sjq | Command-line JSON processor with Scala syntax | JSON Processing library

 by   yannick-cw Scala Version: 0.0.4 License: No License

kandi X-RAY | sjq Summary

kandi X-RAY | sjq Summary

sjq is a Scala library typically used in Utilities, JSON Processing applications. sjq has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Use Scala syntax to modify json fast and however you want from the Commandline. Just pass code to modify the root case class. sjq parses the json to a case class and allows editing and modifying it in any way.
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              sjq has a low active ecosystem.
              It has 52 star(s) with 3 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              sjq has no issues reported. There are 40 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of sjq is 0.0.4

            kandi-Quality Quality

              sjq has no bugs reported.

            kandi-Security Security

              sjq has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              sjq does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              sjq releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of sjq
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            sjq Key Features

            No Key Features are available at this moment for sjq.

            sjq Examples and Code Snippets

            sjq,About
            Scaladot img1Lines of Code : 16dot img1no licencesLicense : No License
            copy iconCopy
            sjq -a 'root.subclass.copy(name = root.subclass.name + "Jo")' -j '{ "subclass": { "name": "Ho", "ids": [22, 23, 24]  }}'
            {
              "name" : "HoJo",
              "ids" : [
                22.0,
                23.0,
                24.0
              ]
            }
            
            curl https://www.holidaycheck.de/svc/search-api/search/mall\  
            sjq,Usage
            Scaladot img2Lines of Code : 6dot img2no licencesLicense : No License
            copy iconCopy
            sjq -a 'root.subclass.ids.filter(id => id > 22)' -j '{ "subclass": { "name": "Ho", "ids": [22, 23, 24]  }}'
            ## Results in 
            [
              23.0,
              24.0
            ]
              
            sjq,Usage,Alternatively pipe input
            Scaladot img3Lines of Code : 1dot img3no licencesLicense : No License
            copy iconCopy
            echo '{ "subclass": { "name": "Ho", "ids": [22, 23, 24]  }}' | sjq -a 'root.subclass.ids.filter(id => id > 22)'
              

            Community Discussions

            QUESTION

            swift4: none of textfields in my scene are editable
            Asked 2019-Apr-30 at 03:57

            I have a Scene in my Storyboard which all of its field are not editable during application run-time.

            Note. I've checked that all text field and all its parent userInteractionEnabled be true and due to this question (My TextField is not editable) but it did not help. I have other scenes like this that work without using any delegates or such things and their textfields are still editable.

            I did comment out everything inside its related view controller however it did not change this situation. I've brought its XML code here for your reference may be you can find anything which lead to this situation.

            Changes which I made to my Scene was: Puting all items in a nested view inside a StackView and some if its constraints + migrating from Swift3 to Swift4.

            ...

            ANSWER

            Answered 2019-Apr-30 at 03:57

            I have pasted your storyboard in my Test project and tried debugging this issue. It is found that when the view between ScrollView and StackView ( highlighted in RED in below screenshot) is removed and StackView is directly placed inside Container ScrollView, the textFields become clickable.

            Your storyboard as given:

            After removing view inside Container Scroll view and moving StackView directly under Container ScrollView.

            Simulator screenshot after removing that middle view

            Source https://stackoverflow.com/questions/55904212

            QUESTION

            how to use a derived type for sync.Map
            Asked 2017-Nov-08 at 13:02

            My goal is to have a custom type the one I could derive and add extra methods, for example, when using a map this works:

            ...

            ANSWER

            Answered 2017-Nov-08 at 13:02

            The Go Programming Language Specification

            Struct types

            A struct is a sequence of named elements, called fields, each of which has a name and a type. Field names may be specified explicitly (IdentifierList) or implicitly (EmbeddedField). Within a struct, non-blank field names must be unique.

            Source https://stackoverflow.com/questions/47178816

            QUESTION

            Error with API Key
            Asked 2017-Jun-21 at 20:37

            Hello everyone I'm developing an app that in one of the activities it displays a map and a textView. But when i run that activity the app stops running and throw this message:

            ...

            ANSWER

            Answered 2017-Jun-21 at 19:26

            You need to add the line:

            Source https://stackoverflow.com/questions/44684614

            QUESTION

            How to combine 2 tables and insert values into a 3rd table
            Asked 2017-Apr-12 at 21:25

            I have 2 tables formatted the following ways listed below...

            T1

            ...

            ANSWER

            Answered 2017-Apr-10 at 18:37

            I am going to go out on a "guess" here with (THE WHERE CLAUSE IS A GUESS ONLY)

            Source https://stackoverflow.com/questions/43329557

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install sjq

            Or download the executable from the releases.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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