Collect | archive websites , also supports video downloads | Continuous Backup library
kandi X-RAY | Collect Summary
kandi X-RAY | Collect Summary
Collect is a server to collect & archive websites written for NodeJS. It is intended for anyone who wants to archive individual websites or videos. Collect stores a static copy of the url on your disk.
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QUESTION
I'm trying to initiate a Springboot project using Open Jdk 15, Springboot 2.6.0, Springfox 3. We are working on a project that replaced Netty as the webserver and used Jetty instead because we do not need a non-blocking environment.
In the code we depend primarily on Reactor API (Flux, Mono), so we can not remove org.springframework.boot:spring-boot-starter-webflux
dependencies.
I replicated the problem that we have in a new project.: https://github.com/jvacaq/spring-fox.
I figured out that these lines in our build.gradle file are the origin of the problem.
...ANSWER
Answered 2022-Feb-08 at 12:36This problem's caused by a bug in Springfox. It's making an assumption about how Spring MVC is set up that doesn't always hold true. Specifically, it's assuming that MVC's path matching will use the Ant-based path matcher and not the PathPattern-based matcher. PathPattern-based matching has been an option for some time now and is the default as of Spring Boot 2.6.
As described in Spring Boot 2.6's release notes, you can restore the configuration that Springfox assumes will be used by setting spring.mvc.pathmatch.matching-strategy
to ant-path-matcher
in your application.properties
file. Note that this will only work if you are not using Spring Boot's Actuator. The Actuator always uses PathPattern-based parsing, irrespective of the configured matching-strategy
. A change to Springfox will be required if you want to use it with the Actuator in Spring Boot 2.6 and later.
QUESTION
I am trying to connect to Postgress and create a folder test.db via Flask. When I run "python3" in the terminal and from there when I run "from app import db" I get an import error:
...ANSWER
Answered 2021-Oct-11 at 10:45Use older version of python (eg 3.8)
QUESTION
In the current stable Rust, is there a way to write a function equivalent to BTreeMap::pop_last?
The best I could come up with is:
...ANSWER
Answered 2022-Mar-15 at 16:55Is there a way to work around this issue without imposing additional constraints on map key and value types?
It doesn't appear doable in safe Rust, at least not with reasonable algorithmic complexity. (See Aiden4's answer for a solution that does it by re-building the whole map.)
But if you're allowed to use unsafe, and if you're determined enough that you want to delve into it, this code could do it:
QUESTION
Springfox 3.0.0 is not working with Spring Boot 2.6.0, after upgrading I am getting the following error
...ANSWER
Answered 2021-Dec-01 at 02:17I know this does not solve your problem directly, but consider moving to springdoc which most recent release supports Spring Boot 2.6.0. Springfox is so buggy at this point that is a pain to use. I've moved to springdoc
2 years ago because of its Spring WebFlux support and I am very happy about it. Additionally, it also supports Kotlin Coroutines, which I am not sure Springfox does.
If you decide to migrate, springdoc
even has a migration guide.
QUESTION
I need help to make the snippet below. I need to merge two files and performs computation on matched lines
I have oldFile.txt which contains old data and newFile.txt with an updated sets of data.
I need to to update the oldFile.txt based on the data in the newFile.txt and compute the changes in percentage. Any idea will be very helpful. Thanks in advance
...ANSWER
Answered 2021-Dec-10 at 13:31Here is a sample code to output what you need.
I use the formula below to calculate pct change.
percentage_change = 100*(new-old)/old
If old is 0 it is changed to 1 to avoid division by zero error.
QUESTION
When running this simple program, different behaviour is observed depending on the compiler.
It prints true
when compiled by GCC 11.2, and false
when compiled by MSVC 19.29.30137 with the (both are the latest release as of today).
ANSWER
Answered 2021-Dec-08 at 16:06GCC and Clang report that S
is trivially copyable in C++11 through C++23 standard modes. MSVC reports that S
is not trivially copyable in C++14 through C++20 standard modes.
N3337 (~ C++11) and N4140 (~ C++14) say:
A trivially copyable class is a class that:
- has no non-trivial copy constructors,
- has no non-trivial move constructors,
- has no non-trivial copy assignment operators,
- has no non-trivial move assignment operators, and
- has a trivial destructor.
By this definition, S
is trivially copyable.
N4659 (~ C++17) says:
A trivially copyable class is a class:
- where each copy constructor, move constructor, copy assignment operator, and move assignment operator is either deleted or trivial,
- that has at least one non-deleted copy constructor, move constructor, copy assignment operator, or move assignment operator, and
- that has a trivial, non-deleted destructor
By this definition, S
is not trivially copyable.
N4860 (~ C++20) says:
A trivially copyable class is a class:
- that has at least one eligible copy constructor, move constructor, copy assignment operator, or move assignment operator,
- where each eligible copy constructor, move constructor, copy assignment operator, and move assignment operator is trivial, and
- that has a trivial, non-deleted destructor.
By this definition, S
is not trivially copyable.
