elisa | Simple music player aiming to provide a nice experience | Music Player library

Ok, you want to sort your array of dictionaries by the Date value in the scheduleddate key.

If scheduleddate sometimes contains multiple dates, it would be simpler if you could assume the correct date is the last one. Failing that, do this:

write a function dateTodayFromString(_:) that takes a String and returns a Date.

Have it use the NSString method containsString to determine if it contains a comma. If it doesn't, just apply the date formatter and return the resulting Date.

If it does, use componentsSeparatedByString: ", " to break the multiple dates apart. Convert each one into a Date using your DateFormatter, loop through the array of Dates and use the Calendar function isDateInToday to find a date that is in the current day. If it finds one, return that.

Rewrite your sort function to call your dateTodayFromString(_:) function to get a date from the string in each array entry.

Note that if your array contains more than ≈100 entries you should really convert the array to an array of mutable dictionaries and go through a pass converting all those date strings to Date objects before you try to sort it. converting date strings to dates for every comparison makes the sorting process a lot slower (I seem to remember that it took like 12 times longer on a modest sized array when I tested it, but I'd have to go back and test it.)

You can do this with the "one or more" or the "zero or more" matchers:

Groceries is in the arules package.

grepl works only for vectors. Use apply:

First, you need one loop only. This loop will go on for however long you need. Not very clear from your question how many times each name needs to appear. Let's assume the total length is 12*16 (months length times names length)

Loop over all names with index 'i' going from 0 to 12*16. When you print out the relevant month and name, use:

When you iterate over your list by for item in transactions_clean: you get items for each list, so indexing them like item[1] would just give you string characters. If the order is always like customer -> sale -> thread_sold, you can do something like this:

Wrapping the c around a data.frame with single column doesn't create a vector. It is a list with a single element i.e.

I just saw your last update and there are some good ideas in it. Here is one version of the program, which does not completely correspond to your assignment as the main execution is not within a loop but in a if __name__ == '__main__': statement which will execute only when the program is called directly, and not when it is imported or when function part of this program are imported. I highly encourage you to try a small part of the code, one at a time, and then to adapt it to your specific need.

Let's go piece by piece:

First of all this line: