jamhub | low-latency jamming space for musicians | Audio Utils library

by fletcherist TypeScript Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | jamhub Summary

jamhub is a TypeScript library typically used in Audio, Audio Utils applications. jamhub has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

— service for musicians' collaboration and jamming with very low latency (~20ms). also feel free to join our discord server to find musicians for jam.

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Support

jamhub has a low active ecosystem.

It has 23 star(s) with 3 fork(s). There are 5 watchers for this library.

It had no major release in the last 6 months.

jamhub has no issues reported. There are 10 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of jamhub is current.

Quality

jamhub has no bugs reported.

Security

jamhub has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

jamhub is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

jamhub releases are not available. You will need to build from source code and install.

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jamhub Key Features

No Key Features are available at this moment for jamhub.

jamhub Examples and Code Snippets

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Community Discussions

Trending Discussions on jamhub

java.lang.Object android.support.v4.app.i.getSystemService(java.lang.String)' in 2g network

QUESTION

java.lang.Object android.support.v4.app.i.getSystemService(java.lang.String)' in 2g network

Asked 2018-Jan-23 at 14:31

It works fine in 4G network and 3G network. but it working sometimes in 2G network and randomly I am getting crashing. How to overcome from this issue. help me out.

...

ANSWER

Answered 2018-Jan-23 at 14:31

i fixed that issue by adding condition like activity not equal to null. if((getActivity()!=null && !getActivity().isFinishing()) { --your code-- }

Source https://stackoverflow.com/questions/47900602

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