Caterpillar | Caterpillar : Type-safe date formats | Date Time Utils library
kandi X-RAY | Caterpillar Summary
kandi X-RAY | Caterpillar Summary
Caterpillar: Type-safe date formats in Swift, no more "yyyy-MM-dd'T'HH:mm:ssZ".
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QUESTION
I want to write a method that returns true if a keyword is found in a string and false if not. I figured out how to do so but when the keyword is something like "cat" and the string is "There is a caterpillar on a lead" it returns true even though the cat is not in the string. What am I doing wrong?
...ANSWER
Answered 2021-Apr-22 at 04:22There are many ways to solve this problem. The issue is that when you use contains(), it looks for that subtext in the full string but you want to look at words only.
So split your string into a list/array of words using space
as a separator. Then Check if your array/list contains the word.
QUESTION
I am currently attempting to programm a small game. An enemy is supposed to chase the player, the actual chasing is not implemented yet. I still need to figure out how to do that, but that's not the question. I have made it so that the player returns to the start point once they collide with the enemy. In addition to that, a text 'Game over' is supposed to appear. The function for that is called at the end of the game loop and while the text appeared briefly(it actually only appeared once, I have tried it multiple times), it does not stay. I was planing on making it appear and then disappear after a few seconds so that the player can play again, but I'm not sure why it disappears instantly. If this is the wrong place to post this, please tell me, I will delete this post. This is my code, would be amazing if somebody could help me out:
...ANSWER
Answered 2021-Mar-23 at 15:57The collision only occurs for a moment and the game over text is only shown when the object collides. If you want to persist the text, set a gameover
variable when the collision is detected and display the text based on the state of the variable:
QUESTION
I am reading from a book, and then I was following the instructions but this error occurred
...ANSWER
Answered 2021-Mar-15 at 08:54The answer is actually very simple, Because
leaf.color('yellow')
can also be put as leaf.color = 'yellow'
QUESTION
I have a huge data-frame (>20m rows) with each row containing a timestamp and a numeric variable X. I want to assign a new column where for each row the value in this new column is the average of X in the previous rows within a specified time window e.g the average of all rows with time stamps no more than 5 min ago. Since the time stamps aren’t at regular intervals I can’t just take fixed slices
Currently the best approach I’ve found is a “caterpillar” algorithm which loops through the data frame once and moves the start/end index depending on whether the timeframe window has been breached. However this is proving infeasibly slow, and I was wondering if there was a clever vectorised way to do this? Perhaps involving np arrays instead?
Thanks
...ANSWER
Answered 2021-Feb-11 at 16:25Set your timestamp to the index and use the rolling() function. You can set the window to a time offset. For example:
QUESTION
First time encountering this so please bear with me.
I'm writing a React web app that pulls in data from a local db.json file and stores it in global state using the Context API. I have the data displayed on the page and I have a dropdown that pulls in the category names of this data as well.
When I select a dropdown item from the list, I'd like it to filter the list of data to that selected category.
Currently when you select a dropdown item, I get the following error:
"TypeError: Cannot read property 'toLowerCase' of undefined".
This tells me that I'm probably not accessing the 'category' data properly.
Here's an example of the JSON, I want to access the 'category':
...ANSWER
Answered 2021-Feb-03 at 02:50const [selectedCategory, setSelectedCategory] = useState('')
const filteredProducts = data.filter(machine => machine.category.toLowerCase() === selectedCategory.toLowerCase())
QUESTION
I'm trying to find a computationally friendly way for doing the following:
given list_of_strings = ['many', 'man', 'cat', 'caterpillar', 'pillow', 'pi', 'pill']
return sublist = ['many', 'caterpillar', 'pillow']
, i.e. the list of strings not contained in any other string.
The simplest solution would be to iterate over the elements and check whether each element is contained in the other, with O(n^2) complexity (even if there are some little optimizations I thought about, like sorting the strings by length, but this adds the sorting complexity), but I think it's too expensive.
I thought also about implementing a trie and then use each element of the list as an haystack, then keeping just the strings contained in one haystack (that of the string itself).
I think I'm missing more than I know, so I'm looking for suggestions
...ANSWER
Answered 2020-Oct-12 at 14:06The following should work considering that there are no duplicates in your list (if there are, question must clarify what will happen with them and the code can be adjusted):
QUESTION
I ran a bayesian linear mixed model with brms and can plot the estimates nicely but I can't figure out how to order the single-subject estimates based on the mean of the posterior samples (so as to get a caterpillar plot). This is what I've done.
Toy data:
...ANSWER
Answered 2020-Sep-10 at 02:52Two points for consideration:
- Ungroup the result from
spread_draws
, otherwise you won't be able to reorder the levels ofsubject
; - Use
fct_reorder
from theforcats
package in tidyverse. It's designed for this exact purpose.
QUESTION
What the class describes is about "reversing a string", which is correct and usable from the Leetcode website. Today, I want to present "reversing a string" by inputting a value by myself (such as the int main() part below), but I still can't execute it after thinking for a long time. Beginners sincerely ask for advice, maybe you can also attach your writing so that I can learn, thank you.
...ANSWER
Answered 2020-Aug-31 at 13:30Your code is pretty good, however we just want to reverse the words not the chars, for that we can use a while loop.
Similarly using two pointers, this'd pass just fine:
QUESTION
I've been doing an exercise and we need to create a caterpillar with the size attribute from the other function. In this code below I've added a size attribute between 0 and 3.
...ANSWER
Answered 2020-Aug-21 at 23:53Look at the API docs for ellipse https://www.pygame.org/docs/ref/draw.html#pygame.draw.ellipse
ellipse()
expects:
QUESTION
I have run into a problem in my project and could use some help figuring out what I am doing wrong.
...ANSWER
Answered 2020-Aug-21 at 22:47A few things I noticed in your code:
- In the
addSegment
method, thelength
never goes past zero - In the
grow
method, only the first segment is added. Other segments are ignored. - As @Kingsley mentioned, you create a new segment with an object instead of the x coord
Make these changes to the caterpillar
class:
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