pant | Ported from Vant | Frontend Framework library
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kandi X-RAY | pant Summary
Mobile UI Components built on Preact.
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QUESTION
I have a table like below and I want to return the name of the item with the greatest effect of a particular type. For example, I want the name of the ring with the best 'Shield' enchantment, in this case 'Brusef Amelion's Ring'.
Description Apparel slot Effect Type Effect Value Apron of Adroitness Chest Fortify Agility 5 pts Brusef Amelion's Ring Ring Shield 18% Cuirass of the Herald Chest Fortify Health 15 pts Fortify Magicka Pants Legs Fortify Magicka 20 pts Grand ring of Aegis Ring Shield 6%I've tried using a MAXIFS statement:
...ANSWER
Answered 2021-Jun-13 at 19:56Is this what you are looking for?
QUESTION
public class Main
{
static String clotheOrder[] = {"FB02", null, null, null, "TS03", "GS04", null, "PA03"};
int clotheQuantity[] = {3, 0, 2, 0, 2, 2, 0, 0};
static String cType, cSize;
```
public static void main(String[] args) {
for (int x = 0; x <= clotheOrder.length; x++) {
if (clotheOrder[x] == null) {
System.out.println("No order");
continue;
}
else {
System.out.println(clotheType(clotheOrder[x].replaceAll("[^0-9]", ""))
+ clotheSize(clotheOrder[x].replaceAll("[^A-Z]", "")));
}
}
}
static String clotheType(String type) {
if (type == "FB" ) {cType = "Blouse .............";}
else if (type == "TS" ) {cType = "T-Shirt ............";}
else if (type == "GS" ) {cType = "Garterized Shorts ..";}
else if (type == "PA" ) {cType = "Pants ..............";}
else if (type == "PS" ) {cType = "Pencil Skirt .......";}
else if (type == "CC" ) {cType = "Chinese Collar Polo ";}
else if (type == "PW" ) {cType = "White Slacks .......";}
else if (type == "RB" ) {cType = "Round Neck Blouse ..";}
else if (type == "S" ) {cType = "Skirt ..............";}
else if (type == "VN" ) {cType = "V-Neck Polo ........";}
return cType;
}
static String clotheSize(String size) {
if (size == "01") {cSize = " (Extra-Small) ...";}
else if (size == "02") {cSize = " (Small) .........";}
else if (size == "03") {cSize = " (Medium) ........";}
else if (size == "04") {cSize = " (Large) .........";}
else if (size == "05") {cSize = " (X-Large) .......";}
else if (size == "06") {cSize = " (2X-Large) ......";}
else if (size == "07") {cSize = " (3X-Large) ......";}
else if (size == "08") {cSize = " (Add-ons) .......";}
return cSize;
}
}
```
...ANSWER
Answered 2021-Jun-06 at 04:14It appears to me that one of your problems is due to you using reference comparison(==
) instead of value comparison(.equals
).
Another one is that your regex strings are doing the opposite of what you want.
Swap the regex strings and change the ==
to .equals()
and the functions should work right.
QUESTION
I have a MongoDB collection that looks like this:
...ANSWER
Answered 2021-May-27 at 15:27$unwind
deconstructcontent
array$group
byairline
andcontent
and get the total count$group
by the onlyairline
and constructcounts
array key-value format$arrayToObject
convert key-value array to object
QUESTION
I'm sorry about the title, I really didn't know how to phrase it, but hopefully this example will make it clear.
Basically,
For the following sentence:
Ashley and Brian are drinking water.
I want the noun chunk to be "Ashley and Brian" instead it is, "Ashley", "Brian"
Another example is:
Types of clothes include shirts, pants and trousers.
I want the noun chunk to be "shirts, pants and trousers" instead of "shirts" "pants" "trousers"
How do I solve this problem?
...ANSWER
Answered 2021-May-27 at 05:21Assuming that it returns a list. You can use the join method on the string to combine the nouns.
QUESTION
So I have an array of objects called products:
...ANSWER
Answered 2021-May-26 at 14:30const updatedProducts = products.map(product => ({ ...product, coupons: [] }))
QUESTION
const [state, setState] = useState("");
setState(e.target.value)}
...ANSWER
Answered 2021-May-20 at 15:02I would create a state for each input, set the value of the respective input to this state, set the state for each input onChange, and finally, in the onClick of the button just combine the three states.
Example input:
QUESTION
How to increment the array value inside the object.
I tried the code below but It's removing the garments array and replacing it with shirts: Nan
value
ANSWER
Answered 2021-May-08 at 07:47You are spreading an undefined value state.garments
that should actually be state.bookings.garments
, so garments
array isn't copied to the new state. Similarly, state.shirts
is undefined and any mathematical operation with it results in a NaN
value.
You should shallow copy all nested state object properties.
For the given state:
QUESTION
This is my CSV sample:
...ANSWER
Answered 2021-May-06 at 04:23Since you are setting keep=False
all duplicates are being dropped on the df.drop_duplicates
method, you need to set keep="first" or "last" in order to keep those duplicate entries.
QUESTION
I’m working on a regex extract where the line item may or may not have a space at the beginning of the string I’m looking to extract.
For example, I’m looking at the line items
...ANSWER
Answered 2021-Mar-29 at 02:56You may use REGEXP_EXTRACT
with a capture group:
QUESTION
I try to split and output the csv file. I must use the date to be the file name but don't need the time.
So I want to split the Order_Date, which is a timestamp that has both date and time.
How can I group by a part of value in pandas?
There is my code:
ANSWER
Answered 2021-Apr-29 at 03:08You need to convert Order_Date
to dates - stripping the time information. One quick way to do this is:
df['Order_Date1'] = pd.to_datetime(df['Order_Date']).dt.strftime('%Y-%m-%d')
Then proceed with a groupby using Order_Date1
.
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