DevIL | Image Library is a cross-platform image library | Computer Vision library
kandi X-RAY | DevIL Summary
kandi X-RAY | DevIL Summary
Developer’s Image Library (DevIL) is a cross-platform image library utilizing a simple syntax to load, save, convert, manipulate, filter, and display a variety of images with ease. It is highly portable and has been ported to several platforms.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of DevIL
DevIL Key Features
DevIL Examples and Code Snippets
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for label in ax.get_xticklabels() + ax.get_yticklabels():
label.set_fontsize(16)
label.set_bbox(dict(facecolor='white', edgecolor='None', alpha=0.65 ))
...
Community Discussions
Trending Discussions on DevIL
QUESTION
I'm utlizing Pandas to groupby two indexes. After performing groupby calculation, Id liek to create a two new columns that refer to the previous row.
See code below
...ANSWER
Answered 2021-Jun-14 at 02:16Try:
QUESTION
When i rewriting my old code, i had a problem i don't know to to optimize this code in past i use switch,but now i know about Object literals, my code:
...ANSWER
Answered 2021-Jun-13 at 13:28You can write the cases as object literals and iterate over them:
QUESTION
I am using lxml and beautifulsoup library, actually my goal is to translate text of the specific tags out of the whole html code, what I want is, I want to replace the text of specific tags with the translated text.
I want to set a loop for the specific xpath in which all the translated text should be inserted one after another. And the html code should be returned with the translated version.
...ANSWER
Answered 2021-Jun-01 at 15:37do you need to replace? Can't you simply just set the string/contnet to the translation?
Also, you are sort of doing some unnecessary loops here. And you would need to fix your indentation as what you want is the for i,z
to be 2 levels up.
try this:
QUESTION
I have a unit test class where my unit under test is dependent on another class. The dependency is mocked using Mockito and then setup with a generic stub that's run before every unit test, using JUnit's @BeforeEach
annotation. See the below pseudo-code.
ANSWER
Answered 2021-May-21 at 20:27You can avoid this check at the test-level by resetting the mock with the stub that's not being called. This is a bit of a work around, but it'll allow you to pass your test without having to make the mock lenient for your entire test class or removing the mock entirely from your setup method.
To reset your barDependency
mock, add the following line of code to the end of your test that is failing with a UnnecessaryStubbingException
.
QUESTION
I have multiple dilogue boxes for different different conditions. when I a dilogue is displayed for one condition and then I try to display another one for another condition. It overlaps the previous one.
Specific Scenario
I have two dialogues. One for when wifi is not active. Another one is when wifi is active. Suppose When I launched an app wifi was not active. So, it displayed a dilogue. Then I turned on wifi. It displayed another dilogue. But, It overlapped previous one. In below screenshot it is clearly visible by looking at the shadow of dilogue box. Left one is when wifi is on. And then I turned off the wifi and turned on again. And this overlapping happened.
Java code
...ANSWER
Answered 2021-Apr-29 at 08:07Just call cancel
before reassigning alertDialog
:
QUESTION
following are my files for html, .ts and json . As json data was very extensive therefore i have just added a few states and their cities. my 1st dropdown is showing all states. Now I want to match my 1st dropdown's selected value of state with a key "state" in "cities" object in my json file so i can populate 2nd dropdown with cities relevant to that state. and I want to do this in function "getCitiesForSelectedState". please help me find solution for this.
//.ts file
...ANSWER
Answered 2021-Apr-27 at 16:44You can do it with the $event
parameter.
Make sure to compare your values safely.
If your value is not in the right type or has spaces or unwanted chars, this c.state == val
might not work.
You can use the trim
function to compare your value safely:
c.state.trim() == val.trim()
HTML
QUESTION
I got a project where I have to print the complex nested JSON files "Keys" only instead of its values. The number of files is multiple and each file has more than 300 lines which are hard to be completed manually. Normally when I am printing JSON data, so I am doing complete mapping like the below example:
...ANSWER
Answered 2021-Apr-24 at 13:04There is a native js
function for this, Object.keys()
,
You can find more info at MDN docs
This method will return only the keys
of the objects you have, any custom functionality
you need can be added by using this function
QUESTION
So I have set up a product display area on my upcoming website, and I am attempting to have it so when you click on one of the smaller images, it changes the large image.
I have a specific layout of the HTML that I am going to require, so it is more now down to the jQuery.
...ANSWER
Answered 2021-Apr-23 at 03:44You are almost there. You are not calling the right selector.
change 'main-img'
to '.main-img'
.
You can also call a data attribute value using this:
$('.element').data('foo')
or $('.element').attr('data-foo')
the first one being preferred.
QUESTION
I have this movie ticket program, which I want to have a class so it becomes a main method and a class and it's aching my mind .
...ANSWER
Answered 2021-Apr-06 at 06:11You need to create separate classes for Theatre, Movie, Ticket etc.
Something like below.
QUESTION
This is a bit of a puzzler, and I wanted to get an ideal algorithm for this type of question. The problem is focused on kangaroo words, which are words that have all the same letters in order as the main word. It's easiest to provide an example. If we take the word (which seems to be floating about online for this type of question) - courage.
courage
courage -> core
courage -> cog
Here is working code to detect the lines above:
...ANSWER
Answered 2021-Mar-31 at 05:21Here's a regex-based approach to the problem. We form a regex from lookup_word
by adding .*
between each letter in the word. Then we attempt to match the regex against word
. Since .*
is inherently greedy, you will get the longest possible match inside word. You can then compare the length of the matched string to the length of lookup_word
, and if the matched string is longer, then lookup_word
is a kangaroo word:
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