leon | 🧠 Leon is your open-source personal assistant | Speech library

by leon-ai TypeScript Version: nodejs-bridge_v1.0.0 License: MIT

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kandi X-RAY | leon Summary

leon is a TypeScript library typically used in Telecommunications, Media, Advertising, Marketing, Artificial Intelligence, Speech applications. leon has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Leon is an open-source personal assistant who can live on your server. He does stuff when you ask him for. You can talk to him and he can talk to you. You can also text him and he can also text you. If you want to, Leon can communicate with you by being offline to protect your privacy.

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leon has a medium active ecosystem.

It has 12924 star(s) with 1052 fork(s). There are 226 watchers for this library.

It had no major release in the last 12 months.

There are 63 open issues and 207 have been closed. On average issues are closed in 25 days. There are 17 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of leon is nodejs-bridge_v1.0.0

Quality

leon has 0 bugs and 0 code smells.

Security

leon has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

leon code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

leon is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

leon releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

leon saves you 500 person hours of effort in developing the same functionality from scratch.

It has 2913 lines of code, 104 functions and 134 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

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leon Key Features

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leon Examples and Code Snippets

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Community Discussions

Trending Discussions on leon

Is there an R function to help turn State abbreviations into full names? Or Vice Versa?

Passing NULL as parameter in a where clause for a Snowflake function

Find the standard deviation with index and dataframe

Functions for finding the average

How to escape special characters in Python?

delete CSV file row based on the value of a column in command line

Transpose multiple sub-headers into factor column in R

how to concatenate same row names in same column on python dataframe

One If-Else statement is always read

Intervals for term structures

QUESTION

Is there an R function to help turn State abbreviations into full names? Or Vice Versa?

Asked 2022-Apr-18 at 03:52

I have two large-ish data frames I am trying to append...

In df1, I have state codes, county codes, state names (Alabama, Alaska, etc.), county names, and years from 2010:2020.

In df2, I have county names, state abbreviations (AL, AK), and data for the year 2010 (which I am trying to merge into df1. The issue lies in that without specifying the state name and simply merging df1 and df2, some of the data which I am trying to get into df1 is duplicated due to there being some counties with the same name...hence, I am trying to also join by state to prevent this, but I have state abbreviations, and state names.

Is there any way in which I can make either the state names in df1 abbreviations, or the state names in df2 full names? Please let me know! Thank you for the help.

Edit: dput(df2)

...

ANSWER

Answered 2022-Apr-18 at 03:52

Here's one way you could turn state abbreviations into state names using R's built in state vectors:

Source https://stackoverflow.com/questions/71907258

QUESTION

Passing NULL as parameter in a where clause for a Snowflake function

Asked 2022-Mar-25 at 03:13

I have a function with parameters. If I pass null as the parameter in a where clause I would like it to bring back all results eg

...

ANSWER

Answered 2022-Mar-25 at 03:13

As per Dai's comment:

Source https://stackoverflow.com/questions/71611565

QUESTION

Find the standard deviation with index and dataframe

Asked 2022-Feb-26 at 19:40

I have a Dataframe df containing information about people. I need to compute the standard deviation of the weight of people whose name starts with N. This is my code to create the Dataframe:

...

ANSWER

Answered 2022-Feb-26 at 19:40

You are almost there. Casting df.index to pd.Series is unnecessary and leads to an error as indices get misaligned form the original df. Try:

Source https://stackoverflow.com/questions/71279696

QUESTION

Functions for finding the average

Asked 2022-Feb-26 at 08:22

I am a newbie here. English is not my native language so excuse any grammatical mistakes. I need to compute the average BMI per hair colour using the df.

...

ANSWER

Answered 2022-Feb-26 at 08:02

You can use df.groupby() which is a functionality within Pandas

For your particular case, you may use

Source https://stackoverflow.com/questions/71274973

QUESTION

How to escape special characters in Python?

Asked 2022-Feb-01 at 22:42

I pulled a report from a crm system that came with some special characters like:

...

ANSWER

Answered 2022-Feb-01 at 15:15

You can use the built-in function html.unescape:

Source https://stackoverflow.com/questions/70934656

QUESTION

delete CSV file row based on the value of a column in command line

Asked 2022-Feb-01 at 01:04

here is how my dataset looks like, I am trying to filter out country that the 4th column is >= 1000.

...

ANSWER

Answered 2022-Feb-01 at 00:47

Assuming that your Input_file's last field may have spaces in it. You can also check it by doing cat -e Input_file it will show you where is line ending including hidden spaces at the line end. If this is the case then try following command.

