scala-util | Scala stuff | Functional Programming library

by metamx Scala Version: Current License: Non-SPDX

X-Ray Key Features Code Snippets Community Discussions(2)Vulnerabilities Install Support

kandi X-RAY | scala-util Summary

scala-util is a Scala library typically used in Programming Style, Functional Programming applications. scala-util has no bugs, it has no vulnerabilities and it has low support. However scala-util has a Non-SPDX License. You can download it from GitHub.

Scala stuff

Support

Quality

Security

License

Reuse

Support

scala-util has a low active ecosystem.

It has 18 star(s) with 8 fork(s). There are 46 watchers for this library.

It had no major release in the last 6 months.

scala-util has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of scala-util is current.

Quality

scala-util has no bugs reported.

Security

scala-util has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

scala-util has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

scala-util releases are not available. You will need to build from source code and install.

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scala-util Key Features

No Key Features are available at this moment for scala-util.

scala-util Examples and Code Snippets

No Code Snippets are available at this moment for scala-util.

Community Discussions

Trending Discussions on scala-util

How to manage DB connection in Scala using functional programming style?

How hashing algorithm works in Dataset.repartition

QUESTION

How to manage DB connection in Scala using functional programming style?

Asked 2018-Jul-10 at 18:28

I have a piece of Scala code using DB connection:

...

ANSWER

Answered 2018-Jul-10 at 14:31

Just pull the connection outside of the try:

Source https://stackoverflow.com/questions/51263449

QUESTION

How hashing algorithm works in Dataset.repartition

Asked 2018-Feb-16 at 18:21

I was doing a basic repartion on dataset. I have data like below in file test.csv

...

ANSWER

Answered 2018-Feb-16 at 18:21

The mistake you've made, is the assumption that hashing is done on a Scala string. In practice Spark hashes on unsafe byte array directly.

So the expression is equivalent to

Source https://stackoverflow.com/questions/48827867

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install scala-util

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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