koko | Yet another IRC client for me and you koko | Chat library

by KokoIRC TypeScript Version: v0.2.1 License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | koko Summary

koko is a TypeScript library typically used in Messaging, Chat, Electron applications. koko has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Yet another IRC client for me and you :koko:

Support

Quality

Security

License

Reuse

Support

koko has a low active ecosystem.

It has 312 star(s) with 26 fork(s). There are 10 watchers for this library.

It had no major release in the last 12 months.

There are 21 open issues and 12 have been closed. On average issues are closed in 53 days. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of koko is v0.2.1

Quality

koko has no bugs reported.

Security

koko has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

koko is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

koko releases are available to install and integrate.

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koko Key Features

No Key Features are available at this moment for koko.

koko Examples and Code Snippets

No Code Snippets are available at this moment for koko.

Community Discussions

Trending Discussions on koko

String class with concatenation с++

Javafx Is there a better way to add myObjects to GridPane?

IDictionary Value overwrite

Google BigQuery SQL: Extract data from JSON (list and array) into columns

undefined index 'value' in laravel

Printing different image for different list data

Web scraping from multiple pages with for loop part 2

Perl, how to make this scripter smaller, faster, better, stronger?

HTML: How to align left, center, and right footer phrases. Bootstrap

Problem with a task of printing inward triangle with stars

QUESTION

String class with concatenation с++

Asked 2021-Apr-22 at 16:10

I recently started learning c++ and I have a problem with implementing my own string class with string concatenation. When the strings are added together, an error appears in debugging : I checked on many lines and noticed that the program works fine when the line is short , but stops working at all with long lines I think I messed up my memory somewhere , but I can't find where I will be very glad of any help

...

ANSWER

Answered 2021-Apr-22 at 16:10

There are a lot of things wrong with your code.

Where is your operator=? You appear to have violated the Rule of Three. This is a massive memory bug.
for (int i = 1; i <= length; i++) if (i % 2 == 0) seems like a weird way to write for (int i = 2; i <= length; i+=2). This works fine, it's just weird.
operator+ does not allocate enough bytes for a null terminator, so all operations after that will read past the end of the buffer. This is a massive memory bug.
String(char* str) doesn't make a copy of the data, it assumes ownership of the pointer passed in. Which might work, except that operator+ constructs a String from tmp, and then deletes tmp, so now the String's data is gone. This is a massive memory bug.

Source https://stackoverflow.com/questions/67216829

QUESTION

Javafx Is there a better way to add myObjects to GridPane?

Asked 2021-Apr-17 at 14:54

i was searching for answer and trying so many options. Finally i found way to pass my own javaxf object to GridPane. But I still think there is a better way to this than I am doing. So here is my code: Main:

...

ANSWER

Answered 2021-Apr-17 at 14:54

As @JimD already commented, embedding a reference to the parent of a Node into a node is bad practice. There's nothing special about the Rectangles other than the event handler which toggles the colour. Assuming that you don't want to access the "selected" state of the Rectangles, you can ditch the custom class altogether.

The following code does everything that your sample does, except the call to the [not included] "ShelfShowUp.display("KOKOS", 7)" :

Source https://stackoverflow.com/questions/67137458

QUESTION

IDictionary Value overwrite

Asked 2021-Apr-04 at 02:53

This is my first time when I need to do something with dictionaries. I can't overwrite the item.Value and i don't know how should I do that.

Write a program that reads the name of one monkey per line from the lines of standard input to the end of file (EOF) and the number of bananas it collects in the following format:

monkey_name; number of bananas

The program writes the names of the monkeys and the number of bananas they have collected to the standard output in the form given in the example output, in lexicographically ascending order based on the names of the monkeys!

Input:

...

ANSWER

Answered 2021-Apr-03 at 14:44

class Program
{
    static void Main()
    {
        string input;
        string[] row;
        IDictionary majom = new SortedDictionary();

        //int i;
        //bool duplicate = false;

        while ((input = Console.ReadLine()) != null && input != "")
        {
            //duplicate = false;
            row = input.Split(';');

            // Usually dictionaries have key and value
            // hier are they extracted from the input
            string key = row[0];
            int value = int.Parse(row[1]);

            // if the key dose not exists as next will be created/addded
            if (!majom.ContainsKey(key))
            {
                majom[key] = 0;
            }

            // the value coresponding to the already existing key will be increased
            majom[key] += value;

            //foreach (var item in majom)
            //{
            //    if (item.Key == row[0])
            //    {
            //        duplicate = true;
            //        i = int.Parse(row[1]);
            //        item.Value += i; I'm stuck at here. I dont know how am i able to modify the Value
            //    }
            //}
            //if (!duplicate)
            //{
            //    i = int.Parse(row[1]);
            //    majom.Add(row[0], i);
            //}
        }

        foreach (var item in majom)
        {
            Console.WriteLine(item.Key + ": " + item.Value);
        }
    }  
}

Source https://stackoverflow.com/questions/66932130

QUESTION

Google BigQuery SQL: Extract data from JSON (list and array) into columns

Asked 2021-Mar-14 at 18:54

I have table with json string

...

ANSWER

Answered 2021-Mar-14 at 18:54

Below will work for you

Source https://stackoverflow.com/questions/66624805

QUESTION

undefined index 'value' in laravel

Asked 2021-Jan-29 at 04:35

im using laravel 7 and trying to get datas from api use http.

when i use dd('$datas'),i got this

...

