polygon-intersection | Simple algo to find convex polygon intersection | Computer Vision library

 by   abreheret C++ Version: Current License: MIT

kandi X-RAY | polygon-intersection Summary

kandi X-RAY | polygon-intersection Summary

polygon-intersection is a C++ library typically used in Artificial Intelligence, Computer Vision, OpenCV, Example Codes applications. polygon-intersection has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Simple algo to find convex polygon intersection and compute area of polygone with using OpenCV
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              polygon-intersection has a low active ecosystem.
              It has 43 star(s) with 13 fork(s). There are 2 watchers for this library.
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              It had no major release in the last 6 months.
              polygon-intersection has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of polygon-intersection is current.

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              polygon-intersection has no bugs reported.

            kandi-Security Security

              polygon-intersection has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              polygon-intersection is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

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              polygon-intersection releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            polygon-intersection Examples and Code Snippets

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            Community Discussions

            QUESTION

            Calculating polygon intersecting area with gArea and gIntersection error in R
            Asked 2020-Dec-30 at 23:50

            I have two polygons

            ...

            ANSWER

            Answered 2020-Dec-30 at 23:50

            Not sure what percentage you're after, but all of the areas are listed below for you to do the math on.

            The following solution uses the sf library to work with the spatial objects.

            If you're working with sp objects (SpatialPolygonsDataframes, etc), they can usually be changed to sf using as(x, 'sf').

            Source https://stackoverflow.com/questions/65514511

            QUESTION

            Efficient extraction of all sub-polygons generated by self-intersecting features in a MultiPolygon
            Asked 2017-Dec-21 at 08:54

            Starting from a shapefile containing a fairly large number (about 20000) of potentially partially-overlapping polygons, I'd need to extract all the sub-polygons originated by intersecting their different "boundaries".

            In practice, starting from some mock-up data:

            ...

            ANSWER

            Answered 2017-Jun-21 at 14:45

            Not sure if it helps you since it is not in R but I think there is a good way to solve this problem using Python. There is a library called GeoPandas (http://geopandas.org/index.html) which has allows you to easily do geo operations. In steps what you would need to do is the following:

            1. Load all Polygons into geopandas GeoDataFrames
            2. Loop all GeoDataFrames running a union overlay operation (http://geopandas.org/set_operations.html)

            The exact example is shown in the documentation.

            Before operation - 2 Polygons

            After operation - 9 Polygons

            If there is anything unclear feel free to let me know! Hope it helps!

            Source https://stackoverflow.com/questions/44631044

            QUESTION

            Find closest line to each point on big dataset, possibly using shapely and rtree
            Asked 2017-Sep-21 at 14:21

            I have a simplified map of a city that has streets in it as linestrings and addresses as points. I need to find closest path from each point to any street line. I have a working script that does this, but it runs in polynomial time as it has nested for loop. For 150 000 lines (shapely LineString) and 10 000 points (shapely Point), it takes 10 hours to finish on 8 GB Ram computer.

            The function looks like this (sorry for not making it entirely reproducible):

            ...

            ANSWER

            Answered 2017-Sep-21 at 11:50

            Here you have a solution using rtree library. The idea is to build boxes that contain the segments in the diagonal, and use that boxes to build the rtree. This will be the most time-expensive operation. Later, you query the rtree with a box centered in the point. You get several hits that you need to check for the minimum, but the number of hits will be (hopefuly) orders of magnitud lower than checking against all the segments.

            In the solutions dict you will get, for each point, the line id, the nearest segment, the nearest point (a point of the segment), and the distance to the point.

            There are some comments in the code to help you. Take into account you can serialize the rtree for later use. In fact, I would recomend to build the rtree, save it, and then use it. Because the exceptions for the adjustments of the constants MIN_SIZE and INFTY will probably raise, and you would not want to lose all the computation you did building the rtree.

            A too small MIN_SIZE will mean you could have errors in the solutions because if the box around the point does not intersect a segment, it could intersect a box of a segment that is not the nearest segment (it is easy to think a case).

            A too big MIN_SIZE would mean to have too much false positives, that in the extreme case would make the code to try with all the segments, and you will be in the same position as before, or worst, because you are now building an rtree you don't really use.

            If the data is real data from a city, I imagine you know that any address will be intersecting a segment with a distance smaller than a few blocks. That will make the search practically logaritmic.

            One more comment. I'm assuming that there are not segments that are too large. Since we are using the segments as the diagonals of the boxes in the rtree, if you have some large segments in a line, this would mean a huge box will be assigned to that segment, and all addresses boxes would intersect it. To avoid this, you can always increase artificially the resolution of the LineStrins by adding more intermediate points.

            Source https://stackoverflow.com/questions/46170577

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            You can download it from GitHub.

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