spark-xml | XML data source for Spark SQL and DataFrames
kandi X-RAY | spark-xml Summary
kandi X-RAY | spark-xml Summary
XML data source for Spark SQL and DataFrames
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QUESTION
I'm trying to parse a wide, nested XML file into a DataFrame using the spark-xml library.
Here is an abbreviated schema definition (XSD):
...ANSWER
Answered 2021-May-19 at 05:57Columns in XSD are required or not null & Some of the columns in XML file is null to match XSD & XML file content, change schema from nullable=false
to nullable=true
Try following code.
QUESTION
I'm trying to parse a very simple XML string column using spark-xml, but I only manage to receive null
values, even when the XML is correctly populated.
The XSD that I'm using to parse the xml is:
...ANSWER
Answered 2021-May-18 at 13:34At the end what opened my eyes was reading the part of the spark-xml documentation that mentions:
Path to an XSD file that is used to validate the XML for each row individually
This mean that the schema matching is done through each row and not through the entire XML, in that case the schema for my example needs to be something like the following:
QUESTION
How to transform values below from multiple XML files to spark data frame :
- attribute
Id0
fromLevel_0
Date
/Value
fromLevel_4
Required output:
...ANSWER
Answered 2021-Jan-01 at 15:51You can use Level_0
as the rowTag, and explode the relevant arrays/structs:
QUESTION
In python, bytes string can be simply saved to single xml file:
...ANSWER
Answered 2021-Jan-22 at 20:25Don't be misled by databricks spark-xml docs, as they lead to use uncompressed XML file as an input. This is very inefficient and much faster is to download XMLs directly to spark dataframe. Databricks xml-pyspark version doesn't include it but there is a workaround:
QUESTION
I'm new with Apache Spark Structured Streaming. I'm trying to read some events from Event Hub (in XML format) and trying to create new Spark DF from the nested XML.
Im using the code example described in https://github.com/databricks/spark-xml and in batch mode is running perfectly but not in Structured Spark Streaming.
Code chunk of spark-xml Github library
...ANSWER
Answered 2021-Jan-21 at 19:54There is nothing wrong with your code if it works in batch mode.
It is important to not only convert the source into a stream (by using readStream
and load
) but it is also required to convert the sink part into a stream.
The error message you are getting is just reminding you to also look into the sink part. Your Dataframe final_df
is actually a streaming Dataframe which has to be started through start
.
The Structured Streaming Guide gives you a good overview on all available Output Sinks and the easiest would be to print the result to the console.
To summarize, you need to add the following to your program:
QUESTION
I am ingesting Large XML file and generating individual JSON according to the XML Element, I am using SPARK-XML in azure databricks. Code to create the json file as
...ANSWER
Answered 2020-Oct-13 at 13:06Unfortunately, it's not possible to control the file name using standard spark library, but you can use Hadoop API for managing file system - save output in temporary directory and then move file to the requested path.
Spark uses Hadoop File Format, which requires data to be partitioned - that's why you have
part-0000
files.
In order to change filename, try to add something like this in your code:
In Scala it will look like:
QUESTION
I am using ADLS Gen2, from a Databricks notebook trying to process the file using 'abfss' path. I am able to read parquet files just fine but when I try to load the XML files, I am getting the error the configuration is not found - Configuration property xxx.dfs.core.windows.net not found.
I haven't tried mounting the file but trying to understand if it's a known limitation with XML files, as I am able to read the parquet files just fine.
Here is my XML libraries config com.databricks:spark-xml_2.11:0.9.0
I tried a couple of things per the other articles but still getting the same error.
- Added a new scope to see if it's a scope issue in the Databricks Workspace.
- Tried adding configuration spark.conf.set("fs.azure.account.key.xxxxx.dfs.core.windows.net", "xxxx==")
ANSWER
Answered 2020-Aug-16 at 12:37I summarize the solution as below.
The package com.databricks:spark-xml
seems using RDD API to read xml file. When we use using the RDD API to access Azure Data Lake Storage Gen2, wecannot access Hadoop configuration options set using spark.conf.set(...)
. So we should update the code as spark._jsc.hadoopConfiguration().set("fs.azure.account.key.xxxxx.dfs.core.windows.net", "xxxx==")
. For more details, please refer to here.
Besides, you aslo can mount Azure Data Lake Storage Gen2 as file system in Azure databricks.
QUESTION
I have a scenario where I am reading from my hive table and creating a spark dataframe. I want to generate an xml string from the output of dataframe and save it in a new dataframe (as xml string) , rather than writing it to a file in HDFS to create an xml. Please tell me if this can be done using databricks spark-xml.
...ANSWER
Answered 2020-Aug-04 at 15:40You cannot do this with the spark-xml lib, but you can reuse the write out part from it to create your own solution for an XmlRdd: https://github.com/databricks/spark-xml/blob/master/src/main/scala/com/databricks/spark/xml/util/XmlFile.scala
You can find in line 80 exactly this.
QUESTION
from pyspark import SparkContext
from pyspark.sql import SparkSession
from pyspark.sql.types import *
import os
os.environ['PYSPARK_SUBMIT_ARGS'] = '--packages com.databricks:spark-xml_2.10:0.4.1 pyspark-shell'
conf = SparkConf().setAppName('Stackoverflow')
sc = SparkContext(master="local", appName="test")
sc.setLogLevel("Error")
spark = SparkSession.builder.getOrCreate()
df=spark.read.format("com.databricks.spark.xml").option("rowTag","Transaction").load("C:/Users/Rajaraman/Desktop/task/data/transactions.xml")
...ANSWER
Answered 2020-Jun-20 at 09:32You need to import libraries referenced in the code
Add this line to import the referenced package
QUESTION
I am working with xml structure something like below:
...ANSWER
Answered 2020-Jun-10 at 19:13You can explode the applicants in a first step and then select the required columns from each applicant in a second step:
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