regulex | : construction : Regular Expression | Regex library
kandi X-RAY | regulex Summary
kandi X-RAY | regulex Summary
Regulex is a JavaScript Regular Expression Parser & Visualizer. Try it now:
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QUESTION
I try to find all href
or src
not starting with a slash or hash.
E.g.
...ANSWER
Answered 2019-Sep-27 at 11:31Because the ((?!\/)|(?!#))
part matches a position that is either not followed with a /
or #
, while [^\/#]
matches a char that is neither /
nor #
.
You need to write the lookahead as (?![\/#])
: a position that is not followed with /
nor #
.
A regex may look like
QUESTION
I am trying to match a regex pattern for a JCL job statement Which can come in the below formats
//jobname JOB
//jobname JOB AccountInfo,'PGMR name',keyword=param,keyword=param,keywod=param
//jobname JOB ,keyword=param,keyword=param
//jobname JOB (Accountinfo)
//jobname JOB 'pgmrname'
//jobname JOB accountinfo
The structure is explained below
//name job > mandatory fields
Account info is optional and can exiting in two day accountinfo or (accountinfo)
PGMR name is optional and looks like this 'myname'
key word parameters optional and will be in pairs MSGCLASS=1,CLASS=P
Looking for matching the regex to match above all optional combination
I have tried using ?= if then else condition but not working regex used in given below
...ANSWER
Answered 2019-Sep-05 at 13:51I think something is missing from what you are trying to explain:
Do you need to have capture groups to extract information? Do you need to select just one line at a time?
if you just need to capture everything that start with \jobname JOB PARAMS, then you can simply say: \/\/.*JOB\s*.*
but im almost certain that this is not the case and some other explanation is missing.
If you need to get parts of the job string and split it into capture groups, something like this might be a good starting point:
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