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avataaars-generator | Simple generator React app for avataaars | Generator Utils library

 by   fangpenlin TypeScript Version: Current License: MIT

 by   fangpenlin TypeScript Version: Current License: MIT

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kandi X-RAY | avataaars-generator Summary

avataaars-generator is a TypeScript library typically used in Generator, Generator Utils, React applications. avataaars-generator has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.
Avataaars generator is a simple web-based app for generating avatars developed by Fang-Pen Lin, the original avatar is designed by Pablo Stanley, the Sketch library can be found here. You can see it here: http://getavataaars.com.
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kandi-support Support

  • avataaars-generator has a medium active ecosystem.
  • It has 2316 star(s) with 306 fork(s). There are 49 watchers for this library.
  • It had no major release in the last 12 months.
  • There are 27 open issues and 9 have been closed. On average issues are closed in 91 days. There are 6 open pull requests and 0 closed requests.
  • It has a neutral sentiment in the developer community.
  • The latest version of avataaars-generator is current.
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quality kandi Quality

  • avataaars-generator has 0 bugs and 0 code smells.
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securitySecurity

  • avataaars-generator has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
  • avataaars-generator code analysis shows 0 unresolved vulnerabilities.
  • There are 0 security hotspots that need review.
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license License

  • avataaars-generator is licensed under the MIT License. This license is Permissive.
  • Permissive licenses have the least restrictions, and you can use them in most projects.
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buildReuse

  • avataaars-generator releases are not available. You will need to build from source code and install.
  • Installation instructions are not available. Examples and code snippets are available.
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avataaars-generator Key Features

Simple generator React app for avataaars

avataaars-generator Examples and Code Snippets

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yarn start

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Community Discussions

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Trending Discussions on Generator

QUESTION

How can I make an object with an interface like a random number generator, but that actually generates a specified sequence?

Asked 2022-Mar-31 at 13:47

I'd like to construct an object that works like a random number generator, but generates numbers in a specified sequence.

# a random number generator
rng = lambda : np.random.randint(2,20)//2

# a non-random number generator
def nrng():
    numbers = np.arange(1,10.5,0.5)
    for i in range(len(numbers)):
        yield numbers[i]

for j in range(10):
    print('random number', rng())
    print('non-random number', nrng())

The issue with the code above that I cannot call nrng in the last line because it is a generator. I know that the most straightforward way to rewrite the code above is to simply loop over the non-random numbers instead of defining the generator. I would prefer getting the example above to work because I am working with a large chunk of code that include a function that accepts a random number generator as an argument, and I would like to add the functionality to pass non-random number sequences without rewriting the entire code.

EDIT: I see some confusion in the comments. I am aware that python's random number generators generate pseudo-random numbers. This post is about replacing a pseudo-random-number generator by a number generator that generates numbers from a non-random, user-specified sequence (e.g., a generator that generates the number sequence 1,1,2,2,1,0,1 if I want it to).

ANSWER

Answered 2022-Mar-29 at 00:47

You can call next() with a generator or iterator as an argument to withdraw exactly one element from it. Saving the generator to a variable beforehand allows you to do this multiple times.

# make it a generator
def _rng():
    while True:
        yield np.random.randint(2,20)//2

# a non-random number generator
def _nrng():
    numbers = np.arange(1,10.5,0.5)
    for i in range(len(numbers)):
        yield numbers[i]

rng = _rng()
nrng = _nrng()
for j in range(10):
    print('random number', next(rng))
    print('non-random number', next(nrng))

Source https://stackoverflow.com/questions/71655179

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install avataaars-generator

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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