amora | semantic search engine where anyone can define anything
kandi X-RAY | amora Summary
kandi X-RAY | amora Summary
Amora is a semantic search engine where anyone can define anything anywhere - a technical prowess that is achieved by relying on semantic web technologies. Everything in Amora is Linked Data or in other words a distributed key-value store where every key-value pair is associated with an unique identifier in form of an URI. Amora was created to provide an IDE and tooling research platform whose ambitious goal it is to supersede existing tools by a new being. So far, there is nothing here yet - this is not even alpha level yet. There is only documentation on how to use it by myself.
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QUESTION
Since this morning I have been struggling with the below code. I'm still new to python. I hope to be able to join you guys in helping people, but for now, I'm the newbie.
I created a class product with a static variable to store all of them.
...ANSWER
Answered 2018-Jul-23 at 16:41First convert your list of dictionaries to a pandas DataFrame:
QUESTION
I am trying to do some string matching using the Levenshtein algorithm for closest words on businesses. (In python but language won't make a huge difference)
An example query would be
search = 'bna' lat & lon are close by the result I am looking for.
There is a pub right by the latitude and longitude called BNA Brewing Co. by searching BNA my hopes would be that that shows up first (as bna == bna)
I have tried two different way
...ANSWER
Answered 2017-Feb-09 at 20:33Recall that Levenshtein distances count the number of substitutions, additions and deletions required to transform one string into another. Because of this, they often are minimized when comparing strings of similar length (because even if a lot of substitutions are required, you don't have to add or remove a bunch of characters). You can see this playing out in your second example where your best outputs all are the same length as your search string (len("bna") == len("A&W")
).
If your search string is always going to be a single word, then your idea to calculate the distance for each word in the string is a good one since each word is more likely to be a similar length to your search string. However, currently you are doing a case sensitive comparison which means that editdistance.eval('bna', 'BNA') == 3
which I'm guessing you don't want.
try:
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