vulture | light JSX rendering library with functional programming | Frontend Framework library

 by   calebmer TypeScript Version: Current License: MIT

kandi X-RAY | vulture Summary

kandi X-RAY | vulture Summary

vulture is a TypeScript library typically used in User Interface, Frontend Framework, React applications. vulture has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

TL;DR, Vulture is cool because promises/observables are valid JSX nodes and renderers are written as reducers. Vulture is an expiremental light JSX rendering library meant to be the base for building great abstractions on top of the JavaScript of the future. Vulture is inspired by React, but it attempts to take the core principles of React to their extremes and add some basic asynchronous features on top. The essence of React is a one input one output function: (data) => view. However, this simple concept somehow takes about 150kB to implement and requires a component most of the time instead of just a pure function. The reason for this is that (data) => view does not give us a good way to handle component state, so that’s where the React component architecture is useful. But Vulture thinks there’s a better way to handle state in a JSX rendering library.
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            kandi-support Support

              vulture has a low active ecosystem.
              It has 27 star(s) with 3 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 4 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of vulture is current.

            kandi-Quality Quality

              vulture has no bugs reported.

            kandi-Security Security

              vulture has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              vulture is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              vulture releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            vulture Key Features

            No Key Features are available at this moment for vulture.

            vulture Examples and Code Snippets

            No Code Snippets are available at this moment for vulture.

            Community Discussions

            QUESTION

            Overload += for a template?
            Asked 2021-May-18 at 01:24

            I have a base class Animal and a derived class Bird : Animal. I use a template class that will store vectors of pointers to either Animal or Bird objects. I want to overload the += operator in such a way that I can insert a new animal right in the Atlas, so m_length = m_length + 1, pages.push_back(animal), just to get the idea.

            Here's my template class:

            ...

            ANSWER

            Answered 2021-May-18 at 01:24

            The basic problem is that you've declared your operator+= as returning a T, but the return statement in it is return *this;, which is an Atlas2.

            If you change the return type to Atlas2 &, it should work. That's what you would normally want to return from an operator+= anyways, though with your use, it doesn't matter much as you're ignoring the returned value.

            Source https://stackoverflow.com/questions/67578313

            QUESTION

            Python - Function not returning y value
            Asked 2021-Apr-18 at 02:43

            I'm essentially making a counter and it counts the number of times a name appears in a list. I'm trying to use a function so I can easily do it for all the names. It works fine when I don't make the code a function but as soon as I do it no longer returns the value of y.

            ...

            ANSWER

            Answered 2021-Apr-18 at 02:39

            The assignment inside a function does not modify the global variable. To modify a global variable from inside a function, use the global keyword as shown below.

            Source https://stackoverflow.com/questions/67144638

            QUESTION

            While reading txt file lines. I can't "append list" or "update dictionary" why?
            Asked 2021-Mar-05 at 19:17

            I have txt file like that:

            ...

            ANSWER

            Answered 2021-Jan-23 at 06:56

            Here you go. below logic will read you file and convert it to the JSON structure which you are looking as output

            Source https://stackoverflow.com/questions/65855052

            QUESTION

            How to map JSON data from newsAPI in React App?
            Asked 2021-Feb-21 at 07:31

            Here is the JSON:

            ...

            ANSWER

            Answered 2021-Feb-21 at 07:31

            You can see the description for JSON function here:

            • JSON.parse() takes a JSON string and transforms it into a JavaScript object.
            • JSON.stringify() takes a JavaScript object and transforms it into a JSON string.

            In this case the fetch api always return Response Object. This is just an HTTP response, not the actual JSON. To extract the JSON body content from the response, we use the json() method. And after that you can use newsId.articles to get articles list

            Source https://stackoverflow.com/questions/66289155

            QUESTION

            Python: nested dictionary problem: trying to run a 'if' command to print out a string
            Asked 2020-Jul-19 at 06:01

            I am trying to do following 2 things for this nested dictionary:

            1. If a bird is aggressive, print out a string advising us to 'cover our heads' using the 'actions' list in this print statement.

