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QUESTION
My code should print the number of all the words replaced from Z's to Y's, using a while loop.
...ANSWER
Answered 2021-Jun-15 at 17:18Use sum
and count
with list comprehension
QUESTION
zebra_owner(Owner) :-
houses(Hs),
member(h(Owner,zebra,_,_,_), Hs).
water_drinker(Drinker) :-
houses(Hs),
member(h(Drinker,_,_,water,_), Hs).
houses(Hs) :-
length(Hs, 5), % 1
member(h(english,_,_,_,red), Hs), % 2
member(h(spanish,dog,_,_,_), Hs), % 3
member(h(_,_,_,coffee,green), Hs), % 4
member(h(ukrainian,_,_,tea,_), Hs), % 5
adjacent(h(_,_,_,_,green), h(_,_,_,_,white), Hs), % 6
member(h(_,snake,winston,_,_), Hs), % 7
member(h(_,_,kool,_,yellow), Hs), % 8
Hs = [_,_,h(_,_,_,milk,_),_,_], % 9
Hs = [h(norwegian,_,_,_,_)|_], % 10
adjacent(h(_,fox,_,_,_), h(_,_,chesterfield,_,_), Hs), % 11
adjacent(h(_,_,kool,_,_), h(_,horse,_,_,_), Hs), % 12
member(h(_,_,lucky,juice,_), Hs), % 13
member(h(japanese,_,kent,_,_), Hs), % 14
adjacent(h(norwegian,_,_,_,_), h(_,_,_,_,blue), Hs), % 15
member(h(_,_,_,water,_), Hs), % one of them drinks water
member(h(_,zebra,_,_,_), Hs). % one of them owns a zebra
adjacent(A, B, Ls) :- append(_, [A,B|_], Ls).
adjacent(A, B, Ls) :- append(_, [B,A|_], Ls).
...ANSWER
Answered 2021-Jun-14 at 21:46The houses list Hs
is not empty at all, ever. It is created right at the very beginning with
QUESTION
There is a table like below one
...ANSWER
Answered 2021-Jun-09 at 19:35It looks like you want a cumulative sum of "product":
QUESTION
Tech
SQL Server 2014 on a shared server with collation
Turkish_CI_AS
- cannot be changed.Entity Framework Core 5.0.5
Data in the database:
...ANSWER
Answered 2021-Jun-08 at 09:18The problem is caused by the fact that the comparison is done on the server using the server-side collation, and you can't change that through EF's linq provider (which is why the overload with the StringComparison
argument fails). The collation is case-insensitive, but of course, being Turkish, considers 'i'
and 'I
' to be different characters.
The solution is to stop trying to change the case of the product names in the database and instead modify the search criterion.
Since none of the data being searched contains 'İ'
, the modification is simple: call ToUpper()
on the search value, and make certain that the conversion isn't done with Turkish culture. For example, if the default culture on the client isn't Turkish, you can just use
QUESTION
System.out.println("Write how many ml of water the coffee machine has: ");
int waterInMachine = scanner.nextInt();
System.out.println("Write how many ml of milk the coffee machine has: ");
int milkInMachine = scanner.nextInt();
System.out.println("Write how many grams of coffee beans the coffee machine has: ");
int beansInMachine = scanner.nextInt();
System.out.println("Write how many cups of coffee you will need: ");
int countCups = scanner.nextInt();
int water = 200 * countCups;
int milk = 50 * countCups;
int coffeeBeans = 15 * countCups;
int amountWater = waterInMachine;
int amountMilk = milkInMachine;
int amountCoffeeBeans = beansInMachine;
int count = 0;
while (amountWater > 200 && amountMilk > 50 && amountCoffeeBeans > 15) {
amountWater -= 200;
amountMilk -= 50;
amountCoffeeBeans -= 15;
count++;
}
if (waterInMachine >= water && milkInMachine >= milk && beansInMachine >= coffeeBeans && count > countCups) {
System.out.println("Yes, I can make that amount of coffee (and even " + (count - countCups) + " more than that)");
} else if (waterInMachine >= water && milkInMachine >= milk && beansInMachine >= coffeeBeans) {
System.out.println("Yes, I can make that amount of coffee");
} else if (count < countCups) {
System.out.println("No, I can make only " + count + " cup(s) of coffee");
}
...ANSWER
Answered 2021-Jun-05 at 17:10You are making coffees while
you have more than enough ingredients.
