shotcut | cross-platform , open-source video editor | Editor library
kandi X-RAY | shotcut Summary
kandi X-RAY | shotcut Summary
cross-platform (Qt), open-source (GPLv3) video editor
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QUESTION
I've got an asp.net Application that uses an manifest.json to be "installed" localy on android devices.
In this manifest I've added: "display":"standalone and "orientation": "landscape"
But it is still rotating 180° if I flip the phone upside down, even if "Screen rotation" is turned off on all these decises. The Problem is, that Those devices have a scanner on top that is used to scann barcodes. So if you flip the phone upside down to scan something the whole webpage turns around and you can't read it anymore when you flip it back up. you eighter have to hold is straight up again, or "shake" it a bit to get it flipping back again.
Edit 20211110: It's a Website, that is running on our local IIS. The Web-page uses a MANIFEST.JSON so that chrome, Firefox and safari promt the user to "install" the Website. This creates a Shortcut on the Main Launcher that opens the website like an Android App. (It's like Twitter, when you brose their website on your andorid Phone it promts you to install the app, but in reality it only creates a shotcut to the website)
...ANSWER
Answered 2021-Nov-10 at 09:56Okay, I figured it out now.
The option "orientation": "portrait"
caused the PWA to be ALWAYS in Portrait, even if the Device is held upside down.
So I just had to remove this option from the manifest.json and now it works.
QUESTION
I have a video file in MP4 format which supposedly has a 720×576 resolution yet is 786 × 576 according to the Finder on Mac:
As part of this discussion here it's been pointed out to me that this may be because the file is PAL standard video, according to which this is the expected behaviour. I'd like to change this using ffmpeg so that the file actually is no longer PAL standard video but always only 720 pixels in width.
To do so, I've been pointed to this question to find the corresponding ffmpeg command. Yet when I try to run ffmpeg -i weird_video.mp4 -vf "scale=iw*sar:ih,setsar=1" -crf 28 -c:a aac -b:a 80k -ac 1 -movflags +faststart h-264-out.mp4
, I get an error message as the actual width of the video seems to be 785 and not 786 pixels as indicated by finder:
ANSWER
Answered 2021-Oct-12 at 22:03To convert non-square pixels to square pixels and crop to desired width:
QUESTION
I've been using Logwatch for at least 12 years, but since I've moved to Ubuntu 18.04 I've gotten soooo annoyed about the daily e-mail is listing 37 /snap in the filesystem check:
...ANSWER
Answered 2021-Jan-24 at 20:16I looked in /usr/share/logwatch/scripts/services/zz-disk_space, where the df command is:
QUESTION
I am working on a drawing application. I summerize the main question to a tiny scenario:
User draws the line A1-B1 and also the point M1. Now user moves the line A1-B1 to a new position A2-B2 while the point M1 also should move with the line (like a rigid body). How can I calculate the new position of point M2?
I know it is possbile with complex calucations on lines or circles conjuction and finally detemrining if the new point is on the right or left of line (this question) etc. But as I want to recalculate live on any steps of dragging, I guess there should be a shortcut and light solution which all modeling softwares use. Is there really a shortcut formula rahter than the line or circle conjuctions?
To summerize the problem again I am looking for a light function with given A1,B1,A2,B2,M1 and looking for M2 position (two separate formula for x and y)
M2 = f(A1,B1,A2,B2,M1)
My guess: I think finding the center and the angle of rotation is one of the best options but I don't know again if there is a shotcut function to find them.
Edit: I prefer to implement it in an online website, so if there is a ready javascript library, it would be helpful, However I am now just looking for the mathematical logic.
...ANSWER
Answered 2021-Jan-21 at 17:48Start with A1 and B1.
D = B1 - A1
C1 = D/|D|
Rotate C1 90 degrees counter-clockwise to get C'1:
C1 = (cx, cy)
C'1 = (-cy, cx)
Now take M1 - A1 and measure it against C1 and C'1:
j = (M1 - A) · C1
k = (M1 - A) · C'1
Now it's easy to prove:
M1 = A1 + j C1 + k C'1
So j and k tell you where M1 is, given A1 and B1.
When you get A2 and B2, use them to construct C2, rotate it to get C'2, and then you'll have:
M2 = A2 + j C2 + k C'2
QUESTION
My goal: Set up a simple class to add some keyboard macros to Maya at startup.
My Issue: The intended key mappings are not set in the hotkey editor. Editing them manually does work, but as these are default commands, they need to be set programmatically.
-thanks
...ANSWER
Answered 2020-Jan-29 at 19:09Here is A fully working example. Perhaps it can help someone in the future.
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