sshrc | bring your .bashrc, .vimrc, etc. with you when you ssh | Wiki library
kandi X-RAY | sshrc Summary
kandi X-RAY | sshrc Summary
sshrc is a Shell library typically used in Web Site, Wiki applications. sshrc has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.
This repository is only a mirror of the original sshrc code which was written by Russell Stewart. I created this mirror when the original repository disappeared from GitHub.
This repository is only a mirror of the original sshrc code which was written by Russell Stewart. I created this mirror when the original repository disappeared from GitHub.
Support
Quality
Security
License
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Support
sshrc has a low active ecosystem.
It has 19 star(s) with 15 fork(s). There are 1 watchers for this library.
It had no major release in the last 6 months.
sshrc has no issues reported. There are no pull requests.
It has a neutral sentiment in the developer community.
The latest version of sshrc is current.
Quality
sshrc has 0 bugs and 0 code smells.
Security
sshrc has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
sshrc code analysis shows 0 unresolved vulnerabilities.
There are 0 security hotspots that need review.
License
sshrc is licensed under the MIT License. This license is Permissive.
Permissive licenses have the least restrictions, and you can use them in most projects.
Reuse
sshrc releases are not available. You will need to build from source code and install.
Installation instructions are not available. Examples and code snippets are available.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of sshrc
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of sshrc
sshrc Key Features
No Key Features are available at this moment for sshrc.
sshrc Examples and Code Snippets
No Code Snippets are available at this moment for sshrc.
Community Discussions
Trending Discussions on sshrc
QUESTION
How to use STDOUT inside /etc/ssh/sshrc without breaking SCP
Asked 2021-Jan-05 at 15:51
I want to call a program when any SSH user logs in that prints a welcome message. I did this by editing the /etc/ssh/sshrc
file:
ANSWER
Answered 2021-Jan-05 at 15:51Use test
to check $SSH_TTY
(final solution in this link):
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install sshrc
You can download it from GitHub.
Support
For any new features, suggestions and bugs create an issue on GitHub.
If you have any questions check and ask questions on community page Stack Overflow .
Find more information at:
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