type-guards | Simple utility for runtime type checking | Validation library

 by   lazarljubenovic TypeScript Version: 0.15.0 License: No License

kandi X-RAY | type-guards Summary

kandi X-RAY | type-guards Summary

type-guards is a TypeScript library typically used in Utilities, Validation applications. type-guards has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

This module allows you to write run-time validation in a clear way in a strongly-typed manner. In other words, it gives you a nice way to keep your code DRY by writing the validation function, and get the TypeScript types with it.
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              type-guards has a low active ecosystem.
              It has 27 star(s) with 6 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 17 open issues and 11 have been closed. On average issues are closed in 101 days. There are 6 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of type-guards is 0.15.0

            kandi-Quality Quality

              type-guards has no bugs reported.

            kandi-Security Security

              type-guards has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              type-guards does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
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              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              type-guards releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            type-guards Key Features

            No Key Features are available at this moment for type-guards.

            type-guards Examples and Code Snippets

            No Code Snippets are available at this moment for type-guards.

            Community Discussions

            QUESTION

            "Structural type guard" works with `if`, but not as array filter predicate
            Asked 2021-Jan-12 at 18:26

            I have a union type (Pet in the example below) that combines multiple object types which each have a type property indicating their type. Sometimes I have an array of the union type (Pet[]) and need to .filter() it based on the type property. That in itself works perfectly fine, but in order to avoid redundant type declarations I want to make sure that the result of the .filter() call is automatically typed properly.

            User-defined type guards seemed like the perfect solution for this, so I implemented one that just checks the type property and narrows the type to { type: 'something' } without explicitly declaring the full type (this one's called isCatLike below). I tried using it inside an if and it correctly narrowed my type from Pet to Cat.

            I then tried to use it as a predicate for .filter() and this time the type wasn't narrowed at all. The resulting array was still typed as Pet[] although my if experiment had shown that the type guard was generally able to narrow from Pet to Cat.

            As another experiment I tried to change the type guard slightly and make the type predicate more explicit (is Cat instead of is { type: 'cat' } and suddenly the .filter() call correctly narrowed the type from Pet[] to Cat[] (this function is called isCat below).

            ...

            ANSWER

            Answered 2021-Jan-12 at 14:30

            From the handbook https://www.typescriptlang.org/docs/handbook/advanced-types.html#user-defined-type-guards

            pet is Fish is our type predicate in this example. A predicate takes the form parameterName is Type, where parameterName must be the name of a parameter from the current function signature. Any time isFish is called with some variable, TypeScript will narrow that variable to that specific type if the original type is compatible.

            I would guess that since the original type is any in the type guard, TS can't narrow it down at all, if you swap any for Cat you even get a compilation error saying that {type: 'cat'} is not assignable to Cat cause of missing the other two props.

            I took that as a hint and made those other props optional: type Cat = { type: 'cat'; name?: string; purrs?: boolean }

            Your predicate starts working as you want it to then.

            Source https://stackoverflow.com/questions/65683063

            QUESTION

            User defined type guard on outer type / nested property?
            Asked 2020-Dec-17 at 20:02

            I have a question related to user defined type guards, in particular whether it is possible to implement a predicate function that serves as a type guard for a sub field.

            Consider the following example:

            ...

            ANSWER

            Answered 2020-Dec-17 at 19:58

            Something like this should do the trick. Playground

            Source https://stackoverflow.com/questions/65347424

            QUESTION

            Check for required fields of an arbitrary input object
            Asked 2020-Nov-20 at 04:30

            I use TypeScript in AWS Lambdas. Input objects provided for such Lambdas can be arbitrary. I always need to check if all required fields are provided in the input. I need to provide an error message explicitly saying which fields are missing if this is the case. If all required fields are provided, I need to cast the object into a domain object defined as an interface. Here an example of how this can be done:

            ...

            ANSWER

            Answered 2020-Nov-19 at 11:12

            Possible answer using an automatical way to check.

