moore | A hardware compiler based on LLHD and CIRCT

 by   fabianschuiki Rust Version: v0.14.0 License: Apache-2.0

kandi X-RAY | moore Summary

kandi X-RAY | moore Summary

moore is a Rust library. moore has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Moore is a compiler for hardware description languages that outputs llhd assembly, with a focus on usability, clear error reporting, and completeness. Its goal is to act as a frontend for hardware design tools such as synthesizers, linters, or logical equivalence checkers.
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            kandi-support Support

              moore has a low active ecosystem.
              It has 207 star(s) with 24 fork(s). There are 17 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 80 open issues and 143 have been closed. On average issues are closed in 69 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of moore is v0.14.0

            kandi-Quality Quality

              moore has no bugs reported.

            kandi-Security Security

              moore has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              moore is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              moore releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.

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            moore Key Features

            No Key Features are available at this moment for moore.

            moore Examples and Code Snippets

            Citing TPOT
            pypidot img1Lines of Code : 38dot img1no licencesLicense : No License
            copy iconCopy
            @article{le2020scaling,
              title={Scaling tree-based automated machine learning to biomedical big data with a feature set selector},
              author={Le, Trang T and Fu, Weixuan and Moore, Jason H},
              journal={Bioinformatics},
              volume={36},
              number={1},
                
            Pin a tensor .
            pythondot img2Lines of Code : 126dot img2License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def pinv(a, rcond=None, validate_args=False, name=None):
              """Compute the Moore-Penrose pseudo-inverse of one or more matrices.
            
              Calculate the [generalized inverse of a matrix](
              https://en.wikipedia.org/wiki/Moore%E2%80%93Penrose_inverse) using i  

            Community Discussions

            QUESTION

            Find byte sequence in typed array without writing a Boyer-Moore implementation
            Asked 2021-May-31 at 09:30

            I have to find some markers (text sequences) in files loaded by the user. Like 85% of those files will be UTF-8 encoded text, but there will be binary files too. The markers are right now text sequences but in the future regular expressions may be used (probably not for the binary files, but I don't know yet).

            I have the file contents as ArrayBuffer arrays, and I have to find the markers within that data. I have the following options:

            1. Use a typed array (UInt8Array) and TextDecoder('ascii'), and use String.indexOf() on the decoded data. I don't like this because at least in principle this can duplicate the memory used by the file contents after TextDecoder.decode(). But it's easy and pretty straightforward. Works with the binary files, too, because the markers will be ASCII bytes within the binary data.
            2. Use a typed array (UInt8Array, again) and write my own version of Boyer-Moore or other fast string searching function, to find the sequence of bytes I need. Fast, memory optimal... but I'd rather not write yet another Boyer-Moore implementation or copy one. And remember, in the future I may want to use regular expressions so...
            3. Read the files as text rather than ArrayBuffer, since like 85% of them will be UTF-8 encoded text, and try to do something ad-hoc with the few real binary files that I'll encounter. That means I can use regular expressions or String.indexOf() from the start, no big deal, but on the other hand handling the binary files after finding the markers can be a problem because the raw data will be converted to text.

            Since in the future the use of regular expressions is almost guaranteed, my only clear path is the first one, but I'm quite worried about memory usage, since some of the files can be large (about 100 MB or so), or use the third option and see how to get the raw bytes after they were converted to text...

            Any suggestions? Am I missing something obvious?

            Thanks in advance!

            ...

            ANSWER

            Answered 2021-May-31 at 09:30

            You could decode your ArrayBuffer to text as a stream.
            There is a TextDecoderStream,, but it is still not supported in FF and it would require to copy your ArrayBuffers in Blobs so they can be streamed.