ANSWER

Answered 2021-Jan-29 at 04:35

If you look at the data you are getting back from the API, your data is actually nested inside objects that live under a manajemen_sdm property.

Your loop should work correctly if you update it to loop over the manajemen_sdm key:

Source https://stackoverflow.com/questions/65948736

QUESTION

Printing different image for different list data

Asked 2021-Jan-14 at 09:26

so i made a list and i used tkinter for choosing a random data in list and showing that in a showinfo box. now i was just wondering if its possible to make a random image for random data. for eg i am making a app that generates a random anime name from the list but i want to add the anime picture also is there any way i can do that ? i haven't tried building it but here is what i have made so far.

i have no error i just want to have different picture for different names from the list chose randomly

...

ANSWER

Answered 2021-Jan-14 at 09:26

Since you want the image to be corresponding to the anime titles I suggest you use a dictionary instead of a list. Also, use Toplevel widget to display the output.

So here is an example code:

Source https://stackoverflow.com/questions/65678411

QUESTION

Web scraping from multiple pages with for loop part 2

Asked 2020-Dec-21 at 23:03

My original problem:

"I have created web scraping tool for picking data from listed houses.

I have problem when it comes to changing page. I did make for loop to go from 1 to some number.

Problem is this: In this web pages last "page" can be different all the time. Now it is 70, but tomorrow it can be 68 or 72. And if I but range for example to (1-74) it will print last page many times, because if you go over the maximum the page always loads the last."

Then I got help from Ricco D who wrote code that it will know when to stop:

...

ANSWER

Answered 2020-Dec-21 at 18:44

Finding your element with class name doesn't seem to be the best idea..because of this. Same class name for all the next elements.

I don't know what you are looking for exactly because of the language. I suggest..you go to the website>press f12>press ctrl+f>type the xpath..See what elements you get.If you don't know about xpaths read this. https://blog.scrapinghub.com/2016/10/27/an-introduction-to-xpath-with-examples

Source https://stackoverflow.com/questions/65398056

QUESTION

Perl, how to make this scripter smaller, faster, better, stronger?

Asked 2020-Sep-20 at 20:16

I'm a newbie in perl, how I can make this better and faster? (SPOJ task)

...

ANSWER

Answered 2020-Sep-20 at 20:16

Something which is divisible by 5 and 3 is divisible by 15, so your logic is more straight forward as...

Divisible by 15
Divisible by 5
Divisible by 3
Not divisible by 5 nor 3

I'd also take advantage of say.

I'd also replace the awkward until with a for and not bother with $i.

Avoid using $a and $b because these are special variables used by sort.

Turn on strict and warnings.

Strip the newline off $a. Technically not necessary if you're going to use it as a number, but if you don't printing it will have an extra newline.

A non-number % anything is 0. Unless we validate the input, if you input nothing or "bananas" you'll get SPOKOKOKO. We can check if the input looks like something Perl considers a number with Scalar::Util::looks_like_number. If it isn't a number, throw an exception; it isn't the function's job to figure out what to do with a non-number. Perl doesn't really have exceptions, but we can get close with a die and eval.

And put the logic inside a subroutine. This separates the details of the input and output from the logic. The logic can now be named, documented, tested, and reused. This also avoids the redundant say.

Source https://stackoverflow.com/questions/63982876

QUESTION

HTML: How to align left, center, and right footer phrases. Bootstrap

Asked 2020-Aug-06 at 22:16

I'm having issues aligning my footer text in a straight line. I'm a beginner here so I apologize if this question is redundant! See below:

I need all three of those lines, to be in a straight line.

My professor teaches a grid method, but that's not working for me at the moment. Any suggestions?

Here is my code:

...

ANSWER

Answered 2020-Aug-06 at 22:16

Source https://stackoverflow.com/questions/63292467

QUESTION

Problem with a task of printing inward triangle with stars

Asked 2020-Jul-12 at 15:25

public class TulosteluaLikeABoss {

    public static void tulostaTahtia(int maara) {
        // part 1
        int i = 0;
        while (maara >i) {

            System.out.print("*");
            i++;
        }
        System.out.println("");

    }

    public static void tulostaTyhjaa(int maara) {
        // part 1.1
        int i = 0;
        while (maara > i) {
            System.out.print(" ");
            i++;
        }
    }
    //something is wrong below
    public static void tulostaKolmio(int koko) {
        // part 2
        
        int j = koko;
        int k = 0;
        while (koko >= k) {

            tulostaTahtia(k);
            
            tulostaTyhjaa(j);
            k++;
            j = j-1;
        }
    }
    // from here below is irrelevant
    public static void jouluKuusi(int korkeus) {
        // part 3
    }

    public static void main(String[] args) {
        // Testit eivät katso main-metodia, voit muutella tätä vapaasti.

        tulostaKolmio(5);
        System.out.println("---");
        jouluKuusi(4);
        System.out.println("---");
        jouluKuusi(10);
    }
}

...

ANSWER

Answered 2020-Jul-12 at 15:25

tulostaKolmio(1) assigns koko the value of 1. The while loop in the method will run (koko + 1) number of times. During the first run in the loop tulostaTahita(0) gets called (since k=0 right now), altough it will not print any starts at this call it will print a new line because you have that outside the while loop in the tulostaTahita method.

During the second run in the loop, k=1 and thus tulostaTahita(1) is called. This will print another line so in the end you are left with 2 lines (where the first one is empty).

To solve this you want to add an if statement to make sure tulostaTahita only prints a new line when maara is greater than 0.

Source https://stackoverflow.com/questions/62862722

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