MAGNETAR | Device Performance Optimizer — Aims To Provide | Performance Testing library

by Kyliekyler Shell Version: v19.2.2 License: Non-SPDX

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | MAGNETAR Summary

MAGNETAR is a Shell library typically used in Testing, Performance Testing, Unity applications. MAGNETAR has no bugs, it has no vulnerabilities and it has low support. However MAGNETAR has a Non-SPDX License. You can download it from GitHub.

Device Performance Optimizer — Aims To Provide An Optimal Experience At Every Usage Scenario.

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Quality

Security

License

Reuse

Support

MAGNETAR has a low active ecosystem.

It has 152 star(s) with 51 fork(s). There are 15 watchers for this library.

It had no major release in the last 12 months.

There are 0 open issues and 9 have been closed. On average issues are closed in 10 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of MAGNETAR is v19.2.2

Quality

MAGNETAR has 0 bugs and 0 code smells.

Security

MAGNETAR has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

MAGNETAR code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

MAGNETAR has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

MAGNETAR releases are available to install and integrate.

Installation instructions are available. Examples and code snippets are not available.

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MAGNETAR Key Features

No Key Features are available at this moment for MAGNETAR.

MAGNETAR Examples and Code Snippets

No Code Snippets are available at this moment for MAGNETAR.

Community Discussions

Trending Discussions on MAGNETAR

To split by date and event columns

QUESTION

To split by date and event columns

Asked 2021-Apr-25 at 14:59

I am trying to split by date and event columns. It is impossible to search for ". " some lines contain multiple sentences ending with ". " Also, some lines don't start with dates. The idea of the script was to use a regexp to find lines starting with the fragment "one or two numbers, space, letters, period, space" and then replace "point, space" with a rare character, for example, "@". If the line does not start with this fragment, then add "@" to the beginning. Then this array can be easily divided into two parts by this symbol ("@") and written to the sheet.

Unfortunately, something went wrong today. I came across the fact that match(re) is always null. I ask for help in composing the correct regular expression and solving the problem.

Original text:

1 June. Astronomers report narrowing down the source of Fast Radio Bursts (FRBs). It may now plausibly include "compact-object mergers and magnetars arising from normal core collapse supernovae".[3][4]

The existence of quark cores in neutron stars is confirmed by Finnish researchers.[5][6][7]

3 June. Researchers show that compared to rural populations urban red foxes (pictured) in London are mirroring patterns of domestication similar to domesticated dogs, as they adapt to their city environment.[21]

The discovery of the oldest and largest structure in the Maya region, a 3,000-year-old pyramid-topped platform Aguada Fénix, with LiDAR technology is reported.

17 June. Physicists at the XENON dark matter research facility report an excess of 53 events, which may hint at the existence of hypothetical Solar axions.

Desired result:

Code:

...

ANSWER

Answered 2021-Apr-25 at 14:59

function breakapart() {
  const ms = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']
  const ss = SpreadsheetApp.getActive();
  const sh = ss.getSheetByName('Sheet1');//Data Sheet
  const osh = ss.getSheetByName('Sheet2');//Output Sheet
  osh.clearContents();
  const vs = sh.getRange(1, 1, sh.getLastRow(), sh.getLastColumn()).getDisplayValues().flat();
  let oA = [];
  vs.forEach(p => {
    let f = p.split(/[. ]/);
    if (!isNaN(f[0]) && ms.includes(f[1])) {
      let s = p.slice(0, p.indexOf('.'));
      let t = p.slice(p.indexOf('.')+2);
      oA.push([s, t]);
    } else {
      oA.push(['',p]);
    }
  });
  osh.getRange(1,1,oA.length,oA[0].length).setValues(oA);
}

Source https://stackoverflow.com/questions/67246500

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

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Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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