JSONPretty | JSON pretty print shell | JSON Processing library

by cute Shell Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | JSONPretty Summary

JSONPretty is a Shell library typically used in Utilities, JSON Processing applications. JSONPretty has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

JSON pretty print shell, is based on .

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Quality

Security

License

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Support

JSONPretty has a low active ecosystem.

It has 14 star(s) with 4 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

JSONPretty has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of JSONPretty is current.

Quality

JSONPretty has 0 bugs and 0 code smells.

Security

JSONPretty has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

JSONPretty code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

JSONPretty does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

JSONPretty releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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JSONPretty Key Features

No Key Features are available at this moment for JSONPretty.

JSONPretty Examples and Code Snippets

No Code Snippets are available at this moment for JSONPretty.

Community Discussions

Trending Discussions on JSONPretty

hcl, json, go : how can I iterate JSON?

QUESTION

hcl, json, go : how can I iterate JSON?

Asked 2020-May-05 at 07:42

Problem: I’m trying to iterate through JSON-content and present the result like key,value pairs.

I've written some code that read hcl-files, these are then decoded with hcldec.Decode, and the result is then converted to JSON. These hcl-files define source and target for the application like this:

source.hcl:

...

ANSWER

Answered 2020-May-05 at 07:42

The solution for me was to create a struct for the target and not use the target spec.

Source https://stackoverflow.com/questions/61496581

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install JSONPretty

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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