Source https://stackoverflow.com/questions/70934439

QUESTION

Transpose multiple sub-headers into factor column in R

Asked 2022-Jan-23 at 00:07

structure(list(
fecha = c("Fuente:La Nueva Viga, DF", "20/02/2020", 
           "20/02/2020", "20/02/2020", "20/02/2020", "Fuente:Monterrey, Nuevo León", 
           "20/02/2020", "20/02/2020", "20/02/2020", "20/02/2020", "17/02/2020", 
           "17/02/2020"), 
producto = c("Fuente:La Nueva Viga, DF", "Aleta de raya", 
           "Bandera", "Besugo", "Cazón con cabeza", "Fuente:Monterrey, Nuevo León", 
             "Huachinango Golfo", "Pampano", "Sargo", "Trucha marina", "Huachinango Golfo", 
            "Pampano"), origen = c("Fuente:La Nueva Viga, DF", "Tabasco", 
             "Campeche", "Veracruz", "Veracruz", "Fuente:Monterrey, Nuevo León", 
            "Tamaulipas", "Tamaulipas", "Tamaulipas", "Tamaulipas", "Tamaulipas", 
            "Tamaulipas"), 
pmin = c("Fuente:La Nueva Viga, DF", "23.00", 
             "35.00", "15.00", "60.00", "Fuente:Monterrey, Nuevo León", "165.00", 
             "--", "--", "--", "210.00", "--"), pmax = c("Fuente:La Nueva Viga, DF", 
             "27.00", "39.00", "19.00", "65.00", "Fuente:Monterrey, Nuevo León", 
             "200.00", "--", "--", "--", "220.00", "--"), 
pfrec = c("Fuente:La Nueva Viga, DF", 
             "25.00", "37.00", "17.00", "63.00", "Fuente:Monterrey, Nuevo León", 
             "190.00", "195.00", "84.00", "98.00", "215.00", "195.00"), 
obs = c("Fuente:La Nueva Viga, DF", 
             "", "", "", "", "Fuente:Monterrey, Nuevo León", "OBS", "OBS", 
             "OBS", "OBS", "OBS", "OBS"), 
category = c("pescado", "pescado", 
             "pescado", "pescado", "pescado", "pescado", "pescado", "pescado", 
             "pescado", "pescado", "pescado", "pescado")), 
row.names = c(2L, 3L, 4L, 5L, 6L, 341L, 342L, 343L, 344L, 345L, 346L, 347L), class = "data.frame")

...

ANSWER

Answered 2022-Jan-23 at 00:07

Here is one possibility (assuming that all sub-headers begin with Fuente) using tidyverse. Here, I create a grouping column (idx) by gathering all rows until Fuente appears in a subsequent row. Then, I split those into individual dataframes and put into a list. Then, I use map to apply a function to that list. I extract the text after Fuente, then copy that to all rows in that dataframe. Finally, I bind the list of dataframes back together.

Tidyverse

Source https://stackoverflow.com/questions/70809923

QUESTION

how to concatenate same row names in same column on python dataframe

Asked 2022-Jan-08 at 15:13

I have a simple dataframe like this:

...

ANSWER

Answered 2022-Jan-08 at 14:52

You could use pandas.DataFrame.groupby and pandas.DataFrame.aggregate after first making the name column lowercase:

Source https://stackoverflow.com/questions/70633347

QUESTION

One If-Else statement is always read

Asked 2022-Jan-06 at 10:29

I'm currently having a problem with my code specifically the If-else part. If my year-level is 1, the if-else is satisfied but if the year-level I'll input is 2, 3 or 4, the if-else for these are satisfied HOWEVER, it always displays the if-else for yrep1 (It always prints "Year-level Representative: Lady Carmel") except if the year-level is 1.

...

ANSWER

Answered 2022-Jan-06 at 10:28

The problem is that these variables

Source https://stackoverflow.com/questions/70605643

QUESTION

Intervals for term structures

Asked 2021-Dec-31 at 00:29

For a student learning platform (mathematics) we have managed to include Maxima and evaluate terms/equations/numbers on equivalence. For this we have programmed an algorithm randomly choosing numbers for all the variables and then comparing the two results whether they lead to the same values or not (more mathematically speaking we are seeing the terms as functions and comparing them at specific places).

Now the problem comes: Unfortunately, there must be the possibility to define ranges for coefficients of variables. So e.g. the correct solution [4,5]x^2-[3,4]x at the position x=10 leads to [4,5]*10^2-[3,4]*10. Here we have to find the minimum/maximum of this expression with e.g. the range of 4 to 5 as the coefficient before x^2. I have not been able to do this with native Maxima functions, so I am asking here for help. I am also wondering whether this is possible to combine with other functions such as sin, e etc. or whether this makes the whole optimisation problem too complex (and we should only allow polynomials).

Your help is greatly appreciated!

Best, Leon

...

ANSWER

Answered 2021-Dec-31 at 00:29

To summarize what we said in the comments, we have something like sum(a[k]*e[k], k, 1, n) where coefficients a[k] are constrained by intervals I[k] and e[k] is an expression in x. Given that x is a specific value, then the sum is a linear combination of the a[k] and the extreme values are at the corners of the hypercube given by the Cartesian product of the intervals.

A simple solution is to just enumerate the corners of the hypercube and evaluate the sum at each corner, and see which is greatest. (If there are ties, that means that the sum is not actually a function of some coefficient. Given the problem statement, that means the corresponding e[k] is zero. Let's look for and omit such coefficients, then there can only be a unique maximum.)

Here's my attempt at a solution, hope I've understood what's going on and what needs to happen. Assume without checking that a, e, and I are all the same length, namely n.

Source https://stackoverflow.com/questions/70526329

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