to_string | Rust : make those primitives into strings
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QUESTION
I have a code sample, and I'd you to review this and tell me if my understanding is correct. I am learning C++, and so I apologize if these questions are rudimentary. I have read about how C++ handles memory management, but I haven't found practical examples. I am trying to write some myself.
Code Sample:
...ANSWER
Answered 2021-Jun-12 at 21:54The move semantics creates new objects. It is not a copy or assignment, it is a move-constructor that is invoked. Thus, if you call move(innerVector)
you actually create a new vector object as entry in containerOfVectors. This automatically contains the content/data of the original innerVector
at the moment you make the call. Afterwards, the innerVector is empty, and whatever you do with it will not affect the new object inside containerOfVectors. There is no link between those two distinct objects. The memory address of an object created with move-construction is certainly always different from its original object.
This fully explains the output of your example. With any other data type inside the vector, also structs, this will be just the same.
QUESTION
I have an application where I am receiving a string with some repetitive characters. I am receiving input as a String. How to remove the characters from specific index?
main.rs
...ANSWER
Answered 2021-Jun-12 at 12:41String indexing works only with bytes, thus you need to find an index for the appropriate byte slice like this:
QUESTION
Say I am building a record type:
...ANSWER
Answered 2021-Jun-06 at 18:50Regarding the last error, it's because OCaml requires a 'stable path' to types inside modules so it can refer to them. A stable path is a named path to a type, e.g. Fruit.t
.
By contrast, StrEnum(struct type t = ... end).t
is not a stable path because the type t
is referencing a type t
in the module literal which does not have a name.
Long story short, you basically can't skip defining the variant module separately. But it's simple to do it in two steps:
QUESTION
My code won't compile and I don't know how to fix it. It looks like the problem is maybe with the "=" operator but I'm not sure. I'm trying to apply a given function on the elements of the sorted list in order to get a different sorted list, but it says that I'm using different arguments than the expected. My code looks like-
...ANSWER
Answered 2021-Jun-12 at 11:19Your copy assignment operator is bringing you the trouble.
The LinkedList apply(A func)
function returns (by value) a LinkedList
, which then in turn is used in this line, in main.cpp
...
QUESTION
I am reading through the Rust book and doing the optinal exercise along the way. I've finished the chapter 8 (Common Collections) and am trying the last exercise. The exercise instructions are:
Using a hash map and vectors, create a text interface to allow a user to add employee names to a department in a company. For example, “Add Sally to Engineering” or “Add Amir to Sales.” Then let the user retrieve a list of all people in a department or all people in the company by department, sorted alphabetically.
What I want my program to do is firstly ask the user if they want to add a new employee, if no, the program ends else it allows them to continously add an employee until the user declines to add any more.
I've chosen to simply start with the initial user prompt asking if they want to add a new employee. I start with an empty String
for the user input, once the user enters their response there is a while loop that repeats until the user enters a valid response ([Y/n]
). Since the condition for the while loop is when the response is not equal to "y"
or "n"
I expected correct responses to skip the while loop but instead the while loop is always entered and never exited no matter what. Since I'm new to Rust I'm not sure if there some obvious or idiosyncratic reason for this behaviour. I'll also add that I remove whitespace (incl. \n
) from the response and make the response lowercase in the while loop condition, all of which can be seen in my code below.
ANSWER
Answered 2021-Jun-11 at 18:34Check your while conditions (it is always true) , and what you wrote
"loop is when the response is not equal to "y" or "n""
means in pseudo code
NOT (answer = "y" OR answer="n")
QUESTION
I'm trying to print a Sorted List and it looks like the list itself is correct- by printing the inner results, but when I try to print the whole list it shows some weird symbols and crashes. Where am I wrong? This is my main with the function I'm calling in "apply":
...ANSWER
Answered 2021-Jun-11 at 14:08This line:
QUESTION
My dataframe df
is:
ANSWER
Answered 2021-Jun-11 at 11:55get the party who is top 2 in 2010 elections:
QUESTION
I have a function that takes in a Vec
value. I want to use this function on values contained inside my_ref
, so I need to extract a Vec
out of a Rc>>
.
I thought I could do this by dereferencing a borrow of my my_ref
, just like I would for a Rc>>
or Rc>>
value:
ANSWER
Answered 2021-Jun-10 at 22:46RefCell::borrow
returns a reference, not an owned value, that's why you having such an error. I can name two different solution for that problem.
Rc
to exclusively-owned type
Rc::try_unwrap
is able to check, whether there's other references to the data. If it's the only one, it can be safely converted to the inner type. Then, an owned RefCell
can be converted into its inner via into_inner
function.
QUESTION
My dataframe df
is:
ANSWER
Answered 2021-Jun-10 at 20:55I believe the one liner df.groupby(["Election Year"]).max().reset_index()['Election Year', 'Party']
solves your problem
QUESTION
I am trying to send a post request in C++ using socket programming, but the request doesnt seem to get executed. I am unsure of whether or not the syntax of the POST request is correct or not. Here is the request that I am sending
...ANSWER
Answered 2021-Jun-10 at 21:07There are a lot of problems with your code.
You are not checking
gethostbyname()
for failure (you should usegetaddrinfo()
instead), or validating thathost->h_addrtype
isAF_INET
only.You are not checking
socket()
,connect()
, orsend()
for failures, either.You are not accounting for the possibility that
send()
may not be able to send the entire request in one call. You need to call it in a loop until the entire request has been sent.Your
while
loop doesn't account fordata_len
at all, and thus will go out of bounds of thebuffer
and likely crash when it eventually tries to access invalid memory.And frankly, your parser is just wholly inadequate for a viable HTTP client.
Most importantly, you are expecting the server to close the connection at the end of the response, but you are requesting
HTTP/1.1
, which keeps the connection open by default, and you are not requesting the connection be closed. Sorecv()
will end up blocking after the response is done (at least for awhile, until the server times out), so you won't see yourresponse
string being printed to the console. Try adding"Connection: close\r\n"
to your request headers, or else have the request ask forHTTP/1.0
instead.
Try this:
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