rho | A self documenting DSL built on http4s
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rho Examples and Code Snippets
def pollard_rho(
num: int,
seed: int = 2,
step: int = 1,
attempts: int = 3,
) -> int | None:
"""
Use Pollard's Rho algorithm to return a nontrivial factor of ``num``.
The returned factor may be composite and require fur
def __init__(
self,
learning_rate: float,
rho: float,
momentum: float,
epsilon: float,
use_gradient_accumulation: bool = True,
clip_weight_min: Optional[float] = None,
clip_weight_max: Optional[float] =
Community Discussions
Trending Discussions on rho
QUESTION
I am new to julia. If a run a program written in julia as
sachin@localhost:$ julia mettis.jl
then it runs sucessfully, without printing anything, though one print statement is in it.
And Secondly If run it as by going in julia:
...ANSWER
Answered 2022-Apr-11 at 11:40There is nothing special about a function called main
in Julia and defining a function is different from calling it. Consequently a file mettis.jl
with the following code:
QUESTION
I have defined the following function
...ANSWER
Answered 2022-Mar-28 at 20:30It turns out the complicated code of laplacian_2D_array
can be simplified as the following implementation:
QUESTION
From the title, I have a shader where my a floating point number is apparently not NaN, is apparently not Ininity, and is apparently not equal to, greater than, or lesser than 0. What?
The function that generates this floating point number is this:
...ANSWER
Answered 2022-Mar-24 at 08:55This appears to be the result of some aggressive optimization by the compiler. With some algebra, you can determine that as of this line:
QUESTION
ANSWER
Answered 2022-Mar-14 at 16:23You can use the "filled" version of each shape (use for example ggpubr::show_point_shapes()
to see a list), so here 22, 21, 24 and 23.
QUESTION
I am trying to match the estimate of random effects from R version 3.5.3 (lme4 1.1-18-1) to R version 4.1.1 (lme4 1.1-27.1). However, there is a small difference of random effects between these two versions when there is singular fit. I'm fine with singularity warnings, but it is puzzling that different versions of R/lme4 produce slightly different results.
The following scripts are from R version 3.5.3 (lme4 1.1-18-1) and R version 4.1.1 (lme4 1.1-27.1) with the dataset Arabidopsis from lme4.
...ANSWER
Answered 2022-Mar-07 at 17:34This is a hard problem to solve in general, and even a fairly hard problem to solve in specific cases.
I think the difference arose between version 1.1.27.1 and 1.1.28, probably from this NEWS item:
construction of interacting factors (e.g. when f1:f2 or f1/f2 occur in random effects terms) is now more efficient for partially crossed designs (doesn't try to create all combinations of f1 and f2) (GH #635 and #636)
My guess is that this changes the ordering of the components in the Z matrix, which in turn means that results of various linear algebra operations are not identical (e.g. floating point arithmetic is not associative, so while binary addition is commutative (a + b == b + a
), left-to-right evaluation of a sum may not be the same as right-to-left evaluation ((a+b) + c != a + (b+c)
) ...)
My attempt at reproducing the problem uses the same version of R ("under development 2022-02-25 r81818") and compares only lme4
package versions 1.18.1 with 1.1.28.9000 (development); any upstream packages such as Rcpp
, RcppEigen
, Matrix
use the same versions. (I had to backport a few changes from the development version of lme4
to 1.1.18.1 to get it to install under the most recent version of R, but I don't think any of those modifications would affect numerical results.)
I did the comparison by installing different versions of the lme4
package before running the code in a fresh R session. My results differed between versions 1.1.18.1 and 1.1.28 less than yours did (both fits were singular, and the relative differences in the theta
estimates were of the order of 2e-7 — still greater than your desired 1e-8 tolerance but much smaller than 1e-4 ...)
The results from 1.1.18.1 and 1.1.27.1 were identical.
- Q1: Why are your results more different between versions than mine?
- in general/anecdotally, numerical results on Windows are slightly more unstable/differ more from other platforms
- there are more differences between your two test platforms than among mine: R version, upstream packages (
Matrix
/Rcpp
/RcppEigen
/minqa
), possibly the compiler versions and settings used to build everything [all of which could make a difference]
- Q2: how should one deal with this kind of problem?
- as a minor frame challenge, why (other than not understanding what's going on, which is a perfectly legitimate reason to be concerned) does this worry you? The differences in the results are way smaller than the magnitude of statistical uncertainty, and differences this large are also likely to occur across different platforms (OS/compiler version/etc.) even for otherwise identical environments (versions of R,
lme4
, and other packages). - you could revert to version 1.1.27.1 for now ...
- I do take the differences between 1.1.27.1 as a bug, of sorts — at the very least it's an undocumented change in the package. If it were sufficiently high-priority I could investigate the code changes described above and see if there is a way to fix the problems they addressed without breaking backward compatibility (in theory this should be possible, but it could be annoyingly difficult ...)
