architecture model?
            Asked 2021-Jun-09 at 16:45

            This question follows on from How can I use the Retrofit response outside the OnResponse function?, but I'm not allowed to comment, so I'm asking it for myself here.

            I'm trying to use the Android Studio Login template because it follows the recommended architecture, but I'm having trouble returning the Result in LoginDataSource.login. The result is trapped in the Call.enqueue function and I can't get it out to return. I've reproduced the callback suggested in the above link, but that just traps the result in a new class.

            How can I access the LoggedInUser returned by my server to return to my repository?

            Original attempt: user is stuck in Call.enqueue - onResponse

            ...

            ANSWER

            Answered 2021-Jun-09 at 16:45

            I switched to Kotlin along the way, so this may not be correct Java, but it shows the process

            1. Set the user model as LiveData
            2. update the user model using .postValue()
            3. set up an observer for the user model in the viewmodel (not shown)

            Source https://stackoverflow.com/questions/67624185

            QUESTION

            Chrome WebDriverException using selenium
            Asked 2021-Jun-09 at 10:32

            Before you rate me, I must say that I read almost every answer on this site about who had my same problem, but i found no answer.

            For example there the one who asked the question accepted the first answer, but copy-pasting the code in the answer the same error was raised.

            An other example there where is linked this video, which doesn't explain much, but there no error is raised, instead of my code when I copied it from the video. (he doesn't write .exe, so probably an error would be found in his code too)

            This one has exactly my same problem, so it would be perfect, but no answer was accepted.

            Here's the last line of the error:

            ...

            ANSWER

            Answered 2021-Jun-09 at 10:10

            As I see your path is to Chrome (browser) exe file instead of chromedriver.exe used by Selenium

            Source https://stackoverflow.com/questions/67901942

            QUESTION

            conda env v venv
            Asked 2021-Jun-02 at 15:57

            To add a question to the great question and discussion here on pyenv, venv, virtualenv, and virtualenvwrapper, could someone please explain how conda environments fit into this world? When are the preferred use cases for conda environments vs the other virtual environment options?

            ...

            ANSWER

            Answered 2021-Jun-02 at 15:57

            Update 2021-0602: After researching, experiencing, and googling more I found this article. It is detailed, opinionated in what I found a helpful way, and provided everything I was looking for and more. Highly recommend. Conda is quite different from venv.

            Original Answer After researching and playing around, here's what I've found, particularly focused on the difference between conda environments and venv:

            • High level, there's not that much of a difference between conda environments and venv. There are not large performance differences, time in setup differences, replication differences, etc.
            • The decision to use one or the other should primarily by driven by personal preference, and the convention at work (e.g. if your work venv for everything, it probably makes sense to use venv and not conda environments.)

            There are some differences worth calling out:

            • Conda environments can set up environments for python and also R, so if you switch between the two conda is probably preferable so you only need to learn one set of tools/conventions.
            • Conda environments all get stored in a single folder. This has pros and cons:
            • Pro: you can easily look up all environments you've created.
            • Pro: you can re-use one environment for multiple projects (e.g. I have a "finance" environment which works well for all my finance-related projects.)
            • Con: you have to name all your environments differently, and remember the names (or look them up).
            • Con: it is more of a pain to store that environment in the project folder you've created. This means you need to remember which environment goes with which project, and you can't simply cd into the project folder and then activate the generically named 'env' that is stored in that folder.

            For the type of programming I'm doing, I find conda environments helpful. I could easily see use cases where venv is the better choice.

            Lastly, Conda is both an environments manager as well as a package manager like PIP. Useful comparison table here.

            In short, if you don't have a strong preference already, conda is more robust than venv or pip, can be combined with pip, and is probably the better default option. That said, if you already have a strong preference it means you likely already know how to do what you want, so it's unlikely to be worth it to change.

            Source https://stackoverflow.com/questions/67065725

            QUESTION

            Styled-components theme with react-native testing-library
            Asked 2021-Jun-01 at 21:15

            I've been stuck for a while trying to figure out exactly what I'm doing wrong here and I feel like I've tried every solution that I've found and it doesn't work. To describe what's happening, I made the most simple component I could to show what was happening.

            Here's my theme

            ...

            ANSWER

            Answered 2021-Jun-01 at 21:15

            Just in case anyone is wondering what the answer is. The solution to the issue I was having was changing

            Source https://stackoverflow.com/questions/67570754

            QUESTION

            Can't throttle IO on cgroup. Says "No such device" when device exists. What could be wrong?
            Asked 2021-Jun-01 at 17:25

            ANSWER

            Answered 2021-Jun-01 at 17:25

            The error occurs because the only way to throttle IO using cgroups version 1 is to use a device that is physical. The major and minor version numbers I used above are for a partition. You need to pick the major and minor numbers for the physical device that HOLDS the partition.

            Source https://stackoverflow.com/questions/67747634

            QUESTION

            Can't get the HTTPS response using Volley
            Asked 2021-Jun-01 at 04:10

            I've been trying to learn about Volley and hence I made a simple app which has a connect button and when the button is pressed it displays the response as a TOAST but when I press the button I cannot neither of the TOAST messages(response TOAST and error TOAST)

            Here's the kotlin code:

            ...

            ANSWER

            Answered 2021-Jun-01 at 04:10

            QUESTION

            Django GraphQL API with JWT authentication implementation still allows for unauthenticated requests from Postman get data. How do I fix this?
            Asked 2021-May-30 at 06:24

            I've built a Django API that uses django-graphql-auth and django-graphql-jwt packages to implement authentication. I followed the package's documentation and got everything to work and everything is working from my Angular UI. The only issue is that even requests made from Postman without the Authorization header, are able to fetch the data from the graphql API.

            This is my Django project's settings.py

            ...

            ANSWER

            Answered 2021-May-30 at 06:24

            You should add the login_required decorator to your queries and mutations resolvers. Like this:

            Source https://stackoverflow.com/questions/67739693

            QUESTION

            Heroku Procfile with multiple workers
            Asked 2021-May-27 at 12:51

            I have an app with 1 web dyno, 7 background queues, and 1 clock. I want to use the Heroku Standard 1x plan as it includes unlimited background workers (and the number of queues might increase further in the future). When I deploy my app, the procfile doesn't appear to provision the way I expected. Three dynos are shown, and it looks like I have to purchase an additional Standard 1x dyno for each worker/clock.

            Procfile:

            ...

            ANSWER

            Answered 2021-May-27 at 12:51

            Firstly, there was an error in how I structured the procfile. Each "worker" should be named differently. I thought the term "worker" held some special meaning for Heroku provisioning; it doesn't. So Procfile should look something like this:

            Source https://stackoverflow.com/questions/67671338

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install rq

            You can download it from GitHub.
            Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.

            Support

            Installation — How to install rq.Tutorial — Learn rq from scratch.Protobuf — Configure Protobuf specifics.Development — Contribute to rq.
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            https://github.com/dflemstr/rq.git

          • CLI

            gh repo clone dflemstr/rq

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            git@github.com:dflemstr/rq.git

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