            So instead in your case where you have ArrayBuffers, you can use the stream option of the TextDecoder.decode() method and read your ArrayBuffer by small chunks:

            Source https://stackoverflow.com/questions/67662028

            QUESTION

            Why aren't my images starting on a new line
            Asked 2021-May-20 at 16:56

            When I resize the screen my images only respond to a certain extent and then they stop moving. I'm still learning this obviously, so I would appreciate any help in understanding how this all works. My next step will be to reposition the nav from the side to the top on a mobile screen, but I think I understand how to do that.

            https://jsfiddle.net/161020/nwkfy6dq/3/

            ...

            ANSWER

            Answered 2021-May-20 at 16:56

            You can achieve responsiveness using the flexbox layout. Looking at you codebase, you need to put all your gallery images inside a div which will serve as a container. Something like the below.

            Source https://stackoverflow.com/questions/67573600

            QUESTION

            How to get the latest rows in BigQuery
            Asked 2021-May-14 at 04:50

            In BigQuery, how can I get rows based on the latest value of timestamp field?

            For example, I have this table.

            first_name last_name use_auto login_at James Davis true 2021-05-13 02:00:00 UTC James Moore true 2021-05-13 02:00:01 UTC James Green true 2021-05-13 02:00:02 UTC Edward Green false 2021-05-13 03:00:00 UTC Edward Wilson false 2021-05-13 03:00:01 UTC James Davis false 2021-05-13 03:00:00 UTC James Moore false 2021-05-13 03:00:01 UTC James Green false 2021-05-13 03:00:02 UTC Edward Green true 2021-05-13 02:00:00 UTC Edward Wilson true 2021-05-13 02:00:00 UTC

            I'd like to get the result after query like this,

            first_name last_name use_auto login_at Edward Green false 2021-05-13 03:00:00 UTC Edward Wilson false 2021-05-13 03:00:01 UTC James Davis false 2021-05-13 03:00:00 UTC James Moore false 2021-05-13 03:00:01 UTC James Green false 2021-05-13 03:00:02 UTC

            Please let me know what query should I use.

            ...

            ANSWER

            Answered 2021-May-14 at 04:50

            Following up on the Gordon's answer: add limit 1 to reduce memory consumption and increase scalability:

            Source https://stackoverflow.com/questions/67517275

            QUESTION

            Stablized cellular automation
            Asked 2021-Apr-29 at 12:20

            I'm working on cellular automation simulation. Rule are the following:

            • Each cell interacts with its Moore's neighborhood to update its value.
            • The cell is in any infinite-dimensional grid.
            • The cell may have a randomized initial value.
            • Rules are stable, after a certain iteration, they will converge to a uniform state.

            It's not necessary for a certain programming language so we only have basic datatypes i.e. bool, int, their's n-dimensional array, etc. in this algorithm.

            I have an initial value of any cell that I can load into the memory whenever I wanted. Is there any algorithm to calculate its stabilized value without looping the whole infinite grid?

            To be specific, what I'm working on is a rule B5678/S45678 2 dimensional life-like cellular automation.

            ...

            ANSWER

            Answered 2021-Apr-29 at 12:20

            Is there any algorithm to calculate [a particular cell's] stabilized value without looping the whole infinite grid?

            For this particular CA rule, yes, sort of. In particular, you can almost surely determine the final stable state of any given cell on the lattice by inspecting only a finite number of surrounding cells. However, the number of cells you may need to inspect can be arbitrarily large.

            First, let me note that the life-like cellular automaton rule code "B5678/S45678" denotes a "majority vote" rule where the state of each cell on the next time step is the current majority state among the nine cells comprised of itself and its eight neighbors.

            This rule happens to satisfy a monotonicity property: flipping the initial state of one or more cells from "off" to "on" cannot cause the future state of any cell to flip from "on" to "off", or vice versa. In other words, the future state of the lattice is a monotone increasing function of the current state.

            This monotonicity has some important consequences. In particular, it implies that if you have a cluster of cells in the "on" state that is surrounded on all sides by cells in the "off" state (or vice versa), and if this cluster is currently stable (in the sense that applying the CA update rule once will not lead to any cells in the cluster changing state), then it will in fact be forever stable regardless of what else happens elsewhere on the lattice.

            This is because the only way that events elsewhere could possibly affect the cluster is by changing the state of one or more cells surrounding it. And since all those surrounding cells are in the "off" state while the cells in the cluster are in the "on" state, monotonicity ensures that changing the state of any surrounding cells to "on" cannot cause the future state of any cell in the cluster to change to "off". (Of course the same argument also applies mutatis mutandis to clusters of "off" cells surrounded by "on" cells.)

            (In fact, you don't really need the cluster of "on" cells to be actually surrounded by "off" cells, or vice versa — all that's required for stability is that the cluster would be stable even if all cells surrounding it were in the opposite state.)

            Thus, in general, to determine the final state of a cell it suffices to simulate the time evolution of its surrounding cells until it becomes part of such a stable cluster.

            One way to do this in (almost surely) finite time is to treat the sequence of 2D lattices at successive time steps as forming a 3D lattice of stacked 2D slices, and to calculate successive "pyramid-shaped" sections of this 3D lattice consisting of the states of the central cell up to time step n, its neighbors up to time step n − 1, their neighbors up to time step n − 2, and so on. At regular intervals, examine each layer of this growing pyramid to see if any of them includes a stable cluster (in the sense described above) containing the central cells.

            Assuming that the central cell in fact eventually becomes part of such a stable finite cluster (which almost all cells on a randomly initialized lattice eventually do under this rule; proof left as exercise!), this method will eventually find that cluster. However, depending on the initial states of the surrounding cells, such stabilization could take an arbitrarily long time and the final state of the cell might depend on the states of other cells arbitrarily far away.

            For example, let's assume that the cell we're interested in happens to be located in a region of the lattice where the initial cell states, just by chance, are arranged like the squares on a checkerboard: the four orthogonal neighbors of each cell are in the opposite state, while the four diagonal neighbors are all in the same state as the central cell. Clearly such a checkerboard arrangement is locally stable, since each cell is (barely!) in the majority among its neighbors, but any deviations in either direction from this precarious balance around the edges of the checkerboard will propagate as a chain reaction throughout it. Thus the final stable state of any particular cell on the checkerboard will depend on the state of cells surrounding the checkerboard region, which could be arbitrarily far away.

            Source https://stackoverflow.com/questions/67297755

            QUESTION

            how to display cities in one dropdown based on selected state in other dropdown using json data in angular ionic?
            Asked 2021-Apr-27 at 16:44

            following are my files for html, .ts and json . As json data was very extensive therefore i have just added a few states and their cities. my 1st dropdown is showing all states. Now I want to match my 1st dropdown's selected value of state with a key "state" in "cities" object in my json file so i can populate 2nd dropdown with cities relevant to that state. and I want to do this in function "getCitiesForSelectedState". please help me find solution for this.

            //.ts file

            ...

            ANSWER

            Answered 2021-Apr-27 at 16:44

            You can do it with the $event parameter. Make sure to compare your values safely.

            If your value is not in the right type or has spaces or unwanted chars, this c.state == val might not work.

            You can use the trim function to compare your value safely: c.state.trim() == val.trim()

            HTML

            Source https://stackoverflow.com/questions/67284495

            QUESTION

            How would u create this function and perform it inside an array?
            Asked 2021-Mar-25 at 13:21
            1. I have an array

            2. I am trying to create a function with two parameters that would return a string value or expression based on the condition such as the year band member joined and left

            3.i am trying to run this function without any loop and in a newbie manner inside an array

            ...

            ANSWER

            Answered 2021-Mar-25 at 13:21

            The typical technique is to use Array.prototype.map -

            Source https://stackoverflow.com/questions/66799862

            QUESTION

            composite github action, automatically cd into actions directory?
            Asked 2021-Mar-15 at 18:11

            I am trying to setup a github actions bot that uses composite to build when the action runs. Notably, this isn't required, and I know that ncc would also achieve the same thing, but I'm curious if it's possible to make this work in a sustainable way.