Thus, as published, S
was trivally copyable in C++11 and C++14, but not in C++17 and C++20.
The change was adopted from DR 1734 in February 2016. Implementors generally treat DRs as though they apply to all prior language standards by convention. Thus, by the published standard for C++11 and C++14, S
was trivially copyable, and by convention, newer compiler versions might choose to treat S
as not trivially copyable in C++11 and C++14 modes. Thus, all compilers could be said to be correct for C++11 and C++14.
For C++17 and beyond, S
is unambiguously not trivially copyable so GCC and Clang are incorrect. This is GCC bug #96288 and LLVM bug #39050
QUESTION
I am trying to find a more efficient solution to a combinatorics problem than the solution I have already found.
Suppose I have a set of N objects (indexed 0..N-1) and wish to consider each subset of size K (0<=K<=N). There are S=C(N,K) (i.e., "N choose K") such subsets. I wish to map (or "encode") each such subset to a unique integer in the range 0..S-1.
Using N=7 (i.e., indexes are 0..6) and K=4 (S=35) as an example, the following mapping is the goal:
0 1 2 3 --> 0
0 1 2 4 --> 1
...
2 4 5 6 --> 33
3 4 5 6 --> 34
N and K were chosen small for the purposes of illustration. However, in my actual application, C(N,K) is far too large to obtain these mappings from a lookup table. They must be computed on-the-fly.
In the code that follows, combinations_table
is a pre-computed two-dimensional array for fast lookup of C(N,K) values.
All code given is compliant with the C++14 standard.
If the objects in a subset are ordered by increasing order of their indexes, the following code will compute that subset's encoding:
...ANSWER
Answered 2021-Oct-21 at 02:18Take a look at the recursive formula for combinations:
Suppose you have a combination space C(n,k)
. You can divide that space into two subspaces:
C(n-1,k-1)
all combinations, where the first element of the original set (of lengthn
) is presentC(n-1, k)
where first element is not preset
If you have an index X that corresponds to a combination from C(n,k)
, you can identify whether the first element of your original set belongs to the subset (which corresponds to X
), if you check whether X
belongs to either subspace:
X < C(n-1, k-1)
: belongsX >= C(n-1, k-1)
: doesn't belong
Then you can recursively apply the same approach for C(n-1, ...)
and so on, until you've found the answer for all n
elements of the original set.
Python code to illustrate this approach:
QUESTION
I installed anaconda and spyder came with the installation. Spyder 4.2.5 came with the installation and I got a pop up notification that spyder=5.1.5 is available. I tried
conda update anaconda
conda install spyder=5.1.5
and gets an error:
Solving environment: failed with initial frozen solve. Retrying with flexible solve.
I tried letting it run for more than 8 hours, but I had to cancel it because I got tired.
Tried
conda install anaconda spyder=5.1.5
and gets another error:
`Solving environment: failed with initial frozen solve. Retrying with flexible solve. Collecting package metadata (repodata.json): done Solving environment: failed with initial frozen solve. Retrying with flexible solve.
PackagesNotFoundError: The following packages are not available from current channels:
- ananconda
Current channels:
- https://repo.anaconda.com/pkgs/main/linux-64
- https://repo.anaconda.com/pkgs/main/noarch
- https://repo.anaconda.com/pkgs/r/linux-64
- https://repo.anaconda.com/pkgs/r/noarch
To search for alternate channels that may provide the conda package you're looking for, navigate to
...ANSWER
Answered 2021-Oct-26 at 06:01(Spyder maintainer here) Our regular instructions to update Spyder don't work in this case because there are some incompatible dependencies between Spyder 5.0.5 and 5.1.5.
To workaround this problem, you need to close Spyder and run the following commands in the Anaconda Prompt (or your system terminal on Linux or macOS):
QUESTION
dict
keeps insertion order since Python 3.6 (see this).
OrderedDict
was developed just for this purpose (before Python 3.6).
Since Python 3.6, is the key order always the same for dict
or OrderedDict
?
I wonder whether I can do this in my code and have always the same behavior (except of equality, and some extended methods in OrderedDict
) but more efficiently:
ANSWER
Answered 2021-Oct-27 at 08:38I realize that the different behavior of equality (__eq__
) can be actually a major concern, why such code snippet is probably not good.
However, you could maybe still do this:
QUESTION
I was checking the code of the toolz library's groupby
function in Python and I found this:
ANSWER
Answered 2021-Sep-22 at 13:05This is a somewhat confusing trick to save a small amount of time:
We are creating a defaultdict
with a factory function that returns a bound append
method of a new list instance with [].append
. Then we can just do d[key(item)](item)
instead of d[key(item)].append(item)
like we would have if we create a defaultdict
that contains lists. If we don't lookup append
everytime, we gain a small amount of time.
But now the dict
contains bound methods instead of the lists, so we have to get the original list instance back via __self__
.
__self__
is an attribute described for instance methods that returns the original instance. You can verify that with this for example:
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