wongames | scalable game store made NextJS | Frontend Framework library
kandi X-RAY | wongames Summary
kandi X-RAY | wongames Summary
This repository refers to a awesome game store made with React .
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QUESTION
I want to know a player's position (rank) from a leaderboard. I'm not having a leaderboard table, it's being generated from the users
table and a query. This is how I get the entries:
ANSWER
Answered 2019-Feb-02 at 10:11This is straightforward using ranking functions of MySQL 8.0. For example, DENSE_RANK
computes the ranking of each row within a partition (tied records are assigned the same rank).
QUESTION
I'm using laravel 5.6.
I have 3 tables : players, games and game_player table.
Retrieving the game count of every player is easy with this in the index action of the PlayersController:
...ANSWER
Answered 2018-Apr-16 at 21:15Since you define a foreign key on the games table, you have a one-to-many relationship between the Player
and Game
already. Try adding the following relation to your Player
model:
QUESTION
I am trying to update a mysql database using an Ajax POST request to a php file, but I receive the following error:
...ANSWER
Answered 2017-Jun-05 at 16:26It doesn't work, because by putting
QUESTION
I am trying to fill a table using a jquery .get request, the url being a php file. The php gets data from a database, then it should return a json array back to the jquery, array which will fill the table. While the length of the array is returned as it should, the table cells are empty.
Here is my get.php function:
...ANSWER
Answered 2017-Jun-05 at 14:13If you look at your JSON data, you can see that there are no keys such as teams
or playedgames
. This is because you used fetch_row()
in the PHP. Change that to fetch_assoc()
:
QUESTION
I am trying to fill a table using a POST command to my servlet, but instead of sending a POST request, my webpage sends a GET request to the servlet. Here is my
...ANSWER
Answered 2017-Jun-05 at 09:03It is because of content-type
, when you are sending data by using post
method you have to use x-www-form-urlencoded
(which is default in $.ajax
) like,
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