            For some context, I'm trying to run my alita-moore/EIP-Bot private action with the yaml script being...

            ...

            ANSWER

            Answered 2021-Mar-15 at 18:11

            You can use ${{github.action_path}} for the path of the directory containing the action definition file action.yaml:

            Source https://stackoverflow.com/questions/66630437

            QUESTION

            C++ yard.h header getting acreage programmatically
            Asked 2021-Mar-02 at 21:09

            I am relatively new to C++ and it is essentially just a filler class for my college. I am stuck on this yard program. I need to create a header with the requirements below:

            following 5 public functions in the Yard class: getWidth(), setWidth(), getLength(), setLength(), and getAcres()

            Validate the width and length to ensure they are not negative

            FYI: There are 43560 square feet in an acre.

            NOTE: I have yet to learn anything about headers , classes, objects.

            here is the premade code given to me from teacher:

            ...

            ANSWER

            Answered 2021-Mar-02 at 21:09

            So, here's a yard.h that will answer the teacher's brief.

            Source https://stackoverflow.com/questions/66445847

            QUESTION

            Find AD user information with DisplayName
            Asked 2021-Mar-01 at 10:38

            I have a list of displaynames and I need to get their AD informations.

            ...

            ANSWER

            Answered 2021-Feb-27 at 11:31

            The basic question here is how to account for middle names.

            PowerShell 5 has some AI-powered cmdlets.

            Here, I will quote an example from the documentation.

            Example 2: Simplify format of a string

            Source https://stackoverflow.com/questions/66387814

            QUESTION

            How to get SECMARK work on Ubuntu 18.04 or centOS 7.7
            Asked 2021-Mar-01 at 08:39

            I have a question about SECMARK, a package labeling function in iptables.

            I tried to config based on Paul Moore's guide(a very old 14 yrs old blog), but it turns out an error on both ubuntu 18.04 and centOS 7.7:

            command: iptables -t mangle -A INPUT -p tcp --src 192.168.0.16 --dport 22 -j SECMARK --selctx system_u:object_r:foo_ssh_packet_t:s0

            Ubuntu: No chain/target/match by that name

            centOS: invalid argument. Run 'dmesg' for more information (P.S. I ran dmesg on centOS but get nothing worthwhile)

            I also tried to config the "security" table by change "-t mangle" to "-t security", and I got the same output.

            iptables -t security -A INPUT -p tcp --src 192.168.0.16 --dport 22 -j SECMARK --selctx system_u:object_r:foo_ssh_packet_t:s0

            ...

            ANSWER

            Answered 2021-Mar-01 at 08:39

            As there is no one knows the answer and I somehow figured out how to do it by myself, I think I'd better leave something to help other people.

            The reason for No chain/target/match by that name

            SECMARK and SELinux are highly coupled, You must define the SELinux Context first, then you can use it in iptables/nftables rules.

            The way to define an SELinux is to create a user-defined SELinux ruleset, aka .te file, then compile and install it on your machine. After that, your iptables/nftables may proceed normally with the command above.

            The relationship between OS types and SECMARK

            Ubuntu is one of the most popular Linux dist nowadays but noted that Ubuntu DO NOT Pre-install SELinux, and AppArmor did not support SECMARK Until Jan 2019, so if you want to use SECMARK on Ubuntu, uninstalling apparmor and install SELinux is probably worthwhile.

            And if you want to use SECMARK between systems, please be advised that you need to install policies on both systems.

            Ref

            SECMARK Support code(did not merge till today)

            From the mailing list: [apparmor] Apparmor netfiter support?

            Source https://stackoverflow.com/questions/66302183

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install moore

            You need a working Rust installation to build Moore. The project also depends on the CIRCT project and transitively on MLIR and LLVM. To get a working binary, you generally want to ensure you have the circt and circt/llvm submodules checked out:.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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