- as a minor frame challenge, why (other than not understanding what's going on, which is a perfectly legitimate reason to be concerned) does this worry you? The differences in the results are way smaller than the magnitude of statistical uncertainty, and differences this large are also likely to occur across different platforms (OS/compiler version/etc.) even for otherwise identical environments (versions of R,
QUESTION
As mentioned above, the function below works, however its very slow. I am very interested in using faster/optimised numpy (or other) vectorized alternatives. I have not posted the entire script here due to it being too large.
My specific question is - are there suitable numpy (or other) functions that I can use to 1) reduce run time and 2) reduce code volume of this function, specifically the for loop?
Edit: mass, temp, U and dpdh are functions that carry out simple algebraic calculations and return constants
...ANSWER
Answered 2022-Feb-24 at 13:43For improving the speed, you can see Numba, which is useable if you use NumPy a lot but not every code can be used with Numba. Apart from that, the formulation of the equation system is confusing. You are solving 3 equations and adding the result to a single dydt
list by 3 elements each. You can simply create three lists, solve each equation and add them to their respective list. For this, you need to re-write my_system
as:
QUESTION
I am working with a data set that is comprised of three columns: patient ID (ID), TIME, and cervical dilation (CD). I apologize in advance for being unable to share my data, as it is confidential, but I have included a sample table below. Each patient CD was recorded in time as they progressed through labor. Time is measured in hours and CD can be 1-10cm. The number of time points/CD scores vary from patient to patient. In this model t is set in reverse, where 10 cm (fully dilated) is set as t=0 for all patients. This is done so that all patients can be aligned at time of full dilation. My dataset has no NA's and all patients have 2 or more time points.
ID TIME CD 1 0 10 1 3 8 1 6 5 2 0 10 2 1 9 2 4 7 2 9 4I know for this problem I need to use nonlinear mixed effects model. I know from literature that the function that defines this biological process is modeled best as a biexponential function of the form CD= Cexp(-At)+(10-C)exp(-Lt), where A is the active labor rate [cm/hour], L is the latent labor rate [cm/hour], C is the diameter of the cervix [cm] at the point where the patient transitions from latent to active labor, and t is time in hours.
I have tried using both nlmer() and nlme() to fit this data, and I have used both the self-start biexponential function SSbiexp() as well as created my own function and its deriv(). Each parameter C, A, and L should have a random effect based on ID. Previous work has shown that C~4.98cm, A~0.41cm/hr, and L~0.07cm/hr. When using the SSbiexp(), there is a term for the second exponential component that is labeled here as C2, but should be the same as the (10-C) component of my self-made biexponential function.
When using nlme() with SSbiexp() I receive the error: Singularity in backsolve at level 0, block 1
...ANSWER
Answered 2022-Feb-23 at 20:36Here's how far I've gotten:
- the exponential rates are supposed to be specified as logs of the rates (to make sure that the rates themselves stay positive, i.e. that we have exponential decay curves rather than growth curves)
- I simplified the model significantly, taking out the random effects in
T1
andT2
.
QUESTION
I need your help! I am plotting a heatmap and I do not have any error, but I do not know how to resolve it because I haven't seen any similar post. I have 2 dataframes:
DF1:
...ANSWER
Answered 2022-Feb-21 at 13:27You need to convert DF2
into long format too. Then you can use the p values as the labels by passing DF2
as an argument to a different geom_text
call. You can also map the fontface
aesthetic to the the p values to get the bold font for "significant*" p values. Finally, you need to nudge the p value labels down a bit.
QUESTION
I'm trying to categorize the type of jigsaw puzzle pieces (number of heads, if it is a border or a corner...) by analyzing their contours.
The approach I'm trying to follow is analyzing this type of plot (from this paper) that "unwinds" the cartesian coordinates of the contours of the puzzle piece by converting it to polar coordinates; however I'm not able to replicate it.
I've tried with:
...ANSWER
Answered 2022-Feb-19 at 17:31Find the center of the tile:
QUESTION
I have this image for a treeline crop. I need to find the general direction in which the crop is aligned. I'm trying to get the Hough lines of the image, and then find the mode of distribution of angles.
I've been following this tutorialon crop lines, however in that one, the crop lines are sparse. Here they are densely pack, and after grayscaling, blurring, and using canny edge detection, this is what i get
...ANSWER
Answered 2022-Jan-02 at 14:10You can use a 2D FFT to find the general direction in which the crop is aligned (as proposed by mozway in the comments). The idea is that the general direction can be easily extracted from centred beaming rays appearing in the magnitude spectrum when the input contains many lines in the same direction. You can find more information about how it works in this previous post. It works directly with the input image, but it is better to apply the Gaussian + Canny filters.
Here is the interesting part of the magnitude spectrum of the filtered gray image:
The main beaming ray can be easily seen. You can extract its angle by iterating over many lines with an increasing angle and sum the magnitude values on each line as in the following figure:
Here is the magnitude sum of each line plotted against the angle (in radian) of the line:
Based on that, you just need to find the angle that maximize the computed sum.
Here is the resulting code:
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