type-guards | Simple utility for runtime type checking | Validation library
kandi X-RAY | type-guards Summary
kandi X-RAY | type-guards Summary
This module allows you to write run-time validation in a clear way in a strongly-typed manner. In other words, it gives you a nice way to keep your code DRY by writing the validation function, and get the TypeScript types with it.
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Trending Discussions on type-guards
QUESTION
I have a union type (Pet
in the example below) that combines multiple object types which each have a type
property indicating their type. Sometimes I have an array of the union type (Pet[]
) and need to .filter()
it based on the type
property. That in itself works perfectly fine, but in order to avoid redundant type declarations I want to make sure that the result of the .filter()
call is automatically typed properly.
User-defined type guards seemed like the perfect solution for this, so I implemented one that just checks the type
property and narrows the type to { type: 'something' }
without explicitly declaring the full type (this one's called isCatLike
below). I tried using it inside an if
and it correctly narrowed my type from Pet
to Cat
.
I then tried to use it as a predicate for .filter()
and this time the type wasn't narrowed at all. The resulting array was still typed as Pet[]
although my if
experiment had shown that the type guard was generally able to narrow from Pet
to Cat
.
As another experiment I tried to change the type guard slightly and make the type predicate more explicit (is Cat
instead of is { type: 'cat' }
and suddenly the .filter()
call correctly narrowed the type from Pet[]
to Cat[]
(this function is called isCat
below).
ANSWER
Answered 2021-Jan-12 at 14:30From the handbook https://www.typescriptlang.org/docs/handbook/advanced-types.html#user-defined-type-guards
pet is Fish is our type predicate in this example. A predicate takes the form parameterName is Type, where parameterName must be the name of a parameter from the current function signature. Any time isFish is called with some variable, TypeScript will narrow that variable to that specific type if the original type is compatible.
I would guess that since the original type is any
in the type guard, TS can't narrow it down at all, if you swap any
for Cat
you even get a compilation error saying that {type: 'cat'}
is not assignable to Cat
cause of missing the other two props.
I took that as a hint and made those other props optional:
type Cat = { type: 'cat'; name?: string; purrs?: boolean }
Your predicate starts working as you want it to then.
QUESTION
I have a question related to user defined type guards, in particular whether it is possible to implement a predicate function that serves as a type guard for a sub field.
Consider the following example:
...ANSWER
Answered 2020-Dec-17 at 19:58Something like this should do the trick. Playground
QUESTION
I use TypeScript in AWS Lambdas. Input objects provided for such Lambdas can be arbitrary. I always need to check if all required fields are provided in the input. I need to provide an error message explicitly saying which fields are missing if this is the case. If all required fields are provided, I need to cast the object into a domain object defined as an interface. Here an example of how this can be done:
...ANSWER
Answered 2020-Nov-19 at 11:12Possible answer using an automatical way to check.
Unfortunately you need to provide the keys of the properties to check.
QUESTION
Just found following code snippet in https://www.typescriptlang.org/docs/handbook/advanced-types.html#type-guards-and-differentiating-types
...ANSWER
Answered 2020-Sep-25 at 23:15Short explanation: This usage, gets all the value types of all properties.
First of all, []
after a type drills into that type by accessing that type with a key (or keys)
QUESTION
Goal: Trying to create a type guard for a custom type.
Here is my custom type:
...ANSWER
Answered 2020-Jul-21 at 21:15The reason you are getting that error is because:
https://www.typescriptlang.org/docs/handbook/advanced-types.html#type-aliases
type Easing = "ease-in" | "ease-out" | "ease-in-out";
String literal types allow you to specify the exact value a string must have. In practice string literal types combine nicely with union types, type guards, and type aliases. You can use these features together to get enum-like behavior with strings.
I had to look this up.... the example I found was https://www.damirscorner.com/blog/posts/20200619-StringLiteralTypeGuardInTypescript.html
QUESTION
I'm working with the React Google Login library in TypeScript. It has type bindings for TypeScript, but all the examples are in JavaScript, and I am pretty new to TypeScript.
The setup code looks like this:
...ANSWER
Answered 2020-Apr-18 at 12:30Have you tried using a type assertion, e.g.
QUESTION
According to the TypeScript documentation we can use TypeGuards to differentiate between types.
The documentation gives examples using the is
predicate, and using the in
operator.
is
predicate:
ANSWER
Answered 2020-Feb-18 at 00:31The in
operator is just one way of narrowing the type of a variable. You can write type guards using any checks you like:
QUESTION
I am reworking an implementation which was previously made using vanilla Javascript. I ran into an interesting situation which I do have a solution for, but for which I thought I had a superior solution which does not appear to work.
Basically, I have an object with two nested objects, their indexes typed as the string literals of their keys, where both objects have some of the other objects keys but not a total overlap. Then, I have a function that can receive either key, and a second key to access one of the values in that object. I created custom type-guards for the key, and created a second set of type-guards to confirm the second key passed was a key of one of the objects. Then, I created a function that takes both keys, and should return an object with correctly matched keys. However, typescript does not seem convinced within the function that I am using my validator function, that the key returned from my function is only one that can definitely access the key of the upper level object.
That a really unclear explanation, and I think some example code will make it better, so here it is:
...ANSWER
Answered 2020-Feb-10 at 17:35you can do this istead:
QUESTION
I'm trying to write a user-defined type guard that tests whether the value it's given has all the properties in a given array.
I'm calling this function hasAll
and it's implementation and usage in Javascript would look like this:
ANSWER
Answered 2020-Jan-23 at 07:03This seems to meet your requirements:
QUESTION
The typescript handbook on user defined type guards defines an example type guard as
...ANSWER
Answered 2017-Dec-16 at 15:26Yes, just as you would have returned boolean
, you simply return pet is Fish
:
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