ealias | Emacs loving aliases for the Bash shell | Command Line Interface library

by politza Shell Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | ealias Summary

ealias is a Shell library typically used in Utilities, Command Line Interface applications. ealias has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Emacs loving aliases for the Bash shell

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Quality

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Support

ealias has a low active ecosystem.

It has 15 star(s) with 2 fork(s). There are 4 watchers for this library.

It had no major release in the last 6 months.

ealias has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of ealias is current.

Quality

ealias has no bugs reported.

Security

ealias has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

ealias does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

ealias releases are not available. You will need to build from source code and install.

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ealias Key Features

No Key Features are available at this moment for ealias.

ealias Examples and Code Snippets

No Code Snippets are available at this moment for ealias.

Community Discussions

Trending Discussions on ealias

MariaDB : How to SUM child values from a GROUPED parent

how can i export pug file with ignored extend?

Owner of the fetching not present

QUESTION

MariaDB : How to SUM child values from a GROUPED parent

Asked 2020-Dec-04 at 17:42

I have found a tricky problem today.

I have an SQL query which collects a set of data from a number of different tables. It is a single query run on the "parent" table and outputs about 40 blocks of data. Some of these blocks are derived values such as "SUM"s.

This works perfectly, except on a page which listed results searched by the user. This page has an identical query with another table, which lists alias names for the "name" of the parent tables row.

When I add this JOIN to the SQL, the derived values are incorrect, being +1 more than they should be (double). The join is set on a PK just the same as every other reference table on the SQL,

The alias is linked to the main SQL by:

...

ANSWER

Answered 2020-Dec-04 at 17:42

My Solution

My solution was to duplicate the eza.name LIKE CONCAT('%',?,'%') on the end of the LEFT JOIN eealias eza ON Nee.see_id = eza.ee_id so:

Source https://stackoverflow.com/questions/64897216

QUESTION

how can i export pug file with ignored extend?

Asked 2018-Mar-06 at 02:48

I'm using pug to build a static site with some layout and module(performed by include).
And I implement pages by extends method, like this:

_layout.pug ...

ANSWER

Answered 2018-Mar-05 at 08:04

I believe you can use the pug if or unless condition to specify whether to render all the extends or not.

Source https://stackoverflow.com/questions/49102676

QUESTION

Owner of the fetching not present

Asked 2018-Feb-22 at 08:49

I am trying to learn hibernate here and came across this Class:

HelloWorldClient.java

...

ANSWER

Answered 2018-Feb-22 at 08:49

Join fetch doesn't make sense here, because it's a performance hint that forces eager loading of the relation.

Here you are practically telling hibernate:

Take all the student from the Guide join Student table, and make sure to eager fetch the reference to Student in Guide entity. But you have no Guide entity

If you want the student just select the student from their table and if you need the relation to Guide fetched declare it.

Source https://stackoverflow.com/questions/48922807

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install ealias

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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