zurl | HTTP and WebSocket client worker with ZeroMQ interface | Websocket library

by fanout C++ Version: v1.11.0 License: GPL-3.0

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | zurl Summary

zurl is a C++ library typically used in Networking, Websocket applications. zurl has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Zurl is an HTTP and WebSocket client daemon with a ZeroMQ interface. Send it a message to make an HTTP request.

Support

Quality

Security

License

Reuse

Support

zurl has a low active ecosystem.

It has 376 star(s) with 29 fork(s). There are 28 watchers for this library.

It had no major release in the last 12 months.

There are 3 open issues and 13 have been closed. On average issues are closed in 43 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of zurl is v1.11.0

Quality

zurl has 0 bugs and 0 code smells.

Security

zurl has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

zurl code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

zurl is licensed under the GPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

zurl releases are available to install and integrate.

Installation instructions, examples and code snippets are available.

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zurl Key Features

No Key Features are available at this moment for zurl.

zurl Examples and Code Snippets

No Code Snippets are available at this moment for zurl.

Community Discussions

Trending Discussions on zurl

Python Webscrape with Beautiful Soup

QUESTION

Python Webscrape with Beautiful Soup

Asked 2020-Nov-25 at 00:01

I am new to python and working on a webscraper. My issues is that my list is only populating the first link in each category. Length on output is 9, but should be 25. I am pretty sure my error has something to do with my l=[] and d={}, but not sure.

Any help would be appreciated.

...

ANSWER

Answered 2020-Nov-25 at 00:01

You just put the l.append(d) out of the for loop. So you only appending the last d in each a you query. Move it to the end of the loop and it will work fine:

Source https://stackoverflow.com/questions/64996485

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install zurl

If accessing from Git, be sure to pull submodules:.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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