hummingbird | Experimental language

by dirk Rust Version: v0.1 License: BSD-3-Clause

X-Ray Key Features Code Snippets(1)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | hummingbird Summary

hummingbird is a Rust library. hummingbird has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

This is an experimental language. For the previous JavaScript implementation which compiled to JavaScript or binary-via-LLVM check out the legacy-2015 branch.

Support

Quality

Security

License

Reuse

Support

hummingbird has a low active ecosystem.

It has 53 star(s) with 4 fork(s). There are 8 watchers for this library.

It had no major release in the last 12 months.

There are 0 open issues and 17 have been closed. On average issues are closed in 699 days. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of hummingbird is v0.1

Quality

hummingbird has 0 bugs and 0 code smells.

Security

hummingbird has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

hummingbird code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

hummingbird is licensed under the BSD-3-Clause License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

hummingbird releases are available to install and integrate.

Installation instructions, examples and code snippets are available.

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hummingbird Key Features

No Key Features are available at this moment for hummingbird.

hummingbird Examples and Code Snippets

Hummingbird,Getting started on macOS

Rust

Lines of Code : 7

License : Permissive (BSD-3-Clause)

Copy

# Install LLVM v8
brew install llvm@8

# Set up your environment so that the llvm-sys crate can discover Homebrew's
# installation of llvm@8.
source script/env-mac

cargo build
cargo test

Community Discussions

Trending Discussions on hummingbird

Add multiple filtering keywords to a single blog in a gallery?

Scrapy: Unable to get data

Python/Pandas: How do I replace specific values of a Pandas Data Frame based on individual id?

RainLab.Blog Post List: List Sub-Categories under a specific Top-Level Category

Adding supervisor and other info into bookdown pdf_book

OS Error in the listdir function of os module

Button Placement on split screen design

Python: nested dictionary problem: trying to run a 'if' command to print out a string

Display Only More Than One Unique Customer/Address Per Truck Number

How to extract key value from a JS object through a common function?

QUESTION

Add multiple filtering keywords to a single blog in a gallery?

Asked 2022-Jan-03 at 16:39

I am planning to add a filtering feature to my website blogs. For this, each blog post will be associated with a keyword. Selecting these keywords will show/filter all the blogs associated with that specific keyword category.

In the code below, I have separated my blogs into 3 categories (Forest, Birds and Sea). However, I also want some of the blogs to be associated with multiple keywords (two or three), see the 'Forest Birds' section in the snippet below. If someone can help me with how to do it, that would be great.

...

ANSWER

Answered 2022-Jan-02 at 18:43

Here's what you can change, on line 198:

Source https://stackoverflow.com/questions/70558659

QUESTION

Scrapy: Unable to get data

Asked 2021-Aug-17 at 07:59

I'm trying to scrape this website www.zillow.com by using Scrapy. I'm trying to import addresses from a CSV file and trying to search by it. But getting error. Here is my code.

csv_read.py ...

ANSWER

Answered 2021-Aug-16 at 16:56

It's the response parsing methond, your should use response.xpath() but not response.body

Source https://stackoverflow.com/questions/68793709

QUESTION

Python/Pandas: How do I replace specific values of a Pandas Data Frame based on individual id?

Asked 2021-Jul-07 at 17:10

I have a long Pandas dataset that contains a column called 'id' and another column called 'species', among other columns. I have to perform a change on the 'species' column, based on specific values of the 'id' column.

For example, if the 'id' is '5555555' (as a string), then I want that the 'species' value change its current value 'dove' (also a string) to 'hummingbird'. So far I have been using the method:

df.loc[df["id"] == '5555555', "species"] = 'hummingbird'

Here is short sample data frame:

...

ANSWER

Answered 2021-Jul-07 at 17:10

Use isin

Source https://stackoverflow.com/questions/68278771

QUESTION

RainLab.Blog Post List: List Sub-Categories under a specific Top-Level Category

Asked 2021-Jun-07 at 16:04

I'm working on an October CMS project which use a blog where I need to seperate blog posts in two major categories. When listing blog posts using the RainLab.Blog plugin's Post List component, I need to list categories that are sub-categories under a specific top-level category and exclude other categories.

In the TWIG template, I want to iterate through and list out the categories that belong to "Birds" and not "Sealife".

In the default Post List component, categories are listed like this:

...

ANSWER

Answered 2021-Jun-07 at 16:04

If it's totally fine to hardcode category then you can simply compare categories parent's slug or id to hardcoded value.

Here I am using the slug to compare parent, you can also use id it's totally up to you.

Source https://stackoverflow.com/questions/67866066

QUESTION

Adding supervisor and other info into bookdown pdf_book

Asked 2021-May-05 at 09:02

I want to include my supervisor's name, course name etc. for my paper written in bookdown. I specifically want this information to be in different lines. So far I have tried this in the yaml:

...