            Unfortunately you need to provide the keys of the properties to check.

            snippet

            Source https://stackoverflow.com/questions/64910009

            QUESTION

            Typescript type declaration with square brackets
            Asked 2020-Sep-25 at 23:15

            ANSWER

            Answered 2020-Sep-25 at 23:15

            Short explanation: This usage, gets all the value types of all properties.

            First of all, [] after a type drills into that type by accessing that type with a key (or keys)

            Source https://stackoverflow.com/questions/64072249

            QUESTION

            TypeScript: Type Guard for custom type
            Asked 2020-Jul-21 at 21:15

            Goal: Trying to create a type guard for a custom type.

            Here is my custom type:

            ...

            ANSWER

            Answered 2020-Jul-21 at 21:15

            The reason you are getting that error is because:

            https://www.typescriptlang.org/docs/handbook/advanced-types.html#type-aliases

            type Easing = "ease-in" | "ease-out" | "ease-in-out";
            String literal types allow you to specify the exact value a string must have. In practice string literal types combine nicely with union types, type guards, and type aliases. You can use these features together to get enum-like behavior with strings.

            I had to look this up.... the example I found was https://www.damirscorner.com/blog/posts/20200619-StringLiteralTypeGuardInTypescript.html

            Source https://stackoverflow.com/questions/63022859

            QUESTION

            TypeScript parameter type is a union of multiple types: How can I determine which was supplied and work with it?
            Asked 2020-Apr-20 at 15:23

            I'm working with the React Google Login library in TypeScript. It has type bindings for TypeScript, but all the examples are in JavaScript, and I am pretty new to TypeScript.

            The setup code looks like this:

            ...

            ANSWER

            Answered 2020-Apr-18 at 12:30

            Have you tried using a type assertion, e.g.

            Source https://stackoverflow.com/questions/61288884

            QUESTION

            When would an 'is' predicate ever be needed, as opposed to using the 'in' operator?
            Asked 2020-Feb-18 at 00:31

            According to the TypeScript documentation we can use TypeGuards to differentiate between types.

            The documentation gives examples using the is predicate, and using the in operator.

            is predicate:

            ...

            ANSWER

            Answered 2020-Feb-18 at 00:31

            The in operator is just one way of narrowing the type of a variable. You can write type guards using any checks you like:

            Source https://stackoverflow.com/questions/60272040

            QUESTION

            Is there a way to create a type-guard for nested key access in Typescript?
            Asked 2020-Feb-10 at 17:48

            I am reworking an implementation which was previously made using vanilla Javascript. I ran into an interesting situation which I do have a solution for, but for which I thought I had a superior solution which does not appear to work.

            Basically, I have an object with two nested objects, their indexes typed as the string literals of their keys, where both objects have some of the other objects keys but not a total overlap. Then, I have a function that can receive either key, and a second key to access one of the values in that object. I created custom type-guards for the key, and created a second set of type-guards to confirm the second key passed was a key of one of the objects. Then, I created a function that takes both keys, and should return an object with correctly matched keys. However, typescript does not seem convinced within the function that I am using my validator function, that the key returned from my function is only one that can definitely access the key of the upper level object.

            That a really unclear explanation, and I think some example code will make it better, so here it is:

            ...

            ANSWER

            Answered 2020-Feb-10 at 17:35
            TL;DR

            you can do this istead:

            Source https://stackoverflow.com/questions/60154699

            QUESTION

            Typescript user-defined type guard checking object has all properties in array
            Asked 2020-Jan-23 at 07:09

            I'm trying to write a user-defined type guard that tests whether the value it's given has all the properties in a given array.

            I'm calling this function hasAll and it's implementation and usage in Javascript would look like this:

            ...

            ANSWER

            Answered 2020-Jan-23 at 07:03

            This seems to meet your requirements:

            Source https://stackoverflow.com/questions/59872604

            QUESTION

            Arrow style user defined type guard?
            Asked 2020-Jan-07 at 13:30

            The typescript handbook on user defined type guards defines an example type guard as

            ...

            ANSWER

            Answered 2017-Dec-16 at 15:26

            Yes, just as you would have returned boolean, you simply return pet is Fish:

            Source https://stackoverflow.com/questions/47846980

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            You can download it from GitHub.

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            npm i type-guards

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