That means you won't make a coffee when you have exactly the right amount of ingredients.
Try changing this:
QUESTION
I need help with the following task please: For instance this is part of the HTML:
...ANSWER
Answered 2021-Jun-05 at 11:35Your first solution does work. So you may need to double check the content in your page.content
.
QUESTION
I have done the Einstein's Riddle exercise with linear programming. I implemented this solutions in Gusek. How can i tell if there is more than one solution?
Einsten's riddle:
There are 5 houses in five different colors. In each house lives a person with a different nationality. These five owners drink a certain type of beverage, smoke a certain brand of cigar and keep a certain pet. No owners have the same pet, smoke the same brand of cigar or drink the same beverage.
Constaints:
the Brit lives in the red house
the Swede keeps dogs as pets
the Dane drinks tea
the green house is on the left of the white house
the green house's owner drinks coffee
the person who smokes Pall Mall rears birds
the owner of the yellow house smokes Dunhill
the man living in the center house drinks milk
the Norwegian lives in the first house
the man who smokes blends lives next to the one who keeps cats
the man who keeps horses lives next to the man who smokes Dunhill
the owner who smokes BlueMaster drinks beer
the German smokes Prince
the Norwegian lives next to the blue house
the man who smokes blend has a neighbor who drinks water
Can I tell which constraints are redundant?
Thank you for your help
...ANSWER
Answered 2021-Jun-04 at 08:53Your decisions/solution will be in the form of binary or integer varibles.
If they are binary, add in a new constraint like the one below: (Y are all the binaries which were 1 and `Y are binaries which were 0.)
sum(Y) + sum(i-Y) != |Y|+|
Y|
Keep repeating this till you get an infeasible model. This can be extended to the integer case too.
As for redundancy, you have to manually try removing them and see if the solution changes. However, in terms of reduncancy, you might have cases where constraint A and B are redundant OR constraint C is redundant. You could have multiple sets of potential redundant constraints depending on which you eliminate.
QUESTION
See code below and log. I am working on a google sheets script that updates a google sheet when a linked google form is submitted. To do this I am using the array "event.namedValues", which is generated automatically when a form is submitted. However while debugging some issues (and learning how to do this), I wanted to check the length of the array I was working with and it would return "null". When I tried adding the .length property of the array to 0, the logger logged "NAN" (See log below). What am I doing wrong?
Code Sample:
...ANSWER
Answered 2021-Jun-03 at 22:59Since e.namedValues is an object, it does not have a length property.
QUESTION
I am querying a map to build some elements that should be wrapped in elements html, head and body.
I just added the key 'run' because I do not know how to call the 3rd template without matching something in the map. The both "store" templates produces expected result if they are run individual or both, but when attempting to wrap then inside the body element, (using the 3rd template) it fails.
Since I am planning to modularize the XSLT and templates I am not looking to reduced amount of template, unless necessary.
JSON:
...ANSWER
Answered 2021-Jun-02 at 09:08I would output the head
and body
in the first template where you create the html
anyway and then it seems adding second template suffices to use the other ones you have:
QUESTION
In first template, I am intentionally excluding an element ('milk') because the parsed data map is relatively flat and I would like to use XSLT to categorize and structure the data. The aim is to process the excluded element ('milk') in the second template. The both templates works running them one at a time. Running the templates together will not show the result of the excluded element ('milk') which should set another attribute name and attribute value.
JSON:
...ANSWER
Answered 2021-Jun-01 at 06:48I would write templates for each different output type and if the order of the output is different from the order of the input throw in an xsl:sort
or an XPath 3.1 sort
call to change the order:
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