scalajson | ScalaJSON - JSON for Scala , currently contains minimal AST | Parser library

by mdedetrich Scala Version: Current License: BSD-3-Clause

X-Ray Key Features Code Snippets(2)Community Discussions(4)Vulnerabilities Install Support

kandi X-RAY | scalajson Summary

scalajson is a Scala library typically used in Utilities, Parser applications. scalajson has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

ScalaJSON library, currently provides two minimal implementations of JSON AST, one that is designed for typical use and another that is designed for performance/corner cases.

Support

Quality

Security

License

Reuse

Support

scalajson has a low active ecosystem.

It has 55 star(s) with 8 fork(s). There are 11 watchers for this library.

It had no major release in the last 6 months.

There are 7 open issues and 25 have been closed. On average issues are closed in 81 days. There are 2 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of scalajson is current.

Quality

scalajson has 0 bugs and 0 code smells.

Security

scalajson has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

scalajson code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

scalajson is licensed under the BSD-3-Clause License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

scalajson releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

It has 4300 lines of code, 454 functions and 47 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

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scalajson Key Features

No Key Features are available at this moment for scalajson.

scalajson Examples and Code Snippets

ScalaJSON,jNumberRegex

Scala

Lines of Code : 6

License : Permissive (BSD-3-Clause)

Copy

import scalajson.jNumberRegex

"3535353" match {
  case jNumberRegex(_ *) => true
  case _ => false
}

ScalaJSON,Usage

Scala

Lines of Code : 2

License : Permissive (BSD-3-Clause)

Copy

"org.scala-lang.platform" %% "scalajson" % "1.0.0-M4"

"org.scala-lang.platform" %%% "scalajson" % "1.0.0-M4"

Community Discussions

Trending Discussions on scalajson

Scala: accessing case class fields when returning a base class after a match statement

Building jsonpath with Scala Play framework

How can I parse the json body from from an Akka Client-Side HttpResponse

Scala: How serialize data in JSON?

QUESTION

Scala: accessing case class fields when returning a base class after a match statement

Asked 2021-Jul-02 at 13:25

I'm currently trying to create a class and subclasses that encapsulate various configuration aspects (provided in json) for a data pipeline; I'm still very much learning scala as well. I'm using the Play framework library in order to parse the json string input - https://www.playframework.com/documentation/2.8.x/ScalaJson

I have some code that currently works, but there are several aspects of it that feel wrong, and this does not feel like the correct approach.

The workflow for the application needs to take a json string, parse and validate it against various similar but slightly different structures, and then make the values accessible for other bits of downstream processing (e.g. if the file type is a csv file, set some config thus, if it's a json file do this instead); but it's important to note that this is a dynamic process. This seemed to me to be a perfect use case for case classes, but I have a feeling I've misunderstood their use.

So I have a sealed (in order to make sure that all matches are known) abstract class FileConfig, and currently two subclasses, DelimitedConfig and JsonConfig. The DelimitedConfig class also makes use of an additional case class DelimitedFileTypeDetails, which is essentially the main difference between the two at this point, but there will be other deviations added as I continue; and I also have companion objects for all three classes in order to take advantage of the play framework format method:

...

ANSWER

Answered 2021-Jul-02 at 13:25

If every FileConfig will have a member of a given type (e.g. fileType), you can put that member in FileConfig:

Source https://stackoverflow.com/questions/68225604

QUESTION

Building jsonpath with Scala Play framework

Asked 2020-Jun-04 at 19:05

I have a simple json structure like this:

...

ANSWER

Answered 2020-Jun-04 at 19:05

Analogous doesn't mean identical, and JsPath doesn't offer conditional path.

Source https://stackoverflow.com/questions/62198261

QUESTION

How can I parse the json body from from an Akka Client-Side HttpResponse

Asked 2020-May-10 at 07:15

I'm using Akka's HTTP client library to request a json, and I want to use Play Framework's play-json to parse the json. After I get Akka's HttpResponse, I don't know how to parse the json from the response body, and I don't know how to pass the json to another function in the onComplete directive. Instead, I get this error

...

ANSWER

Answered 2020-May-10 at 07:15

The main problem is that Unmarshal returns a Future so you need to process the data inside the Future to get the String value.

If you want to keep the result rather than just print it, use tranformWith on the initial result rather than onComplete:

Source https://stackoverflow.com/questions/61708021

QUESTION

Scala: How serialize data in JSON?

Asked 2020-Feb-21 at 11:12

I recently started to learn Scala. I need an EASY way to SERIALIZE my data in Json. Below I will give an example of data. I tried several popular libraries: GSON, Play JSON, Circe, but did not get the result! GSON does not know how to work with Option (eg Option [String]), in Play JSON and Circe they need to describe serialization and deserialization of an abstract class (I don’t know how to get around this).

...

ANSWER

Answered 2020-Feb-21 at 11:12

You need to create a companion object for your case class as:

Source https://stackoverflow.com/questions/60316286

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install scalajson

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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