lazy-static.rs | small macro for defining lazy evaluated static variables

Any string that you can reference with a &'static str must live until the program terminates. So yes, the way that you have it set up, you would never be able to delete any of the string data that is put into the HashMap. Moreover, outside of the lazy_static block you will also never be able to add anything to the HashMap. This is because outside the lazy_static block you will only be able to obtain a shared reference to the HashMap, and you cannot perform mutation on a HashMap with only a shared reference (i.e., a &HashMap).

If you want to be able to modify the HashMap, you can do so by wrapping it in a Mutex and using owned strings instead of &'static str:

bincode::serialize is not const fn so it can not be guaranteed to be executed at compile time. That means there is no guarantee that the compiler will replace the call.