vime | Modern alternative | Frontend Framework library

by vime-js TypeScript Version: v5.4.0 License: MIT

X-Ray Key Features Code Snippets Community Discussions(4)Vulnerabilities Install Support

kandi X-RAY | vime Summary

vime is a TypeScript library typically used in User Interface, Frontend Framework, Angular, React applications. vime has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Vime is a customizable, extensible, accessible and framework agnostic media player.

Support

Quality

Security

License

Reuse

Support

vime has a medium active ecosystem.

It has 2524 star(s) with 143 fork(s). There are 21 watchers for this library.

It had no major release in the last 6 months.

There are 158 open issues and 138 have been closed. On average issues are closed in 41 days. There are 4 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of vime is v5.4.0

Quality

vime has no bugs reported.

Security

vime has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

vime is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

vime releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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vime Key Features

No Key Features are available at this moment for vime.

vime Examples and Code Snippets

No Code Snippets are available at this moment for vime.

Community Discussions

Trending Discussions on vime

how can i fix this NullExceptionPointer error?

How to filter a data.frame by matching a character string?

SQL Server using inner join on 2 databases with different SQL authentication credentials

Generate Usernames in Python

QUESTION

how can i fix this NullExceptionPointer error?

Asked 2020-Jul-28 at 20:54

Hey this is ready made code from a Maple Story game That I run a function for me it works for others does not They do not get a timer. seems chr.getFitness() returning null I'm not strong in java I would love if someone would help. Error 1 img

Also they cant pass last stage in game Error 2 img

MapleFitness Script

...

ANSWER

Answered 2020-Jul-28 at 20:54

Check if the MapleFitness is null and if it is, then create the object before returning like this

Source https://stackoverflow.com/questions/63020226

QUESTION

How to filter a data.frame by matching a character string?

Asked 2020-Jul-08 at 17:11

I have those structures:

...

ANSWER

Answered 2020-Jul-07 at 22:59

Using the solution from this answer.

Source https://stackoverflow.com/questions/62784381

QUESTION

SQL Server using inner join on 2 databases with different SQL authentication credentials

Asked 2018-Apr-16 at 11:58

This probably can't be done, but thought I'd ask anyway.

On my SQL Server I have 2 databases, each has different SQL Authentication credentials - different usernames and passwords on each one as each are used by different programs.

What I want to do is an inner join query which links 2 tables, one from each database.

If it was Just Windows authentication, I could use something like:

...

ANSWER

Answered 2018-Apr-16 at 11:58

I think the best way to show this is with a script. This is pretty much self explanatory, however, if you have any question, please comment:

Source https://stackoverflow.com/questions/49854804

QUESTION

Generate Usernames in Python

Asked 2018-Apr-08 at 05:21

I have a text file studentlist.txt which reads as follows:

studentlist.txt

...

ANSWER

Answered 2018-Apr-08 at 04:58

usernames = []
count = 1 #put countoutside
for line in open('studentlist.txt'):

  name = line.lower().split()
  surname = name[-1]
  username = ''.join(name[0:-1])
  username_w_surname = username + surname[0]
  username_w_surname_integer = username_w_surname + str(count)

  if username not in usernames:
    usernames.append(username)
  elif username_w_surname not in usernames:
    usernames.append(username_w_surname)
  else:
    count = count + 1
    usernames.append(username_w_surname_integer)
for entry in usernames:
  print (entry)


sam
samf
samg
samc
samv
samv1
samv2

Source https://stackoverflow.com/questions/49714426

Community Discussions, Code Snippets contain sources that include Stack Exchange Network