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QUESTION
I have three tables:
table1:
MODULE EMPLOYEE A Billy Bob A Billy Joe B John Doe B Jane Doe C Catey Ricetable2: Primary_Key = (MATERIAL_ID, MATERIAL_NUM)
MATERIAL_ID MATERIAL_NUM MODULE 11111111111 222222222222 A 11111111112 222222222223 B 11111111113 222222222224 Cand I need a query that will fill in my third table so that it looks like this:
table3: Foreign_Key = (MATERIAL_ID, MATERIAL_NUM)
MATERIAL_ID MATERIAL_NUM EMPLOYEE 11111111111 222222222222 Billy Bob 11111111111 222222222222 Billy Joe 11111111112 222222222223 John Doe 11111111112 222222222223 Jane Doe 11111111113 222222222224 Catey RiceI tried this query:
...ANSWER
Answered 2021-Jun-15 at 12:14I think you want to UPDATE
the employee column, not INSERT
new rows:
QUESTION
Is it possible to return the entirety of data not just part of which we are grouping by?
I mean for example - I have a dataframe with 5 columns and one of those columns contains distance
, the other one is timestamp
and the last important one is name
. I grouped dataframe by timestamp
- agg function I applied is (min) on distance
. As a return i get correctly grouped dataframe with timestamp and distance - how can i add columns name
there. If I group it by name
as well then timestamp
becomes duplicated - it has to stay unique. As a final result I need to get dataframe like this:
But instead i get this:
timestamp distance 2020-03-03 15:30:235 123 2020-03-03 15:30:435 111Whole table has more than 700k rows so joining it back on distance
gives me that amount of rows which my PC can't even handle.
Here is my groupby
which gives me 2nd table:
grouped_df = df1.groupby('timestamp')['distance'].min()
Here is what i tried to do in order to get name
inside the table:
ANSWER
Answered 2021-Jun-15 at 03:48You can use GroupBy.agg
method to apply min
on the distance column, and apply a relevant function on name column (lambda x:x
to simply return its data). This will return the dataframe with both columns back to you:
QUESTION
Working on a little Fallout minigame in python...
I have a function called level_up that allows player to distribute skill points.
Player's current stats are stored as attributes of the player class.
I created a variable inside the level_up function that copies the player's current stats to compare against while the leveling loop is running. I did this so that the player cannot edit the stat value to be less than what it was when the level up occurred.
I initialized this variable outside of the main loop of the function in order to have it be constant, but as the player makes edits to their stats, this variable (original values) seems to be updated with the new values, instead of staying at what the values were when the level up occurred.
Example (Billy's Small Guns skill is 15 when he levels up. original_values should store that 15 was the original value. Billy adds 5 points to Small Guns, making it 20. He decides he wants to go back to 15. Should work since the original value was 15, but original_values now has Small Guns at 20, so this change can't occur).
I thought initializing original_values outside the loop is what I would need to do. Does this have something to do with the fact that I'm updating class attributes?
Can anyone tell me what I am doing wrong? Thank you.
The Function
...ANSWER
Answered 2021-Jun-11 at 01:52original_values = self.combat_skills
does not make a copy. It's just another reference to the same object - changes made via one reference will be seen no matter which reference you use to access them because they're all the same object.
If you want to make a distinct copy use the copy
method of the dict
to make a copy. e.g. original_values = self.combat_skills.copy()
QUESTION
What is the best way to get a jwt token from a running NodeJS server, in a C# .NET Windows app? in .NET I use HttpClient to connect to an oauth2 server (and that succeeds), but how to get the very jwt token?
In NodeJS:
...ANSWER
Answered 2021-Jun-09 at 13:13In NodeJS you never send the token result in the api response, modify it like this :
QUESTION
I have strings that can have a various amount of "groups". I need to split them, but I am having trouble doing so. The groups will always start with [A-Z]{2-5}
followed by a :
and a string or varying length and spaces. It will always have a space in front of the group.
Example strings:
...ANSWER
Answered 2021-Jun-07 at 22:20You can use
QUESTION
I am new to this. I am exploring a timetable Android library in GitHub. I can now save a JSON of the class data and I have a JSON that stores the data of a simple timetable. The JSON string is as below:
...ANSWER
Answered 2021-Jun-07 at 08:48I don´t know any library that can do this, but you can do it yourself.
First, you can compare the days of the week of classes to know which classes you have to compare (you are going to compare the classes given on the same day).
Then, when you have the classes of a day, you have to compare the hours of these classes.
QUESTION
There will be a save button which will update the user column with the value in the assign user column. If the select list can be consolidated under the user column and keep the updated values that would be even better.
These are the steps I have taken so far:
- Added an interactive grid to the page.
- Created a query to populate the interactive grid.
ANSWER
Answered 2021-Jun-03 at 13:40The 2nd query you posted should be
QUESTION
I want the location to appear when I ask for results. Why can't I display the employee of the month's location?
Code:
...ANSWER
Answered 2021-May-21 at 07:32current_max = 0
employee_of_month = ''
employee_of_month_location = ''
for employee,location,hours in work_hours:
if hours > current_max:
current_max = hours
employee_of_month = employee
employee_of_month_location = location
else:
pass
return (employee_of_month, employee_of_month_location, current_max)
QUESTION
I have the following dataframe df1
ANSWER
Answered 2021-May-30 at 11:38merge
with pd.concat
QUESTION
I would like to know how to order values in a text file based on number, specifically, these numbers in front of the names. The program, in theory, should scan through all the numbers, move the largest one to the top, then repeat with the second largest, if I am correct. Test cases:
...ANSWER
Answered 2021-May-27 at 10:11Try:
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