ANSWER

Answered 2021-May-05 at 09:02

Using a "line block" should do the trick:

Source https://stackoverflow.com/questions/67397354

QUESTION

OS Error in the listdir function of os module

Asked 2021-Apr-14 at 08:14

I am learning the os module of python, where I wrote the following code to try out the functions of the module.

Input:

...

ANSWER

Answered 2021-Apr-14 at 06:34

In python, the backslash is used as an ignore symbol. So after each backslash add another backslash

Source https://stackoverflow.com/questions/67086612

QUESTION

Button Placement on split screen design

Asked 2020-Aug-22 at 14:14

Im playing around with bootstrap and i've come up against something I am struggling to find an answer to.

I want to put a 'Login' on the bottom right of the screen, near the fold. Below is my code:

...

ANSWER

Answered 2020-Aug-22 at 14:14

Source https://stackoverflow.com/questions/63537039

QUESTION

Python: nested dictionary problem: trying to run a 'if' command to print out a string

Asked 2020-Jul-19 at 06:01

I am trying to do following 2 things for this nested dictionary:

If a bird is aggressive, print out a string advising us to 'cover our heads' using the 'actions' list in this print statement.
If a bird is endangered, print out a string advising us to 'back away', also using the actions list in this print statement.

Here's what I have so far. Any help is much appreciated!:

...

ANSWER

Answered 2020-Jul-19 at 04:49

final_actions={}
for key, value in rarebirds.items():
    if final_actions.get(key)==None:
        final_actions[key]=[]
    if 'Aggressive' in value and value.get("Aggressive")==True:
        final_actions[key].append(actions[1])
    if 'Endangered' in value and value.get("Endangered")==True:
        final_actions[key].append(actions[0])
    if ('Aggressive' in value and value.get("Aggressive")==False) and ('Endangered' in value and value.get("Endangered")==False):
        final_actions[key].append(actions[2])
print(final_actions)

Source https://stackoverflow.com/questions/62976274

QUESTION

Display Only More Than One Unique Customer/Address Per Truck Number

Asked 2020-Apr-29 at 15:40

Been working on a project in which a report will generated from the SQL Query. I wish to display all Shipments (based on unique automatic truck ID) which contain any combination of:

Unique Customers (based on Customer Number, more than one Customer Number per shipment)
Unique Addresses (based on defined Address Field, more than one unique Address per shipment)

The output should look like this when the code runs correct:

...

ANSWER

Answered 2020-Apr-29 at 15:40

SELECT * FROM (SELECT DISTINCT shp.shipmentID
                                                       , ven.CustomerCode
                                                       , ven.CustomerName
                                                       , ads.FirstAddress
                                                       , ads.SecondAddress
                                                       , ads.ThirdAddress
                                                       , ads.City
                                                       , ads.State
                                                       , ads.Zip
                                                       , CASE WHEN(ads.Country LIKE 'US') THEN N'USA' ELSE 'CANADA' END AS Country
                                                       , COUNT (shp.shipmentID) OVER (PARTITION BY shipmentID ORDER BY shp.shpID) AS cntshpID


                        FROM dbo.OrderItems AS ori
                        JOIN dbo.OrderLineProducts AS olns ON olns.olnID = ori.olnID
                        JOIN dbo.OrderLines AS oln ON oln.olnID = olns.olnID
                        JOIN dbo.Orders AS ord ON oln.ordID = ord.ordID
                        JOIN dbo.VendorCustomer AS ven ON ven.venID = ord.venID
                        JOIN dbo.OrderAddresses AS oa ON oa.ordID = ord.ordID
                        JOIN dbo.Address AS ads ON ads.addID = oa.addID
                        JOIN dbo.AddressType AS adst ON adst.atcID = ads.atcID
                                                       AND adst.atcAddressTypeCode = N'SHIP'
                        JOIN dbo.OrderItemShipments AS shpo ON ori.itmID = shpo.itmID
                                                       AND ori.itmIDInstance = shpo.itmIDInstance
                                                       AND ori.olnID = shpo.olnID
                                                       AND ori.olnIDInstance = shpo.olnIDInstance
                        JOIN dbo.Shipments AS shp ON shp.shpID = shpo.shipmentID
                        WHERE shpo.shpID = shp.shipmentID

                        GROUP BY shp.shipmentID
                                         , ven.CustomerCode
                                         , ven.CustomerName
                                         , ads.FirstAddress
                                         , ads.SecondAddress
                                         , ads.ThirdAddress
                                         , ads.City
                                         , ads.State
                                         , ads.aZip
                                         , ads.Country) AS bb

WHERE bb.cntshpID > 1

ORDER BY shpID ASC

Source https://stackoverflow.com/questions/61488423

QUESTION

How to extract key value from a JS object through a common function?

Asked 2020-Jan-01 at 11:15

I try to extract a value from JS object.

Here is my data -

...

ANSWER

Answered 2020-Jan-01 at 08:21

You don't need a for loop. If you know the structure of your object, then you can simple do the following:

Source https://stackoverflow.com/questions/59550869

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install hummingbird

When starting work in a new shell:.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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