            2. If a bird is endangered, print out a string advising us to 'back away', also using the actions list in this print statement.

            Here's what I have so far. Any help is much appreciated!:

            ...

            ANSWER

            Answered 2020-Jul-19 at 04:49
            final_actions={}
            for key, value in rarebirds.items():
                if final_actions.get(key)==None:
                    final_actions[key]=[]
                if 'Aggressive' in value and value.get("Aggressive")==True:
                    final_actions[key].append(actions[1])
                if 'Endangered' in value and value.get("Endangered")==True:
                    final_actions[key].append(actions[0])
                if ('Aggressive' in value and value.get("Aggressive")==False) and ('Endangered' in value and value.get("Endangered")==False):
                    final_actions[key].append(actions[2])
            print(final_actions)
            

            Source https://stackoverflow.com/questions/62976274

            QUESTION

            items between the hr tag in HTML. Top HR tag is not aligning properly
            Asked 2020-May-15 at 00:31

            I want to have a hr tag at the top and then my company logo and name of the company and an HR tag at the bottom. I wrote the below code to achieve this, but it is not showing the way I want it. Below is my code and the image:

            ...

            ANSWER

            Answered 2020-May-15 at 00:31

            Please give this code a try and let me know how it goes on your end. The logos and name I used it to see the final look and feel, sorry about that! Please make sure you add the Bootstrap css library in the head section as I have it on the code I am sharing with you. I certainly hope this helps!

            Source https://stackoverflow.com/questions/61808738

            QUESTION

            Python beginner query
            Asked 2020-May-12 at 12:42

            I've been trying to limit the wrong_answers to maximum of six times. That is if the user inputs answers 6 times wrong, he gets a print message.

            If I use the If statement, python code checks it only the first time it runs. Which means it doesn't come back to the If statement again. (If statement is us from bird_random = random.choice(Animals.bird_list))

            If I use Function, it displays the wrong_answers limit reached message correctly, however it continues to display code lines below. (i.e will continue to display further questions.)

            Question 1. What am I doing wrong? What is the solution 2. How Can I make my code more "Professional"?

            ...

            ANSWER

            Answered 2020-May-12 at 12:42

            Modify the 3rd while loop..

            from while guess_count < guess_limit:

            to while guess_count < guess_limit and wrong_answers < 6:

            Source https://stackoverflow.com/questions/61751760

            QUESTION

            Adding a dynamic MultiFrame index
            Asked 2020-Apr-09 at 09:10

            a question which I'm not able to answer myself. I've created a dataframe containing tournament rankings. The dataframe is the result of a group action and looks like this:

            ...

            ANSWER

            Answered 2020-Jan-16 at 10:33

            Use groupby with rank with ascending=False to get rank for each group and then set index with append=True , then reorder the levels:

            Source https://stackoverflow.com/questions/59767436

            QUESTION

            How to extract some text that doesn't have html tag with python
            Asked 2020-Jan-13 at 02:23

            How do i extract each sentence without a html tags, then add them to a list.

            For Example

            ...

            ANSWER

            Answered 2020-Jan-13 at 01:52

            Try with some similar like this :

            Source https://stackoverflow.com/questions/59708889

            QUESTION

            Count keywords and word stems in tweets
            Asked 2019-Nov-06 at 09:37

            I have a large dataframe consisting of tweets, and keyword dictionaries loaded as values that have words associated with morality (kw_Moral) and emotion (kw_Emo). In the past I have used the keyword dictionaries to subset a dataframe to get only the tweets that have one or more of the keywords present.

            For example, to create a subset with only those tweets that have emotional keywords, I loaded in my keyword dictionary...

            ...

            ANSWER

            Answered 2018-Dec-12 at 14:02

            Your requirement would seem to lend itself to a matrix type output, where, for example, the tweets are rows, and each term is a column, with the cell value being the number of occurrences. Here is a base R solution using gsub:

            Source https://stackoverflow.com/questions/53744358

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install vulture

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/calebmer/vulture.git

          • CLI

            gh repo clone calebmer/vulture

          • sshUrl

            git@github.com:calebmer/vulture.git

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